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For the following exercises, find the \(x\) - or \(t\) -intercepts of the polynomial functions. $$ f(x)=x^{3}+x^{2}-4 x-4 $$

Short Answer

Expert verified
The x-intercepts are at \((-1, 0)\), \((2, 0)\), and \((-2, 0)\).

Step by step solution

01

Set the Function Equal to Zero

To find the intercepts of the polynomial function, set the equation:\[ f(x)=x^{3}+x^{2}-4x-4 = 0 \]
02

Try Rational Root Theorem

According to the Rational Root Theorem, the possible rational roots are the factors of the constant term (-4), divided by the factors of the leading coefficient (1). Thus, the possible rational roots are \(\pm 1, \pm 2, \pm 4\).
03

Test Possible Rational Roots

Substitute each potential root into the polynomial until you find one that zeroes the function:- For \(x = 1\), \((1)^3 + (1)^2 - 4(1) - 4 = -6\)- For \(x = -1\), \((-1)^3 + (-1)^2 - 4(-1) - 4 = 0\)Thus, \(x = -1\) is a root.
04

Factor the Polynomial

Use the found root \(x = -1\) to factor the polynomial by polynomial division or synthetic division against \(x + 1\). Divide \(x^{3}+x^{2}-4x-4\) by \(x + 1\). The quotient will be \(x^2 - 4\).
05

Solve the Quadratic Equation

The complete factorization using the quadratic is:\[ (x + 1)(x^2 - 4) \]Substitute back and solve:\(x^2 - 4 = 0\) gives roots \(x = 2\) and \(x = -2\).
06

List All Intercepts

The roots found are \(x = -1\), \(x = 2\), and \(x = -2\). Hence, the x-intercepts of the polynomial \(f(x)\) are at \((-1, 0)\), \((2, 0)\), and \((-2, 0)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Root Theorem
The Rational Root Theorem is a useful tool when working with polynomial functions, especially when trying to identify possible rational roots (or x-intercepts). This theorem states that, for a polynomial equation of the form \(a_nx^n + a_{n-1}x^{n-1} + \ldots + a_0 = 0\), any potential rational root \(\frac{p}{q}\) must have a numerator \(p\) that is a factor of the constant term \(a_0\) and a denominator \(q\) that is a factor of the leading coefficient \(a_n\).

In the case of the polynomial \(f(x)=x^{3}+x^{2}-4x-4\), the constant term is \(-4\) and the leading coefficient is \(1\). Thus, the possible rational roots to test are \(\pm 1, \pm 2, \pm 4\). After testing these values, only \(x = -1\) is found to be a root, making it integral in further factoring the polynomial.
Polynomial Division
Polynomial division is akin to the long division method used in arithmetic. It is necessary for breaking down a complex polynomial into simpler parts, typically by dividing by a factor of the polynomial that has been verified as a root. This process can either be carried out by long division or by synthetic division, a shortcut for certain types of polynomials involving one root.

For the polynomial \(x^{3}+x^{2}-4x-4\) and known root \(x = -1\), we can directly transform the full expression to \((x + 1)\), due to \(x - (-1)\), and use this in polynomial division. After performing polynomial division on \(x^{3}+x^{2}-4x-4\) by \(x + 1\), the quotient is \(x^2 - 4\), helping us to factor the overall expression further.
Factoring Polynomials
Factoring polynomials involves rewriting the polynomial as a product of its simpler factors. This step is crucial in finding the roots of the equation. After using polynomial division or identifying a known root, the next step is to factor any remaining quadratic or lower-order polynomials.

From our division of \(x^{3}+x^{2}-4x-4\) by \(x + 1\), we obtained \(x^2 - 4\). Recognizing this as a difference of squares, it can be factored further to \((x - 2)(x + 2)\). Thus, the entire polynomial factors to \((x + 1)(x - 2)(x + 2)\). This expression makes it straightforward to find all the x-intercepts or roots of the original polynomial.
X-Intercepts
Finding x-intercepts is one of the primary goals when working with polynomial functions. The intercepts represent the points where the polynomial crosses the x-axis, indicating the roots of the equation. Each intercept corresponds to a root of the polynomial.

After factoring the polynomial \(f(x)=x^{3}+x^{2}-4x-4\) into \((x + 1)(x - 2)(x + 2)\), we can easily see the x-intercepts:
  • \(x = -1\) from \(x + 1 = 0\)
  • \(x = 2\) from \(x - 2 = 0\)
  • \(x = -2\) from \(x + 2 = 0\)
Therefore, the graph of the polynomial intersects the x-axis at points \((-1, 0)\), \((2, 0)\), and \((-2, 0)\). Identifying these points helps visualize the graph and understand the polynomial's behavior.

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