Chapter 7: Problem 37
For the following exercises, solve the system of linear equations using Cramer's Rule. $$ \begin{aligned} 4 x+5 y-z &=-7 \\ -2 x-9 y+2 z &=8 \\ 5 y+7 z &=21 \end{aligned} $$
Short Answer
Expert verified
The solution is \( x = \frac{96}{31}, y = -\frac{210}{31}, z = \frac{332}{31} \).
Step by step solution
01
Write the system in matrix form
The given system of equations can be expressed in matrix form as \( AX = B \), where:- \( A \) is the coefficient matrix:\[A = \begin{bmatrix} 4 & 5 & -1 \ -2 & -9 & 2 \ 0 & 5 & 7 \end{bmatrix}\]- \( X \) is the column matrix of variables:\[ X = \begin{bmatrix} x \ y \ z \end{bmatrix} \]- \( B \) is the column matrix of constants:\[ B = \begin{bmatrix} -7 \ 8 \ 21 \end{bmatrix} \]
02
Compute the determinant of matrix A
Using the formula for a 3x3 determinant, calculate \( \det(A) \).\[\det(A) = \begin{vmatrix} 4 & 5 & -1 \ -2 & -9 & 2 \ 0 & 5 & 7 \end{vmatrix}\]Expanding along the third column:\[\det(A) = (-1) \left( (-2)(7) - (-9)(5) \right) - (5) \left( (-2)(0) - (-9)(0) \right) + (4) \left( 5(2) - (-9)(0) \right)\]Simplifying:\[\det(A) = -1(-14 + 45) + 0 + 20 = -31\]
03
Compute determinant of matrix A_x
Replace the first column of \( A \) with \( B \) to find \( A_x \):\[A_x = \begin{bmatrix} -7 & 5 & -1 \ 8 & -9 & 2 \ 21 & 5 & 7 \end{bmatrix}\]Calculate \( \det(A_x) \):\[\det(A_x) = \begin{vmatrix} -7 & 5 & -1 \ 8 & -9 & 2 \ 21 & 5 & 7 \end{vmatrix}\]Expand along the first column:\[\det(A_x) = -7 \left( (-9)(7) - 2(5) \right) - 8 \left( 5(7) - 2(-1) \right) + 21 \left( 5(-9) - (-1)(-9) \right)\]Simplifying:\[\det(A_x) = -7(-63 - 10) - 8(35 + 2) + 21(-45 - 1) = -96\]
04
Compute determinant of matrix A_y
Replace the second column of \( A \) with \( B \) to find \( A_y \):\[A_y = \begin{bmatrix} 4 & -7 & -1 \ -2 & 8 & 2 \ 0 & 21 & 7 \end{bmatrix}\]Calculate \( \det(A_y) \):\[\det(A_y) = \begin{vmatrix} 4 & -7 & -1 \ -2 & 8 & 2 \ 0 & 21 & 7 \end{vmatrix}\]Expand along the first row:\[\det(A_y) = 4 \left( 8(7) - 2(21) \right) - (-7) \left( (-2)(7) - 2(0) \right) - (-1) \left( (-2)(21) - 8(0) \right)\]Simplifying:\[\det(A_y) = 4(56 - 42) + 7(14) + 42 = 210\]
05
Compute determinant of matrix A_z
Replace the third column of \( A \) with \( B \) to find \( A_z \):\[A_z = \begin{bmatrix} 4 & 5 & -7 \ -2 & -9 & 8 \ 0 & 5 & 21 \end{bmatrix}\]Calculate \( \det(A_z) \):\[\det(A_z) = \begin{vmatrix} 4 & 5 & -7 \ -2 & -9 & 8 \ 0 & 5 & 21 \end{vmatrix}\]Expand along the third column:\[\det(A_z) = -7 \left( (-9)(21) - 8(5) \right) + 8 \left( 5(2) - 5(0) \right) + 21 \left( 5(-2) - 5(0) \right)\]Simplifying:\[\det(A_z) = -7(-189 - 40) + 80 + 21(-10) = -332\]
06
Solve for x, y, and z using Cramer's Rule
Using Cramer's Rule, the solutions for \( x \), \( y \), and \( z \) are given by\[ x = \frac{\det(A_x)}{\det(A)} = \frac{-96}{-31} = \frac{96}{31} \]\[ y = \frac{\det(A_y)}{\det(A)} = \frac{210}{-31} = -\frac{210}{31} \]\[ z = \frac{\det(A_z)}{\det(A)} = \frac{-332}{-31} = \frac{332}{31} \]
07
Conclusion of the solution
The solution to the system of equations using Cramer's Rule is \( x = \frac{96}{31} \), \( y = -\frac{210}{31} \), \( z = \frac{332}{31} \). These are the values of the variables that satisfy all three equations in the system.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
System of Linear Equations
A system of linear equations is a collection of two or more linear equations involving the same set of variables. In our scenario, we have three equations with three variables: \( x \), \( y \), and \( z \). The equations are presented as follows:
In our case, Cramer's Rule is a method used to find the unique solution for a system of linear equations that have as many equations as unknowns, provided the determinant is non-zero.
- 4x + 5y - z = -7
- -2x - 9y + 2z = 8
- 5y + 7z = 21
In our case, Cramer's Rule is a method used to find the unique solution for a system of linear equations that have as many equations as unknowns, provided the determinant is non-zero.
Determinants
Determinants are a special number that can be calculated from a square matrix. They offer a wealth of information about the matrix and the system it represents. For instance, a non-zero determinant of the coefficient matrix signals that the system of linear equations has a unique solution.
In this particular exercise, we calculate determinants to use in Cramer's Rule which requires computing the determinant of the original matrix (\( A \)) and modified matrices (\( A_x \), \( A_y \), \( A_z \)) to find the solutions for the variables \( x \), \( y \), and \( z \). Here is how you can view the role of each determinant:
In this particular exercise, we calculate determinants to use in Cramer's Rule which requires computing the determinant of the original matrix (\( A \)) and modified matrices (\( A_x \), \( A_y \), \( A_z \)) to find the solutions for the variables \( x \), \( y \), and \( z \). Here is how you can view the role of each determinant:
- \( \det(A) \) is the determinant of the coefficient matrix.
- \( \det(A_x) \), \( \det(A_y) \), and \( \det(A_z) \) are determinants of matrices derived from A by replacing columns with the constant matrix. These determine the values of \( x \), \( y \), and \( z \) respectively.
Matrix Form
Expressing a system of linear equations in matrix form is a compact and elegant way to represent and solve complex systems. To use matrix operations, we first rearrange our given equations into a matrix format. For our problem, the matrices have the following form:
- Coefficient matrix (\( A \)) which holds the coefficients of variables.
- Variable matrix (\( X \)) which consists of the variables we need to solve for.
- Constant matrix (\( B \)) which includes the constants from the right side of each equation.