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For the following exercises, find the determinant. \(\left|\begin{array}{rrr}5 & 1 & -1 \\ 2 & 3 & 1 \\ 3 & -6 & -3\end{array}\right|\)

Short Answer

Expert verified
The determinant of the matrix is 15.

Step by step solution

01

Understand the Matrix

We are given a 3x3 matrix and need to find its determinant. The matrix is:\[\begin{bmatrix} 5 & 1 & -1 \ 2 & 3 & 1 \ 3 & -6 & -3 \end{bmatrix}\]
02

Apply the Determinant Formula for 3x3 Matrix

The formula for the determinant of a 3x3 matrix \( A = \begin{bmatrix} a & b & c \ d & e & f \ g & h & i \end{bmatrix} \) is:\[\text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)\]
03

Substitute the Values from Matrix into Formula

Substitute the values from our matrix into the determinant formula:\((a, b, c) = (5, 1, -1)\), \((d, e, f) = (2, 3, 1)\), \((g, h, i) = (3, -6, -3)\).\[\text{det}(A) = 5((3)(-3) - (1)(-6)) - 1((2)(-3) - (1)(3)) - 1((2)(-6) - (3)(3))\]
04

Calculate Intermediate Values

Calculate the intermediate products:- \((3)(-3) - (1)(-6) = -9 + 6 = -3\)- \((2)(-3) - (1)(3) = -6 - 3 = -9\)- \((2)(-6) - (3)(3) = -12 - 9 = -21\)
05

Calculate the Determinant

Substitute the intermediate values back into the equation:\[\text{det}(A) = 5(-3) - 1(-9) - 1(-21) = -15 + 9 + 21 \]Finally, solve the sum:\[\text{det}(A) = 15\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding a 3x3 Matrix
A 3x3 matrix is an essential mathematical concept that comes up frequently in linear algebra. It is a rectangular array of numbers consisting of 3 rows and 3 columns, making a total of 9 elements. Each element in the matrix has a specific position, denoted by their row and column numbers. For example, in the matrix:
\[\begin{bmatrix} 5 & 1 & -1 \2 & 3 & 1 \3 & -6 & -3 \end{bmatrix}\]- The element in the first row, third column is \(-1\).- The element in the second row, second column is \(+3\).
These matrices are often used to solve systems of linear equations, perform transformations, and in various applications across physics and engineering. To solve problems involving matrices, one must understand how to navigate through and manipulate these elements.
Determinant Formula for 3x3 Matrix
To find the determinant of a 3x3 matrix, you must apply a specific formula. This determinant is a scalar value that provides important information about the matrix, such as whether it can be inverted and the scale transformation it represents in space. For a matrix:
\[A = \begin{bmatrix} a & b & c \d & e & f \g & h & i \end{bmatrix}\]The determinant \( \text{det}(A) \) can be calculated using:\[\text{det}(A) = a(ei - fh) - b(di - fg) + c(dh - eg)\]
This formula involves calculating products and differences of the matrix's elements, where:- \( a, b, c, \) are elements of the first row.- \( d, e, f, \) are elements of the second row.- \( g, h, i, \) are elements of the third row.
Understanding this formula is crucial because it lays the foundation for many operations involving matrices, including solving equations and theoretical proofs.
Matrix Multiplication in the Determinant Formula
Matrix multiplication within the determinant formula involves carefully executing operations with elements from the matrix to find specific products. These calculations assess the inter-dependence of elements, impacting multi-dimensional transformations described by the matrix. When applying the determinant formula:
- Calculate products like \((ei - fh)\), \((di - fg)\), and \((dh - eg)\) step-by-step. This allows us to know how different rows and columns of the matrix interact.- Each product involves simple multiplications of two elements, denoted by pairs such as \((e \, \times \, i)\) and \((f \, \times \, h)\).
Being careful and systematic with these calculations ensures accuracy when solving for a matrix determinant. Mistakes often happen with signs (positive or negative) and can significantly affect the result.
Evaluating Intermediate Values
Intermediate values are the building blocks that simplify the calculation of a determinant. By breaking the determinant down into these smaller parts, we achieve greater accuracy and understanding of the process. For instance, consider the calculation for the matrix:
- Calculate \((3 \, \times \, -3) - (1 \, \times \, -6)\), resulting in \(-3\).- Then, solve \((2 \, \times \, -3) - (1 \, \times \, 3)\), leading to \(-9\).- Lastly, \((2 \, \times \, -6) - (3 \, \times \, 3)\) simplifies to \(-21\).
These values are then used in the main determinant equation to achieve the final solution. Simplifying complex calculations into intermediate values provides a clearer path to the end solution while reducing potential calculation errors.

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Most popular questions from this chapter

For the following exercises, create a system of linear equations to describe the behavior. Then, solve the system for all solutions using Cramer’s Rule. A movie theatre sold tickets to three movies. The tickets to the first movie were \(5, the tickets to the second movie were \)11, and the third movie was \(12. 100 tickets were sold to the first movie. The total number of tickets sold was 642, for a total revenue of \)6,774. How many tickets for each movie were sold?

For the following exercises, create a system of linear equations to describe the behavior. Then, solve the system for all solutions using Cramer’s Rule. Three bands performed at a concert venue. The first band charged \(15 per ticket, the second band charged \)45 per ticket, and the final band charged \(22 per ticket. There were 510 tickets sold, for a total of \)12,700. If the first band had 40 more audience members than the second band, how many tickets were sold for each band?

For the following exercises, write a system of equations that represents the situation. Then, solve the system using the inverse of a matrix. A farmer constructed a chicken coop out of chicken wire, wood, and plywood. The chicken wire cost \(\$ 2\) per square foot, the wood \(\$ 10\) per square foot, and the plywood \(\$ 5\) per square foot. The farmer spent a total of \(\$ 51,\) and the total amount of materials used was 14 \(\mathrm{ft}^{2} .\) He used 3 \(\mathrm{ft}^{2}\) more chicken wire than plywood. How much of each material in did the farmer use?

For the following exercises, create a system of linear equations to describe the behavior. Then, solve the system for all solutions using Cramer’s Rule. Your garden produced two types of tomatoes, one green and one red. The red weigh 10 oz, and the green weigh 4 oz. You have 30 tomatoes, and a total weight of 13 lb, 14 oz. How many of each type of tomato do you have?

For the following exercises, solve the system by Gaussian elimination. $$ \begin{aligned} -\frac{1}{2} x-\frac{1}{3} y+\frac{1}{4} z &=-\frac{29}{6} \\ \frac{1}{5} x+\frac{1}{6} y-\frac{1}{7} z &=\frac{431}{210} \\ -\frac{1}{8} x+\frac{1}{9} y+\frac{1}{10} z &=-\frac{49}{45} \end{aligned} $$

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