Chapter 2: Problem 6
Solve the quadratic equation by factoring. $$ x^{2}+4 x-21=0 $$
Short Answer
Expert verified
The solutions are \(x = -7\) and \(x = 3\).
Step by step solution
01
Identify the Quadratic Equation
The given equation is a quadratic equation of the form \( ax^2 + bx + c = 0 \). Here, the coefficients are: \( a = 1 \), \( b = 4 \), \( c = -21 \).
02
Find Two Numbers that Multiply to \( c \) and Add to \( b \)
To factor the quadratic, we need two numbers that multiply to \(-21\) (the constant term) and add to \(4\) (the coefficient of \(x\)). After exploring possibilities, the numbers \(7\) and \(-3\) satisfy these conditions because \(7 \times (-3) = -21\) and \(7 + (-3) = 4\).
03
Write Middle Term as Two Separate Terms
Split the middle term \(4x\) into \(7x\) and \(-3x\) so that the equation is expressed as: \[ x^2 + 7x - 3x - 21 = 0. \]
04
Group Terms and Factor by Grouping
Group the terms to factor by grouping: \( (x^2 + 7x) + (-3x - 21) = 0 \). Factor out the common factors from each group. The expression becomes \( x(x + 7) - 3(x + 7) = 0 \).
05
Factor the Common Binomial
Notice that \((x + 7)\) is a common factor. Factor it out: \[ (x + 7)(x - 3) = 0. \]
06
Solve for \(x\)
Set each factor equal to zero and solve for \(x\):1. \( x + 7 = 0 \rightarrow x = -7 \).2. \( x - 3 = 0 \rightarrow x = 3 \).
07
Verify the Solutions
Substitute \(x = -7\) and \(x = 3\) back into the original equation to verify both solutions are correct. The solutions satisfy the equation \( x^2 + 4x - 21 = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Method
The factoring method is a powerful tool in solving quadratic equations. It involves rewriting the quadratic expression as a product of two binomial expressions. For a quadratic equation of the form:
In our example given by the equation \( x^2 + 4x - 21 = 0 \), we need numbers that multiply to -21 and add to 4. The numbers 7 and -3 work because:
- \( ax^2 + bx + c = 0 \)
In our example given by the equation \( x^2 + 4x - 21 = 0 \), we need numbers that multiply to -21 and add to 4. The numbers 7 and -3 work because:
- \( 7 \times (-3) = -21 \)
- \( 7 + (-3) = 4 \)
Solving Quadratic Equations
Quadratic equations can be solved via several methods, one of which is factoring, as demonstrated in this exercise. Solving involves finding the values of \( x \) that make the equation equal zero. After factoring the quadratic equation, the next step:
- Express the quadratic in the form \((x - p)(x - q) = 0\)
- \( x = p \)
- \( x = q \)
- \( x + 7 = 0 \Rightarrow x = -7 \)
- \( x - 3 = 0 \Rightarrow x = 3 \)
Algebraic Techniques
To efficiently tackle quadratic equations, certain algebraic techniques are essential. Understanding the concept of factoring, grouping, and solving is key.
Let's take a closer look at the original equation:
This use of algebraic techniques not only aids in solving the equation but also builds foundational skills for more complex algebraic manipulations.
Let's take a closer look at the original equation:
- Group terms for ease of factorization, i.e., \( (x^2 + 7x) + (-3x - 21) \).
- Extract common factors from each group, resulting in \( x(x + 7) - 3(x + 7) \).
- Notice the repeated binomial \( (x + 7) \), which is a common factor.
This use of algebraic techniques not only aids in solving the equation but also builds foundational skills for more complex algebraic manipulations.