Chapter 2: Problem 33
Graph the function. Observe the points of intersection and shade the \(x\) -axis representing the solution set to the inequality. Show your graph and write your final answer in interval notation. $$ |x-1|>2 $$
Short Answer
Expert verified
The solution set is \((-
fty, -1) \cup (3,
fty)\).
Step by step solution
01
Understanding the Inequality
The inequality given is \(|x-1|>2\). This means we need to find all \(x\) values for which the distance between \(x\) and 1 is greater than 2. We will split this into two separate inequalities.
02
Breaking Down the Absolute Value Inequality
We can split the inequality \(|x-1|>2\) into two separate inequalities: \(x-1 > 2\) and \(x-1 < -2\). We will solve these inequalities separately.
03
Solve First Inequality
For \(x-1 > 2\), adding 1 to both sides gives us \(x > 3\). This means \(x\) must be greater than 3.
04
Solve Second Inequality
For \(x-1 < -2\), adding 1 to both sides gives us \(x < -1\). This means \(x\) must be less than -1.
05
Combine the Solutions
The solution for the inequality \(|x-1|>2\) is the union of the solutions from the two inequalities: \(x < -1\) or \(x > 3\). We can express this in interval notation as \((-fty, -1) \cup (3, fty)\).
06
Graph the Solution
On a number line, we shade to the left of -1 and to the right of 3, indicating the regions where the inequality holds true. The regions \((-fty, -1)\) and \((3, fty)\) do not include -1 and 3 themselves, as indicated by open circles at -1 and 3.
07
Final Representation and Interval Notation
The solution set on the number line corresponds to values of \(x\) outside the interval \([-1, 3]\). The solution to the inequality \(|x-1|>2\) in interval notation is \((-fty, -1) \cup (3, fty)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Inequalities
When it comes to graphing inequalities on a number line, the main goal is to visually represent the solution set of the inequality. For an inequality like \(|x-1|>2\), we need to show where the inequality holds true. This involves identifying on the number line:
- The regions that satisfy the inequality.
- Whether certain points are included or excluded.
- Shade all numbers less than -1.
- Leave -1 itself unshaded, indicating it's not part of the solution (open circle).
- Also shade numbers greater than 3.
- Leave 3 itself unshaded (open circle as well).
Interval Notation
Interval notation is a concise way to describe sets of numbers on a number line. It's especially handy for inequalities because it clearly shows which numbers are included or excluded from the solution set. For instance, let's take the solution to \(|x-1|>2\): \(x < -1\) or \(x > 3\).
- This translates to two separate intervals: \((-\infty, -1)\) and \((3, \infty)\).
- Parentheses \(()\) are used because -1 and 3 are not included in the solution, which matches the open circles on the graph.
- The union symbol \(\cup\) is used to combine the two intervals, indicating the complete solution set.
Solution Sets
A solution set is simply the collection of numbers that satisfy a given inequality. When dealing with inequalities involving absolute values, the solution set often comprises multiple intervals. For our example \(|x-1|>2\), the solution set includes:
- All \(x\) values less than -1.
- All \(x\) values greater than 3.
Inequality Solving Steps
Solving absolute value inequalities involves a structured approach to ensure all solutions are found. Here's how it's done:
- Step 1: Understand the Inequality: Absolute value inequalities like \(|x-1|>2\) measure distance from a point on a number line. We're looking for points more than 2 units away from 1.
- Step 2: Split the Inequality: The inequality is divided into two: \(x - 1 > 2\) and \(x - 1 < -2\). This comes from the nature of absolute values needing to consider both the positive and negative distances.
- Step 3: Solve Each Part Separately: Solve \(x - 1 > 2\) by adding 1 to find \(x > 3\). Solve \(x - 1 < -2\) similarly to find \(x < -1\).
- Step 4: Combine the Solutions: Merge the separate solutions using union, resulting in \(x < -1\) or \(x > 3\), and express in interval notation: \((-\infty, -1) \cup (3, \infty)\).