Chapter 3: Problem 15
For the following exercises, find the \(x\) - and \(y\) -intercepts of the graphs of each function. $$ f(x)=-|x-9|+16 $$
Short Answer
Expert verified
y-intercept: (0, 7); x-intercepts: (-7, 0) and (25, 0).
Step by step solution
01
Find the y-intercept
To find the y-intercept of the function, evaluate the function at \(x = 0\). This is because the y-intercept occurs where the graph crosses the y-axis.Substitute \(x = 0\) into the function: \[f(x) = -|x-9|+16\] \[f(0) = -|0-9|+16\] \[f(0) = -|-9|+16\] \[f(0) = -9 + 16\] \[f(0) = 7\] So, the y-intercept is at the point \((0, 7)\).
02
Find the x-intercepts
To find the x-intercepts, set \(f(x)\) equal to 0 and solve for \(x\). The x-intercepts are the points where the graph crosses the x-axis.Set the function equal to 0:\[0 = -|x-9|+16\] Add \(|x-9|\) to both sides:\[|x-9| = 16\] The absolute value equation \(|x-9| = 16\) has two solutions:1. \(x - 9 = 16\) 2. \(x - 9 = -16\)Solve each equation separately:**Equation 1:** \[x - 9 = 16\] \[x = 25\]**Equation 2:** \[x - 9 = -16\] \[x = -7\]So, the x-intercepts are at the points \((-7, 0)\) and \((25, 0)\).
03
Summary of intercepts
In summary, the y-intercept of the function is at the point \((0, 7)\), and the x-intercepts are at the points \((-7, 0)\) and \((25, 0)\). These are the points where the graph crosses the axes.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
x-intercepts
In the realm of functions and their graphs, finding the x-intercepts is a vital step in understanding the behavior of the function. The x-intercepts are the points where the graph of the function crosses the x-axis. This means that at these points, the y-coordinate is zero. To find the x-intercepts, we need to set the function equal to zero and solve for the variable, usually denoted as \(x\).
In our exercise, the function given is \(f(x) = -|x-9| + 16\). To find the x-intercepts, you substitute \(f(x)\) with 0 and solve:
In our exercise, the function given is \(f(x) = -|x-9| + 16\). To find the x-intercepts, you substitute \(f(x)\) with 0 and solve:
- Start with the equation: \(0 = -|x-9| + 16\)
- Rearrange to isolate the absolute value: \(|x-9| = 16\)
- \(x - 9 = 16\)
- \(x - 9 = -16\)
- For \(x - 9 = 16\), \(x = 25\)
- For \(x - 9 = -16\), \(x = -7\)
y-intercepts
The y-intercept of a function is another fundamental aspect of analyzing graphs. This is the point where the graph crosses the y-axis, which occurs when \(x = 0\). In simple terms, it is the value of the function when the input is zero.
To find the y-intercept for our function \(f(x) = -|x-9| + 16\), you would substitute \(x\) with 0:
To find the y-intercept for our function \(f(x) = -|x-9| + 16\), you would substitute \(x\) with 0:
- Evaluate \(f(0) = -|0-9| + 16\)
- Simplify this to: \(-|-9| + 16\)
- Become: \(-9 + 16\)
absolute value function
Understanding the absolute value function is key in analyzing expressions like \(-|x-9| + 16\). The absolute value of a number is its distance from zero, regardless of direction on a number line. Therefore, it is always represented as a non-negative number.
In our function, the absolute value component \(|x-9|\) shifts the graph horizontally by 9 units. This operation means we consider both \(x-9\) and \(-x+9\), leading to a reflection effect that results in a "V-like" shape characteristic of absolute value functions. By manipulating this shape with a factor or by adding or subtracting a constant, you can move the "V" up, down, left, or right on a graph.
For \(f(x) = -|x-9| + 16\), the graph is translated upwards by 16 units because of the "+16". The negative sign before the absolute value flips the graph over the horizontal axis, turning the "V" shape upside down.
When analyzing absolute value functions, always remember:
In our function, the absolute value component \(|x-9|\) shifts the graph horizontally by 9 units. This operation means we consider both \(x-9\) and \(-x+9\), leading to a reflection effect that results in a "V-like" shape characteristic of absolute value functions. By manipulating this shape with a factor or by adding or subtracting a constant, you can move the "V" up, down, left, or right on a graph.
For \(f(x) = -|x-9| + 16\), the graph is translated upwards by 16 units because of the "+16". The negative sign before the absolute value flips the graph over the horizontal axis, turning the "V" shape upside down.
When analyzing absolute value functions, always remember:
- The point at which the variable is zero inside the absolute value determines the vertex (in this case \(x=9\));
- Positive absolute value coefficients stretch the graph, while negative create a reflection.