Chapter 4: Problem 102
Graph the linear function \(f\) on a domain of [-10,10] for the function whose slope is \(\frac{1}{8}\) and \(y\) -intercept is \(\frac{31}{16}\). Label the points for the input values of -10 and 10 .
Short Answer
Expert verified
Graph the line through points (-10, \(\frac{11}{16}\)) and (10, \(\frac{51}{16}\)) on the domain [-10, 10].
Step by step solution
01
Understanding the Linear Function
A linear function can be expressed in the slope-intercept form: \( f(x) = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Here, \( m = \frac{1}{8} \) and \( b = \frac{31}{16} \).
02
Determine the Function Equation
Insert the given slope and y-intercept into the slope-intercept form: \( f(x) = \frac{1}{8}x + \frac{31}{16} \). This is the equation of the linear function to be graphed.
03
Calculate Points for Domain Input -10
Use \( x = -10 \) to find the corresponding \( f(x) \). Substitute into the function: \( f(-10) = \frac{1}{8}(-10) + \frac{31}{16} \). This simplifies to \( -\frac{10}{8} + \frac{31}{16} = -\frac{5}{4} + \frac{31}{16} \). Convert \(-\frac{5}{4}\) to \( -\frac{20}{16} \) to add: \( -\frac{20}{16} + \frac{31}{16} = \frac{11}{16} \). Thus, the point is (-10, \( \frac{11}{16} \)).
04
Calculate Points for Domain Input 10
Use \( x = 10 \) to find \( f(x) \). Substitute into the function: \( f(10) = \frac{1}{8}(10) + \frac{31}{16} \). This simplifies to \( \frac{10}{8} + \frac{31}{16} = \frac{5}{4} + \frac{31}{16} \). Convert \(\frac{5}{4}\) to \( \frac{20}{16} \) to add: \( \frac{20}{16} + \frac{31}{16} = \frac{51}{16} \). The point is (10, \( \frac{51}{16} \)).
05
Graph the Function on the Domain [-10, 10]
Plot the two calculated points (-10, \( \frac{11}{16} \)) and (10, \( \frac{51}{16} \)) on the coordinate plane. Use these points to draw a straight line which represents the linear function \( f(x) = \frac{1}{8}x + \frac{31}{16} \) over the domain from -10 to 10.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
When working with linear functions, one of the most common ways to represent them is using the slope-intercept form. This form is expressed as:\[ f(x) = mx + b \] Here, \( m \) represents the slope of the line, and \( b \) denotes the y-intercept. The slope \( m \) indicates how steep the line is. A larger value of \( m \) means the line is steeper, and it moves upward more quickly as you move from left to right.The y-intercept \( b \) is the point where the line crosses the y-axis on a graph.One important thing about the slope-intercept form is that it makes it very easy to quickly understand and graph a linear function.
- The slope \( m \) tells you how many units to move up or down for every unit you move to the right.
- The y-intercept \( b \) gives you a starting point on the y-axis where you can begin graphing the line.
Graphing Functions
Graphing a linear function involves plotting points on a plane to visualize the line represented by the function. To graph a function like \( f(x) = \frac{1}{8}x + \frac{31}{16} \), you begin by identifying key components: the slope and y-intercept.
1. **Locate the Y-Intercept**: Start at \( b = \frac{31}{16} \) on the y-axis. This is the initial point where your graph will begin.2. **Apply the Slope**: From the y-intercept, use the slope \( m = \frac{1}{8} \) to determine the direction of the line. For every 8 units you move horizontally, move 1 unit vertically, since the slope is \( \frac{1}{8} \).
To ensure the accuracy of your line, compute and plot additional points if needed, using different \( x \) values within your domain. By connecting these points with a straight line, you create a visual representation of the function, effectively illustrating the linear relationship between \( x \) and \( f(x) \). This process highlights how the slope and y-intercept guide the plotting of the line on the graph.
1. **Locate the Y-Intercept**: Start at \( b = \frac{31}{16} \) on the y-axis. This is the initial point where your graph will begin.2. **Apply the Slope**: From the y-intercept, use the slope \( m = \frac{1}{8} \) to determine the direction of the line. For every 8 units you move horizontally, move 1 unit vertically, since the slope is \( \frac{1}{8} \).
To ensure the accuracy of your line, compute and plot additional points if needed, using different \( x \) values within your domain. By connecting these points with a straight line, you create a visual representation of the function, effectively illustrating the linear relationship between \( x \) and \( f(x) \). This process highlights how the slope and y-intercept guide the plotting of the line on the graph.
Coordinate Plane
The coordinate plane is a fundamental concept in graphing functions. It consists of two perpendicular axes: the x-axis (horizontal) and the y-axis (vertical), which intersect at the origin (0,0). Every point on this plane can be identified using an ordered pair \((x, y)\), where \( x \) is the position along the horizontal axis, and \( y \) is the location along the vertical axis.When plotting a function like \( f(x) = \frac{1}{8}x + \frac{31}{16} \) on the coordinate plane:
- First, find the y-intercept on the y-axis where the value of \( x \) is 0.
- Second, choose several \( x \) values, such as -10 and 10, and calculate their corresponding \( f(x) \) values.
- Plot these points on the plane based on their ordered pairs \((x, f(x))\).