Chapter 5: Problem 17
For the following exercises, determine whether there is a minimum or maximum value to each quadratic function. Find the value and the axis of symmetry. $$ f(x)=4 x^{2}+x-1 $$
Short Answer
Expert verified
Minimum value is \(-\frac{17}{16}\); axis of symmetry is \(x = -\frac{1}{8}\).
Step by step solution
01
Identify the Form of the Quadratic Function
The given function is a quadratic function in the standard form \(f(x) = ax^2 + bx + c\), where \(a = 4\), \(b = 1\), and \(c = -1\).
02
Determine the Type of Extremum
Since the coefficient \(a = 4\) is positive, the parabola opens upwards. This means there is a minimum value for the quadratic function.
03
Find the Axis of Symmetry
The axis of symmetry for a quadratic function \(f(x) = ax^2 + bx + c\) is given by the formula \(x = -\frac{b}{2a}\). Substitute \(b = 1\) and \(a = 4\) to find the axis of symmetry:\[x = -\frac{1}{2(4)} = -\frac{1}{8}\].
04
Calculate the Minimum Value
To find the minimum value of \(f(x)\), substitute \(x = -\frac{1}{8}\) back into the function:\[f\left(-\frac{1}{8}\right) = 4\left(-\frac{1}{8}\right)^2 + \left(-\frac{1}{8}\right) - 1\]Calculate each part:\[ = 4\left(\frac{1}{64}\right) - \frac{1}{8} - 1\]\[ = \frac{4}{64} - \frac{1}{8} - 1\]\[ = \frac{1}{16} - \frac{2}{16} - \frac{16}{16}\]\[ = -\frac{17}{16}\].Thus, the minimum value of the function is \(-\frac{17}{16}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Axis of Symmetry
In a quadratic function, the axis of symmetry is a vertical line that divides the parabola into two mirror-image halves. It passes through the vertex of the parabola, serving as the "balancing point." For any quadratic function written in the form \( f(x) = ax^2 + bx + c \), you can find the axis of symmetry using the formula:
- \( x = -\frac{b}{2a} \)
- \( x = -\frac{1}{2(4)} = -\frac{1}{8} \)
Finding the Minimum Value of a Quadratic Function
A quadratic function can have either a minimum or maximum value, which occurs at the vertex of the parabola. The direction the parabola opens (upwards or downwards) depends on the sign of the coefficient \( a \) in the standard form equation \( f(x) = ax^2 + bx + c \). If \( a \) is positive, like in our example where \( a = 4 \), the parabola opens upwards and has a minimum value at its vertex.To find the minimum value, we first find the x-coordinate of the vertex using the axis of symmetry formula \( x = -\frac{b}{2a} \), which we determined as \( x = -\frac{1}{8} \). Next, substitute this back into the original function to find the minimum value.For \( f(x) = 4x^2 + x - 1 \):
- Substitute \( x = -\frac{1}{8} \)
- \( f\left(-\frac{1}{8}\right) = 4\left(-\frac{1}{8}\right)^2 + \left(-\frac{1}{8}\right) - 1 \)
- Simplify to find \( f\left(-\frac{1}{8}\right) = -\frac{17}{16} \)
Quadratic Functions and the Standard Form
Quadratic functions are equations that can be expressed in the form \( f(x) = ax^2 + bx + c \). This is known as the standard form. In this expression:
- \( a \) is the coefficient of \( x^2 \) and determines the direction of the parabola (whether it opens upwards or downwards)
- \( b \) is the coefficient of \( x \) and influences the position of the vertex along the x-axis
- \( c \) is the constant term, affecting where the parabola crosses the y-axis
- Quickly identifying the parabola's orientation based on the sign of \( a \)
- Finding the vertex using the axis of symmetry
- Graphing the function accurately on a coordinate plane