Chapter 4: Problem 55
Write an equation for a line perpendicular to \(p(t)=3 t+4\) and passing through the point \((3,1)\) .
Short Answer
Expert verified
Equation: \( y = -\frac{1}{3}x + 2 \).
Step by step solution
01
Identify the Slope of the Given Line
The given line is expressed with the equation \( p(t)=3t+4 \), which means its slope is 3. We need to find the slope of a line that is perpendicular to this given line.
02
Find the Perpendicular Slope
The slope of a line perpendicular to another line is the negative reciprocal of the original line's slope. Thus, the perpendicular slope is \( -\frac{1}{3} \).
03
Use the Point-Slope Formula
To write the equation of a line, use the point-slope formula: \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is the point through which the line passes.
04
Plug in Values
The slope \( m \) is \( -\frac{1}{3} \), and the point is \( (3,1) \). Substitute these values into the point-slope formula: \( y - 1 = -\frac{1}{3}(x - 3) \).
05
Simplify to Slope-Intercept Form
Distribute and simplify to convert the equation to the slope-intercept form \( y = mx + b \):- Start with the equation: \( y - 1 = -\frac{1}{3}(x - 3) \).- Distribute \( -\frac{1}{3} \): \( y - 1 = -\frac{1}{3}x + 1 \).- Solve for \( y \): \( y = -\frac{1}{3}x + 2 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Slope
The slope is a fundamental concept in understanding the nature of a line on a graph. It indicates the steepness and direction of the line. A greater slope value means a steeper line, while a smaller slope indicates a flatter line. The slope is usually represented by the symbol 'm'.
To calculate the slope of a line from its equation in the form of \( y = mx + b \), we identify 'm'. For the line expressed as \( p(t) = 3t + 4 \), the slope is 3.
Perpendicular lines have a special relationship. Their slopes are negative reciprocals of each other. So, if one line has a slope of 3, the line perpendicular to it will have a slope of \( -\frac{1}{3} \). This is because the product of the slopes of two perpendicular lines is always -1.
To calculate the slope of a line from its equation in the form of \( y = mx + b \), we identify 'm'. For the line expressed as \( p(t) = 3t + 4 \), the slope is 3.
Perpendicular lines have a special relationship. Their slopes are negative reciprocals of each other. So, if one line has a slope of 3, the line perpendicular to it will have a slope of \( -\frac{1}{3} \). This is because the product of the slopes of two perpendicular lines is always -1.
Using the Point-Slope Formula
The point-slope formula is a versatile tool used to find the equation of a line when you know a point on the line and the slope. The formula is expressed as \( y - y_1 = m(x - x_1) \). Here, \( m \) is the slope, and \( (x_1, y_1) \) are the coordinates of the given point.
In our exercise, we have the perpendicular slope \( m = -\frac{1}{3} \) and the point \( (3, 1) \). Plugging these into the point-slope formula gives us:
This step is crucial because it connects the slope and a particular point in a clear and direct way, helping to form the basis for deriving the final equation of the line.
In our exercise, we have the perpendicular slope \( m = -\frac{1}{3} \) and the point \( (3, 1) \). Plugging these into the point-slope formula gives us:
- \( y - 1 = -\frac{1}{3}(x - 3) \)
This step is crucial because it connects the slope and a particular point in a clear and direct way, helping to form the basis for deriving the final equation of the line.
Converting to Slope-Intercept Form
The slope-intercept form of a line is \( y = mx + b \), where 'm' is the slope and 'b' is the y-intercept. This form is helpful for easily identifying the slope and where the line crosses the y-axis.
To convert the equation from point-slope to slope-intercept form, use algebraic manipulation. From our point-slope equation \( y - 1 = -\frac{1}{3}(x - 3) \), you need to:
To convert the equation from point-slope to slope-intercept form, use algebraic manipulation. From our point-slope equation \( y - 1 = -\frac{1}{3}(x - 3) \), you need to:
- Distribute \( -\frac{1}{3} \) over \( (x - 3) \):
\( y - 1 = -\frac{1}{3}x + 1 \) - Add 1 to both sides to solve for \( y \):
\( y = -\frac{1}{3}x + 2 \)