Chapter 6: Problem 10
For the following exercises, graph the function and its reflection about the \(y\) -axis on the same axes, and give the \(y\) -intercept. $$ h(x)=6(1.75)^{-x} $$
Short Answer
Expert verified
The y-intercept is 6; graph both functions to observe reflections.
Step by step solution
01
Understand the Original Function
The given function is \( h(x) = 6(1.75)^{-x} \). This is an exponential function where the base is \( 1.75 \), and it is raised to the power of \( -x \), which means this function will produce a reflection in the \( x \)-axis of a typical exponential decay function.
02
Identify the Reflection Function
To reflect the function \( h(x) = 6(1.75)^{-x} \) about the \( y \)-axis, we replace \( x \) with \( -x \), resulting in the function \( h(-x) = 6(1.75)^{x} \). This is the reflection function that needs to be graphed along with the original function.
03
Plot the Original Function
To plot \( h(x) = 6(1.75)^{-x} \), select various values of \( x \) (such as \( x = -2, -1, 0, 1, 2 \)) and calculate the corresponding \( y \)-values: - For \( x = 0 \), \( y = 6(1.75)^{0} = 6 \)- For \( x = 1 \), \( y = 6(1.75)^{-1} \approx 3.43 \)- For \( x = 2 \), \( y = 6(1.75)^{-2} \approx 1.96 \)- Similarly compute for \( x = -1 \) and \( x = -2 \). Plot these points and draw a smooth curve through them.
04
Plot the Reflection Function
For \( h(-x) = 6(1.75)^x \), compute the \( y \)-values using the same \( x \)-values from Step 3, as follows: - For \( x = 0 \), \( y = 6(1.75)^{0} = 6 \)- For \( x = 1 \), \( y = 6(1.75)^{1} \approx 10.5 \)- For \( x = 2 \), \( y = 6(1.75)^{2} \approx 18.375 \)- Similarly compute for \( x = -1 \) and \( x = -2 \). These values will help plot the reflection curve on the same graph.
05
Determine the y-Intercept
The \( y \)-intercept of a function is where \( x = 0 \). Both original and reflected functions \( h(x) = 6(1.75)^{-x} \) and \( h(-x) = 6(1.75)^x \) yield a \( y \)-intercept of 6 in this case, because \( 6(1.75)^0 = 6 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reflection Across Axes
Reflection across axes is a fundamental concept in graphing functions. It involves flipping the graph over a specified axis, like a mirror. This exercise focuses on reflecting an exponential function across the \( y \)-axis. For any function \( f(x) \), reflecting it across the \( y \)-axis translates to evaluating \( f(-x) \). This simply means that the input \( x \) values are negated, which flips the graph sideways.
For the given function \( h(x) = 6(1.75)^{-x} \), reflecting it over the \( y \)-axis results in \( h(-x) = 6(1.75)^{x} \). It reveals how reflections can transform the features of the graph while retaining some properties like the \( y \)-intercept. Embracing the symmetry and transformations can simplify complex graphing tasks by creating visual connections between different forms of a function.
For the given function \( h(x) = 6(1.75)^{-x} \), reflecting it over the \( y \)-axis results in \( h(-x) = 6(1.75)^{x} \). It reveals how reflections can transform the features of the graph while retaining some properties like the \( y \)-intercept. Embracing the symmetry and transformations can simplify complex graphing tasks by creating visual connections between different forms of a function.
Graphing Functions
Graphing functions is a crucial skill that brings equations to life as visual representations. The task is to take the mathematical description and plot the graph on a coordinate plane to see its behavior.
In this exercise, plotting the graph of the function \( h(x) = 6(1.75)^{-x} \) involves calculating the output for various values of \( x \). Begin by making a table and computing values for conveniently selected points, such as \( x = -2, -1, 0, 1, 2 \).
In this exercise, plotting the graph of the function \( h(x) = 6(1.75)^{-x} \) involves calculating the output for various values of \( x \). Begin by making a table and computing values for conveniently selected points, such as \( x = -2, -1, 0, 1, 2 \).
- For \( x = 0 \), \( y = 6 \)
- For \( x = 1 \), \( y \approx 3.43 \)
- For \( x = 2 \), \( y \approx 1.96 \)
Y-Intercept
The \( y \)-intercept is the point where a graph crosses the \( y \)-axis, which occurs when \( x = 0 \). It's a vital point as it often provides helpful information about the initial value of a function.
Calculating the \( y \)-intercept is straightforward: substitute \( x = 0 \) into the function equation. For this function \( h(x) = 6(1.75)^{-x} \), inserting \( x = 0 \) gives us \( y = 6(1.75)^{0} = 6 \).
The result, \( y = 6 \), reveals that the \( y \)-intercept for both the original and the reflected function is at the same point - (0, 6). This consistency despite reflection is characteristic of many function transformations where the initial condition remains unaffected by horizontal adjustments.
Calculating the \( y \)-intercept is straightforward: substitute \( x = 0 \) into the function equation. For this function \( h(x) = 6(1.75)^{-x} \), inserting \( x = 0 \) gives us \( y = 6(1.75)^{0} = 6 \).
The result, \( y = 6 \), reveals that the \( y \)-intercept for both the original and the reflected function is at the same point - (0, 6). This consistency despite reflection is characteristic of many function transformations where the initial condition remains unaffected by horizontal adjustments.
Function Transformation
Function transformation entails altering a function's formula to produce shifts, stretches, compressions, and reflections of its graph. These manipulations provide a versatile toolkit for graphically representing functions in diverse forms.
In this exercise, a transformation occurs through changing the exponent in the function to a negative value \(-x\), which produces a reflection across the \( y \)-axis and yields \( h(-x) = 6(1.75)^{x} \).
In this exercise, a transformation occurs through changing the exponent in the function to a negative value \(-x\), which produces a reflection across the \( y \)-axis and yields \( h(-x) = 6(1.75)^{x} \).
- A transformation that includes changing signs affects the direction a function heads.
- Scaling by multiplication or division can vertically stretch or compress the graph.
- Translating a function, like adding/subtracting to \( x \) or the whole function, moves the graph horizontally or vertically.