Chapter 3: Problem 24
Given functions \(q(x)=\frac{1}{\sqrt{x}}\) and \(h(x)=x^{2}-9,\) state the domain of each of the following functions using interval notation. a. \(\frac{q(x)}{h(x)}\) b. \(q(h(x))\) c. \(h(q(x))\)
Short Answer
Expert verified
a. \((0, 3) \cup (3, \infty)\); b. \((-\infty, -3) \cup (3, \infty)\); c. \((0, \infty)\)
Step by step solution
01
Determine Domain of q(x)
The function \( q(x) = \frac{1}{\sqrt{x}} \) is only defined for \( x > 0 \) because the square root and the denominator cannot be zero. Thus, the domain of \( q(x) \) is \((0, \infty)\).
02
Determine Domain of h(x)
The function \( h(x) = x^2 - 9 \) is a polynomial and is defined for all real numbers. Hence, the domain of \( h(x) \) is \((-\infty, \infty)\).
03
Identify Domain Constraints for q(x)/h(x)
For \( \frac{q(x)}{h(x)} = \frac{1/\sqrt{x}}{x^2 - 9} \), \( q(x) \) requires \( x > 0 \) and \( h(x) eq 0 \). Solve \( x^2 - 9 = 0 \) to find when \( h(x) = 0 \), which gives \( x = \pm 3 \). The domain is \( x > 0 \) excluding \( x = 3 \), so the domain is \((0, 3) \cup (3, \infty)\).
04
Identify Domain Constraints for q(h(x))
For \( q(h(x)) = \frac{1}{\sqrt{h(x)}} = \frac{1}{\sqrt{x^2 - 9}} \), solve \( x^2 - 9 > 0 \) which leads to \( x^2 > 9 \) or \( x > 3 \) and \( x < -3 \). Hence, the domain is \((-\infty, -3) \cup (3, \infty)\).
05
Identify Domain Constraints for h(q(x))
For \( h(q(x)) = \left( \frac{1}{\sqrt{x}} \right)^2 - 9 = \frac{1}{x} - 9 \), it is defined for \( q(x) \) which requires \( x > 0 \). Therefore, the domain is \((0, \infty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
When expressing the domain of functions, interval notation is a clean and concise way to show which input values are acceptable for a function. It takes the form of either open intervals, closed intervals, or a combination of both.
In interval notation:
In interval notation:
- An open interval, such as \(a, b\), means that the endpoints 'a' and 'b' are not included.
- A closed interval, indicated by \[a, b\], includes both endpoints.
- If a function is defined for all real numbers except specific points, we use union symbols \cup to combine different intervals.
Function Composition
Function composition involves creating a new function by applying one function to the results of another. This means if you have two functions, say \( f(x) \) and \( g(x) \), you can form a composite function \( (f \circ g)(x) \), which is read as 'f composed with g'.
Here's how it generally works:
Here's how it generally works:
- The output of \( g(x) \) becomes the input for \( f(x) \).
- The result is a new function that we represent as \( f(g(x)) \).
Polynomial Functions
Polynomial functions are expressions that involve terms in which variables are raised to whole number exponents. A typical polynomial looks like \( a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0 \), where \( a_i \) are coefficients.
Key characteristics of polynomial functions include:
Key characteristics of polynomial functions include:
- They are defined for all real numbers.
- Their graphs are smooth and continuous without breaks, holes, or jumps.
- The domain of a polynomial function is always \((-\infty, \infty)\).
Square Root Functions
A square root function takes the form \( \sqrt{x} \), where the result is the non-negative number that, when squared, gives \( x \). The domain of a square root function is typically restricted to non-negative values, i.e., \( x \geq 0 \) because the square root of a negative number is not a real number.
Features of square root functions include:
Features of square root functions include:
- The output is always non-negative.
- The graph of a basic square root function \( y = \sqrt{x} \) starts at the origin and increases without bound.