/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 98 Graph the function \(f\) on a do... [FREE SOLUTION] | 91Ó°ÊÓ

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Graph the function \(f\) on a domain of \([-10,10] : f(x)=0.02 x-0.01 .\) Enter the function in a graphing utility. For the viewing window, set the minimum value of \(x\) to be \(-10\) and the maximum value of \(x\) to be \(10 .\)

Short Answer

Expert verified
Graph the function on domain \([-10, 10]\); it's a line with slope 0.02.

Step by step solution

01

Understand the Function

We are given the function \( f(x) = 0.02x - 0.01 \). This is a linear function, which means its graph will be a straight line. The function is defined on the domain \([-10, 10]\).
02

Determine the Slope and Y-intercept

For the function \( f(x) = 0.02x - 0.01 \), the slope is \(0.02\) and the y-intercept is \(-0.01\). This tells us how steep the line is and where it crosses the y-axis.
03

Set Up the Graphing Utility

Input the function \( f(x) = 0.02x - 0.01 \) into a graphing utility. Set the x-axis to display the range from \(-10\) to \(10\). You may set the y-axis range as the utility's default or adjust according to the scale needed.
04

Graph the Function

Once entered and the viewing window is adjusted, plot the function. You should see a straight line crossing the y-axis at \(-0.01\) and having small positive slope, meaning it slightly inclines to the right as x increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
When exploring linear functions, understanding the domain and range is crucial. The domain of a function is the set of all possible input values—essentially, the 'x' values that you can put into the function. In this exercise, the domain is defined as \([-10, 10]\), which means you can choose any x-value between -10 and 10, inclusive, to plug into the function. These boundaries are important, especially when using a graphing utility because it tells the tool where to start and stop displaying the line.The range, on the other hand, refers to all possible output values—essentially, the 'y' values produced by plugging domain values into the function. In linear functions like this one, the range is directly influenced by the domain. As the x-value changes across the domain, the corresponding y-value will vary. In this case, the function will output values starting at the lower boundary of the domain up to its maximum. Due to the linearity of the function, you see a direct and continuous relationship between x and y-values.
Linear Equations
Linear equations are expressions that form straight lines when graphed. They are typically arranged in the format \( f(x) = mx + b \), where \(m\) represents the slope and \(b\) represents the y-intercept. In our exercise, the linear equation is \( f(x) = 0.02x - 0.01 \). This simple format helps in predicting how the graph will look.In essence, linear equations demonstrate a constant rate of change. This means that for each unit increase in x, there will be a consistent change in y. That's why, when plotted, these equations always result in straight lines. They are essential tools in mathematics and various fields because they help illustrate relationships between variables clearly.
Slope and Y-intercept
Understanding the slope and y-intercept in the context of a linear function is fundamental. The slope, denoted as \( m \) in the equation \( f(x) = mx + b \), signifies the rate at which y changes with respect to x. For our function \( f(x) = 0.02x - 0.01 \), the slope is \( 0.02 \). This indicates that for every unit increase in x, y increases by \0.02\. A positive slope, like this one, suggests that the line slopes up to the right, although here it's quite gradual.The y-intercept, marked as \( b \), indicates the point at which the line crosses the y-axis. In this case, the y-intercept is \( -0.01 \). This means when \( x = 0 \), the function value \( f(x) \) is \( -0.01 \). Graphically, this is where the line meets the vertical axis. Always remember that the slope shows the direction and steepness, while the y-intercept pinpoints the line's starting position on the y-axis. These two together define the unique position and angle of the line on a graph.

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Most popular questions from this chapter

For the following exercises, which of the tables could represent a linear function? For each that could be linear, find a linear equation that models the data. $$ \begin{array}{|c|c|c|c|c|} \hline \boldsymbol{x} & 0 & 5 & 10 & 15 \\ \hline \boldsymbol{f}(\boldsymbol{x}) & -5 & 20 & 45 & 70 \\ \hline \end{array} $$

For the following exercises, use a calculator or graphing technology to complete the task. If \(f\) is a linear function, \(f(0.1)=11.5,\) and \(f(0.4)=-5.9,\) fi \(\mathrm{d}\) an equation for the function.

For the following exercises, use the median home values in Indiana and Alabama (adjusted for inflation) shown in Table \(3 .\) Assume that the house values are changing linearly. \(\begin{array}{lll}{\text { Year }} & {\text { Indiana }} & {\text { Alabama }} \\ {1950} & {\$ 37,700} & {\$ 27,100} \\ {2000} & {\$ 94,300} & {\$ 85,100}\end{array}\) If we assume the linear trend existed before 1950 and continues after 2000 , the two states' median house values will be (or were) equal in what year? (The answer might be absurd.)

In 1991 , the moose population in a park was measured to be \(4,360 .\) By \(1999,\) the population was measured again to be \(5,880\) . Assume the population continues to change linearly. a. Find a formula for the moose population, b. since 1990 . b. What does your model predict the moose population to be in 2003\(?\)

$$ \begin{array}{|c|c|c|c|c|} \hline \boldsymbol{x} & 2 & 4 & 8 & 10 \\ \hline \boldsymbol{h}(\boldsymbol{x}) & 13 & 23 & 43 & 53 \\ \hline \end{array} $$

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