Chapter 5: Problem 22
For the following exercises, determine the domain and range of the quadratic function. $$ f(x)=-2(x+3)^{2}-6 $$
Short Answer
Expert verified
Domain is \((-\infty, \infty)\); Range is \((-
fty, -6]\).
Step by step solution
01
Understand the Function Structure
The given function is a quadratic function in the form \( f(x) = a(x-h)^2 + k \), where \(a = -2\), \(h = -3\), and \(k = -6\). This is a parabola that opens downwards because \(a\) is negative.
02
Determine the Domain
The domain of a quadratic function is all real numbers because there is no restriction on the values that \(x\) can take. Thus, the domain is \((-\infty, \infty)\).
03
Find the Vertex of the Parabola
The vertex of the parabola is at the point \((h, k)\). Here, \(h = -3\) and \(k = -6\), so the vertex is \((-3, -6)\).
04
Determine the Range
Since the parabola opens downwards (\(a = -2 < 0\)), the highest point on the graph is the vertex. Thus, the range of \(f(x)\) is all \(y\) values less than or equal to \(k\), which is \(-6\) in this case. Therefore, the range is \((-fty, -6]\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Domain of a Function
A quadratic function is symbolized by the expression \( f(x) = ax^2 + bx + c \) or transformed versions like \( f(x) = a(x-h)^2 + k \). Regardless of the shape or direction of a parabola, the domain is always about the possible \( x \)-values the function can accept.
In the case of any quadratic function including \( f(x)=-2(x+3)^{2}-6 \), the domain is rather straightforward. For quadratics, it extends across all real numbers because there are no restrictions that prevent \( x \) from taking on any value. With no holes, breaks, or asymptotes in a quadratic function graph, these functions cover the entire \( x \)-axis.
In the case of any quadratic function including \( f(x)=-2(x+3)^{2}-6 \), the domain is rather straightforward. For quadratics, it extends across all real numbers because there are no restrictions that prevent \( x \) from taking on any value. With no holes, breaks, or asymptotes in a quadratic function graph, these functions cover the entire \( x \)-axis.
- This means the domain is \((-fty, fty)\).
- Every quadratic, regardless of how it is shifted or opened up or down, has the same domain.
Range of a Function
While the domain of a quadratic function is all-encompassing, the range involves the set of possible \( y \)-values the function produces. This is heavily influenced by two main factors: the orientation of the parabola (up or down) and the vertex's \( y \)-value.
In a function like \( f(x)=-2(x+3)^{2}-6 \), we notice a few things. The coefficient \( a = -2 \) is negative, indicating that the parabola opens downward. Therefore, its topmost point is the vertex, and the parabola stretches downward without bound.
In a function like \( f(x)=-2(x+3)^{2}-6 \), we notice a few things. The coefficient \( a = -2 \) is negative, indicating that the parabola opens downward. Therefore, its topmost point is the vertex, and the parabola stretches downward without bound.
- The vertex being the highest point limits the range.
- For this function, at the vertex \((-3, -6)\), the \( y \)-value is \(-6\). This means the function can produce \( y \)-values as low as \(-fty\) but no higher than \(-6\).
- Thus, the range is \((-\infty, -6]\).
Vertex of a Parabola
The vertex is a pivotal feature in understanding quadratics as it conveys critical information about the graph itself. It is the point \((h, k)\) in the form \( f(x) = a(x-h)^2 + k \), around which the parabola is symmetrically organized.
For our quadratic function \( f(x)=-2(x+3)^{2}-6 \):
For our quadratic function \( f(x)=-2(x+3)^{2}-6 \):
- The vertex is located at \((-3, -6)\).
- This vertex indicates two things: the \( x \)-coordinate \( h = -3 \) is the axis of symmetry, dividing the parabola into two mirror-image halves, and \( k = -6 \) represents either the minimum or maximum \( y \)-value.
- Since the function opens downwards, \(-6\) is the maximum value.