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For the following exercises, solve each system by Gaussian elimination. $$ \begin{aligned} 2 x+3 y-6 z &=1 \\\\-4 x-6 y+12 z &=-2 \\ x+2 y+5 z &=10 \end{aligned} $$

Short Answer

Expert verified
The system has infinitely many solutions: \(x = 32t - 28\), \(y = 19 - 16t\), \(z = t\), where \(t\) is a real number.

Step by step solution

01

Write the augmented matrix

Convert the given system of equations into an augmented matrix. The system is: \[\begin{align*}2x + 3y - 6z &= 1 \-4x - 6y + 12z &= -2 \x + 2y + 5z &= 10\end{align*}\]The corresponding augmented matrix is:\[\begin{bmatrix} 2 & 3 & -6 & | & 1 \-4 & -6 & 12 & | & -2 \1 & 2 & 5 & | & 10 \end{bmatrix}\]
02

Obtain a leading 1 in the first row, first column

Swap the first and third rows to get a leading 1 in the first row, first column.\[\begin{bmatrix} 1 & 2 & 5 & | & 10 \-4 & -6 & 12 & | & -2 \2 & 3 & -6 & | & 1 \end{bmatrix}\]
03

Eliminate first column entries below the leading 1

Use row operations to make the first column entries below the first row to be zeros. Add 4 times the first row to the second row and subtract 2 times the first row from the third row. The operations are:\( R_2 = R_2 + 4R_1 \)\( R_3 = R_3 - 2R_1 \)After these operations, the matrix becomes:\[\begin{bmatrix}1 & 2 & 5 & | & 10 \0 & 2 & 32 & | & 38 \0 & -1 & -16 & | & -19\end{bmatrix}\]
04

Obtain leading 1 in the second row, second column

To obtain a leading 1 in the second row, second column, divide the entire second row by 2:\[R_2 = \frac{1}{2}R_2\]The new matrix is:\[\begin{bmatrix}1 & 2 & 5 & | & 10 \0 & 1 & 16 & | & 19 \0 & -1 & -16 & | & -19\end{bmatrix}\]
05

Eliminate second column entry below the leading 1

Add row 2 to row 3 to make the entry 0 below the leading 1 in the second row:\[R_3 = R_3 + R_2\]The new matrix becomes:\[\begin{bmatrix}1 & 2 & 5 & | & 10 \0 & 1 & 16 & | & 19 \0 & 0 & 0 & | & 0\end{bmatrix}\]
06

Back substitution

The last row corresponds to the equation \(0=0\) which is always true, indicating that the system has infinitely many solutions. We express the solution in terms of a free variable, \(z = t\). From row 2: \[ y + 16z = 19 \implies y = 19 - 16t \]From row 1: \[ x + 2y + 5z = 10 \implies x = 10 - 2(19 - 16t) - 5t = 10 - 38 + 32t - 5t = 32t - 28 \]Thus, the solutions are: \[\begin{align*}x &= 32t - 28, \y &= 19 - 16t, \z &= t\end{align*}\]
07

Solution statement

Since the system has infinitely many solutions, the solution set can be written in terms of the parameter \(t\). The solutions are \(x = 32t - 28 \), \(y = 19 - 16t \), and \(z = t\), where \(t\) is any real number.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Augmented Matrix
An augmented matrix is a very useful tool when working with systems of equations. It’s like taking all the crucial information from a set of equations and organizing it in a neat rectangular box. This matrix includes both the coefficients of the variables and the constants on the other side of the equations. Here’s how it works:
- Imagine you have a system of equations. Each equation will contribute one row to the augmented matrix.
- The coefficients of the variables form the columns of the matrix, and the constants form an additional column often separated by a vertical line (|) to indicate the equal part from each original equation.

For example, consider the system:\[\begin{aligned} 2x + 3y - 6z &= 1 \-4x - 6y + 12z &= -2 \x + 2y + 5z &= 10\end{aligned}\]This will result in the augmented matrix:\[\begin{bmatrix} 2 & 3 & -6 & | & 1 \-4 & -6 & 12 & | & -2 \1 & 2 & 5 & | & 10 \end{bmatrix}\]By converting the equations into this format, it becomes easier to apply Gaussian elimination techniques.
System of Equations
A system of equations is simply a collection of two or more equations that share the same variables. The goal is to find the values of these variables that satisfy all the equations simultaneously. Systems of equations can be seen frequently in mathematical problems, especially when working with linear equations.

When you're dealing with a system of equations, you might have:- Unique solutions (one solution set for the variables that fits all equations)
- No solutions (no common solutions exist)
- Infinitely many solutions (many solutions fulfill the equations simultaneously)

For instance, in our example, the system:\[\begin{aligned} 2x + 3y - 6z &= 1 \-4x - 6y + 12z &= -2 \x + 2y + 5z &= 10\end{aligned}\]has infinitely many solutions. This was determined through Gaussian elimination, which simplified the system to make it clear that one variable could vary freely, and the others would depend on it.
Row Operations
Row operations are a fundamental part of Gaussian elimination. They allow us to systematically and efficiently solve systems of equations by transforming the augmented matrix until it's in a more easily interpretable form. There are three basic types of row operations you can use:

- **Swapping rows:** This means exchanging places between two rows. It’s used when you want to rearrange the matrix for easier manipulation.
- **Multiplying a row by a non-zero constant:** This helps in normalizing a row, commonly used to turn a coefficient into 1, as seen in our example when dividing a row to get a leading 1.
- **Adding or subtracting a multiple of one row to another:** This operation helps eliminate unwanted values in certain spots of the column, aiding in achieving the desired reduced row-echelon form.

For example, to eliminate the first column entries below the leading 1 in our example system, operations like:\[R_2 = R_2 + 4R_1\]were used to make that column & row form zeros, simplifying the system to find solutions.

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Most popular questions from this chapter

For the following exercises, create a system of linear equations to describe the behavior. Then, calculate the determinant. Will there be a unique solution? If so, find the unique solution. Th ee numbers add up to \(106 .\) The fi st number is 3 less than the second number. The third number is 4 more than the fi st number.

For the following exercises, set up the augmented matrix that describes the situation, and solve for the desired solution. The three most popular ice cream flavors are chocolate, strawberry, and vanilla, comprising \(83 \%\) of the flavors sold at an ice cream shop. If vanilla sells \(1 \%\) more than twice strawberry, and chocolate sells \(11 \%\) more than vanilla, how much of the total ice cream consumption are the vanilla, chocolate, and strawberry flavors?

For the following exercises, set up the augmented matrix that describes the situation, and solve for the desired solution. At an ice cream shop, three flavors are increasing in demand. Last year, banana, pumpkin, and rocky road ice cream made up \(12 \%\) of total ice cream sales. Th s year, the same three ice creams made up \(16.9 \%\) of ice cream sales. The rocky road sales doubled, the banana sales increased by \(50 \%,\) and the pumpkin sales increased by \(20 \%\). If the rocky road ice cream had one less percent of sales than the banana ice cream, fi \(\mathrm{d}\) out the percentage of ice cream sales each individual ice cream made last year.

For the following exercises, set up the augmented matrix that describes the situation, and solve for the desired solution. Bikes'R'Us manufactures bikes, which sell for \(\$ 250\). It costs the manufacturer \(\$ 180\) per bike, plus a startup fee of \(\$ 3,500\). After how many bikes sold will the manufacturer break even?

For the following exercises, solve the system of linear equations using Cramer's Rule. $$ \begin{aligned} 8 x-2 y &=-3 \\ -4 x+6 y &=4 \end{aligned} $$

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