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For the following exercises, determine whether the equation of the curve can be written as a linear function. $$ -2 x^{2}+3 y^{2}=6 $$

Short Answer

Expert verified
The equation is not linear; it's a hyperbola.

Step by step solution

01

Understand the equation type

The given equation is \(-2x^2 + 3y^2 = 6\). This equation includes squared terms \(x^2\) and \(y^2\), which suggest that it is likely to represent a conic section, such as an ellipse or hyperbola, not a linear function. Linear functions do not have squared terms.
02

Simplification and Rearrangement

Attempt to rearrange the equation to identify the type of conic section. We start with \(-2x^2 + 3y^2 = 6\). Divide the entire equation by 6 to simplify: \[-\frac{2}{6}x^2 + \frac{3}{6}y^2 = 1\] which simplifies to \[-\frac{1}{3}x^2 + \frac{1}{2}y^2 = 1\].
03

Identify the Conic Section

Notice that when rewritten, \(-\frac{1}{3}x^2 + \frac{1}{2}y^2 = 1\) resembles the standard form of a hyperbola: \(-\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\). This confirms that the equation represents a hyperbola. A hyperbola is not a linear function since it is not in the form \(y = mx + b\).
04

Conclusion about Linearity

Since we identified the conic section as a hyperbola and not a linear equation, we conclude that the given equation cannot be written as a linear function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Functions
Linear functions are the most basic type of function in mathematics and are easily recognizable. They have the general form given by the equation: \[ y = mx + b \] where:
  • \(m\) is the slope of the line. It shows how steep the line is and the direction it goes, either upward or downward.
  • \(b\) is the y-intercept, which tells you where the line crosses the y-axis.
Linear functions are represented graphically by straight lines. They don't contain any exponents other than one, and their plots are always lines that extend infinitely in both directions. In contrast to the equation \(-2x^2 + 3y^2 = 6\), linear functions do not include squared terms like \(x^2\) or \(y^2\). This means the equations do not curve and have straightforward, straightforward, predictable relationships. So, if you ever see squared terms, you're dealing with more complex forms such as conic sections, not linear functions.
Hyperbola
A hyperbola is a specific type of conic section defined as the locus of points where the difference of the distances to two fixed points, called foci, is constant. The standard form of a hyperbola can be written as: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] This describes a hyperbola that opens left and right. There's another form which opens up and down: \[ \frac{y^2}{b^2} - \frac{x^2}{a^2} = 1 \] In the given equation, \(-\frac{1}{3}x^2 + \frac{1}{2}y^2 = 1\), we rearranged the original equation to fit the hyperbola's standard form, confirming it represents a hyperbola. Some key characteristics of a hyperbola include:
  • Two separate curves or branches.
  • An asymptote line that the curves approach but never actually touch.
  • Openings along either the x or y axis.
These features differentiate hyperbolas significantly from linear functions which are simply straight lines.
Quadratic Equation
Quadratic equations are polynomials of degree two, typically taking the form: \[ ax^2 + bx + c = 0 \] They represent parabolas when graphed with a characteristic U-shape, either opening upwards or downwards depending on the coefficient of \(x^2\). Key features of quadratic equations include:
  • A leading coefficient \(a\) which affects the width and direction of the parabola.
  • A vertex which is the highest or lowest point on the graph depending on the parabola's opening direction.
  • An axis of symmetry that runs vertically through the vertex, dividing the parabola into mirror-image halves.
While the equation \(-2x^2 + 3y^2 = 6\) includes quadratic terms, it's not a simple quadratic equation due to the presence of both \(x^2\) and \(y^2\). Instead, it aligns with a conic section. Quadratic functions on their own can still share the squared term but are focused around the use of one variable, unlike the hyperbola in focus here.

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