Chapter 6: Problem 9
Graph the function and its reflection about the y-axis on the same axes, and give the y-intercept. $$g(x)=-2(0.25)^{x}$$
Short Answer
Expert verified
Both functions intersect the y-axis at (0, -2) with a y-intercept of -2.
Step by step solution
01
Graph the Original Function
The given function is \( g(x) = -2(0.25)^x \). Start by identifying key points of the function for graphing. Since \( 0.25^x \) is a decreasing exponential function, the original function will also be decreasing but multiplied by \(-2\), which reflects it over the x-axis. Calculate a few values of \( g(x) \):\[\begin{align*}g(0) &= -2(0.25)^0 = -2,\g(1) &= -2(0.25)^1 = -0.5,\g(2) &= -2(0.25)^2 = -0.125.\end{align*}\]Plot these points to graph the function \( g(x) = -2(0.25)^x \).
02
Reflect the Function About the Y-axis
To reflect the function \( g(x) \) about the y-axis, replace \( x \) with \( -x \) in the function. This gives us \( h(x) = -2(0.25)^{-x} = -2(4)^x \). Calculate a few points of the reflected graph: \[\begin{align*}h(0) &= -2(4)^0 = -2,\h(1) &= -2(4)^1 = -8,\h(2) &= -2(4)^2 = -32.\end{align*}\]Plot these points and join them to form the graph of the reflection \( h(x)=-2(4)^x \).
03
Identify the Y-intercept
For both the original function \( g(x) \) and its reflection \( h(x) \), the y-intercept is the value of the function when \( x = 0 \). Thus, the y-intercept for both functions is the point \((0, -2)\).
04
Final Answer: Graph & Y-intercept
The graph consists of the original and reflected functions. They both intersect the y-axis at the point \((0, -2)\). Therefore, the y-intercept for both functions is \(-2\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reflection about y-axis
When you have a function, reflecting it about the y-axis is a simple yet important transformation. This reflection involves changing every occurrence of variable \( x \) to \( -x \). For our function \( g(x) = -2(0.25)^x \), the reflection would be \( h(x) = -2(0.25)^{-x} \). This can be simplified to \( h(x) = -2(4)^x \).
Reflections about the y-axis will essentially "mirror" the function horizontally. Think about your reflection in a virtual mirror placed on the y-axis; the points will appear on the opposite side at the same vertical level. This transformation does not affect the y-intercept of the function, as this point lies directly on the y-axis.
Reflections about the y-axis will essentially "mirror" the function horizontally. Think about your reflection in a virtual mirror placed on the y-axis; the points will appear on the opposite side at the same vertical level. This transformation does not affect the y-intercept of the function, as this point lies directly on the y-axis.
- Original function: \( g(x) = -2(0.25)^x \)
- Reflected function: \( h(x) = -2(4)^x \)
Y-intercept in functions
Finding the y-intercept of a function is straightforward. It is the point where the graph crosses the y-axis. This occurs when \( x = 0 \). Therefore, to find the y-intercept, substitute \( x \) with \( 0 \) in the function.
For both our original function \( g(x) = -2(0.25)^x \) and its reflection \( h(x) = -2(4)^x \), we calculate:
For both our original function \( g(x) = -2(0.25)^x \) and its reflection \( h(x) = -2(4)^x \), we calculate:
- \( g(0) = -2(0.25)^0 = -2 \)
- \( h(0) = -2(4)^0 = -2 \)
Exponential decay and growth
Exponential functions are fascinating because of their rapid change over a short span of x-values. There are two behaviors to note: exponential growth and exponential decay.
In our original function \( g(x) = -2(0.25)^x \), the term \( (0.25)^x \) demonstrates exponential decay. This is because the base \( 0.25 \) is between 0 and 1, making the value shrink as x increases. This shrinking or decaying is further emphasized by the \(-2\), which flips the graph vertically over the x-axis.
Conversely, in the reflected function \( h(x) = -2(4)^x \), the base \( 4 \) is greater than 1, indicating exponential growth. Even though it grows, the \(-2\) in front flips the result, leading the graph to decrease in y-values as x increases.
In our original function \( g(x) = -2(0.25)^x \), the term \( (0.25)^x \) demonstrates exponential decay. This is because the base \( 0.25 \) is between 0 and 1, making the value shrink as x increases. This shrinking or decaying is further emphasized by the \(-2\), which flips the graph vertically over the x-axis.
Conversely, in the reflected function \( h(x) = -2(4)^x \), the base \( 4 \) is greater than 1, indicating exponential growth. Even though it grows, the \(-2\) in front flips the result, leading the graph to decrease in y-values as x increases.
- Exponential decay: \( 0 < \text{base} < 1 \)
- Exponential growth: \( \text{base} > 1 \)
Graph transformations in algebra
Graph transformations can take various forms such as translations, reflections, stretches, and compressions. These transformations alter how a function's graph appears.
Starting with the basic function form \( a(b)^x \):
Starting with the basic function form \( a(b)^x \):
- Reflection: Changing \( x \) to \( -x \) reflects the graph about the y-axis.
- Scaling vertically affects the steepness, either stretching or compressing it.
- Translation moves the graph horizontally or vertically, but not applicable to our function \( g(x) = -2(0.25)^x \).
- Reflect through the negative sign in \(-2\)
- Y-axis reflection by substituting \( x \) to \( -x \) in reflection.