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For the following exercises, graph the inequality. $$x^{2}+y^{2}<4$$

Short Answer

Expert verified
Graph a dashed circle with radius 2 and shade the interior.

Step by step solution

01

Identify the General Form of the Inequality

The given inequality is \(x^2 + y^2 < 4\). This resembles the inequality for a circle \(x^2 + y^2 < r^2\), where \(r\) is the radius of the circle. In our case, \(r^2 = 4\), so \(r = 2\). This tells us that the boundary of the region is a circle centered at the origin \((0,0)\) with a radius of 2.
02

Draw the Boundary Circle

Plot a circle with the center at \((0,0)\) and a radius of 2 on a graph. Since the inequality is "less than" and not "less than or equal to", the boundary of the circle will be dashed, indicating that points on the circle are not included in the solution set.
03

Identify the Solution Region

Since the inequality is \(x^2 + y^2 < 4\), the solution is the area inside the circle but not including the boundary. Any point \((x, y)\) that falls inside this circle will satisfy the inequality.
04

Shade the Region Inside the Circle

Shade the entire interior of the dashed circle on your graph. This shaded area represents all points that satisfy \(x^2 + y^2 < 4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circle Inequalities
Circle inequalities help us to graph regions defined by a circle in the coordinate plane. An inequality like \(x^2 + y^2 < 4\) represents all the points \((x, y)\) within a circle, centered at the origin \((0,0)\) with a radius. In this case, the radius \( r \) is found by taking the square root of the number on the right side of the inequality. Here, \( r = \sqrt{4} = 2\).

Unlike equations, inequalities focus not only on the boundary but on what lies inside or outside that boundary. The 'less than' symbol \(<\) denotes the set of points strictly inside the circle. A solid understanding of how these symbols affect graphing is crucial.

When the inequality is \(<\), the circle's edge isn't included, while \(\leq \) includes it. This simple difference significantly impacts the graphing of such inequalities.
Solution Region
The solution region for a given circle inequality corresponds to all the points that satisfy the inequality condition. In our example with \(x^2 + y^2 < 4\), the solution region is the area lying strictly inside the circle of radius 2, excluding the boundary itself.

To identify the solution region, it is necessary to translate the inequality's conditions into a visual form on a graph. Here are the key steps:
  • Start by plotting the circle's boundary.
  • Consider the inequality symbol. Since here it's \(<\), pick any test point inside the circle, like \((0,0)\). If this point satisfies the inequality, it confirms that the entire area inside the circle forms part of our solution region.
The solution region is a continuous area, making it essential to appropriately shade or highlight it for clarity.
Inequality Graph
The graph of an inequality involves more than simply plotting points or lines; it requires showing regions where the inequality holds true. When graphing \(x^2 + y^2 < 4\), it's essential to graph the outline and the solution region.

Here's how to effectively graph an inequality like this:
  • Start by plotting the boundary circle with the correct center and radius.
  • Since our inequality uses \(<\), depict this fact with a dashed line for the boundary, indicating the edge isn't part of the solution.
  • Shade the region inside the circle to represent all points satisfying \(x^2 + y^2 < 4\).
Through this approach, the graph becomes a powerful tool for visualizing solutions, clearly displaying areas that meet the inequality's condition.
Boundary Circle
The boundary circle is crucial in graphing inequalities, forming the border of the area you're considering. It stems from the circle equation with equality \(x^2 + y^2 = 4\), which becomes a guideline when graphed.

Understanding the role of the boundary circle includes:
  • Plotting the boundary accurately: For \(x^2 + y^2 < 4\), this involves a circle centered at \( (0,0) \) with radius 2.
  • Using a dashed line for inequalities not including the boundary, which visually differentiates from solid lines showing inclusive boundaries.
  • Recognizing that the boundary itself doesn't satisfy the inequality \(<\).
The boundary circle visually frames the solution area, assisting in understanding and solving inequalities effectively.

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