/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Find the limit. $$ \lim _{n ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limit. $$ \lim _{n \rightarrow \infty}\left(4-\frac{2}{n}\right) $$

Short Answer

Expert verified
\( \lim_{n \to \infty} \left( 4 - \frac{2}{n} \right) = 4 \).

Step by step solution

01

Substitute the Limit into the Expression

Start by considering the expression inside the limit: \( 4 - \frac{2}{n} \). As \( n \) approaches infinity, the fraction \( \frac{2}{n} \) changes its value. Let's explore what happens when we substitute \( n \to \infty \).
02

Evaluate the Behavior of \( \frac{2}{n} \) as \( n \to \infty \)

As \( n \to \infty \), the term \( \frac{2}{n} \) becomes smaller and smaller because you are dividing 2 by a larger and larger number. Mathematically, as \( n \) approaches infinity, \( \frac{2}{n} \to 0 \).
03

Simplify the Expression as \( n \to \infty \)

With \( \frac{2}{n} \rightarrow 0 \), substitute it back into the original expression: \( 4 - \frac{2}{n} \). As \( \frac{2}{n} \to 0 \), the expression becomes \( 4 - 0 \).
04

Final Evaluation of the Limit

The simplified expression is \( 4 \). Hence, the limit of the expression as \( n \to \infty \) is 4.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Infinity in Limits
When dealing with infinity in limits, it is crucial to grasp how we describe the behavior of a sequence or function as its variable approaches infinity. Think of infinity not as a number, but more of a concept representing something growing without bound. When we say \( n \rightarrow \infty \), we are interested in what the sequence or function settles into as \( n \) becomes very large.
Consider the expression \( 4 - \frac{2}{n} \). As \( n \) increases, \( \frac{2}{n} \) gets smaller and approaches zero. This is a good example of handling infinity because it shows how a part of the sequence disappears as \( n \rightarrow \infty \).
It's important to understand that the rest of the expression, in this case, the constant 4, remains unchanged as \( n \rightarrow \infty \). The influence of the variable vanishes, leaving behind this constant as the final result. This shows how infinity serves as a tool to provide a "long-term" perspective of expressions.
The Meaning of Convergence
Convergence is a core concept when talking about limits. It describes how a sequence or function approaches a specific value as its variable moves towards a target, often infinity. In simpler terms, when a sequence converges, it means that as we keep stepping through the terms, they get closer and closer to a particular value.
In the context of the given exercise \( \lim _{n \rightarrow \infty}(4-\frac{2}{n}) \), the expression converges to 4. Given that \( \frac{2}{n} \) approaches zero, the sequence \( 4 - \frac{2}{n} \) moves closer and closer to 4.
Convergence is a fundamental part of calculus as it helps us determine if sequences are "heading towards" a specific number or if they diverge by growing large without settling. Recognizing convergence allows us to solve limit problems by knowing that we're looking for a "settling value".
Connecting This to Calculus
Calculus is a branch of mathematics that studies how things change and involves key concepts like limits, derivatives, and integrals. Limits are foundational in calculus as they allow us to handle values and functions that change continuously.
In calculus, by finding limits, such as \( \lim _{n \rightarrow \infty}(4-\frac{2}{n}) \), we determine how functions behave as their variables tend towards infinity or other critical points. This aids calculations in many real-world situations where continuous change is a factor.
Understanding limits and convergence is also crucial because these concepts enable us to make sense of more complex ideas in calculus, such as derivatives which represent rates of change, and integrals which signify accumulations of quantities.

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Most popular questions from this chapter

Let \(p>1\). Show that for any integer \(j\), the \(j\) th truncation error \(E_{j}\) for \(\sum_{n=1}^{\infty} 1 / n^{p}\) satisfies the inequalities $$ \frac{1}{(p-1)(j+1)^{p-1}} \leq E_{j} \leq \frac{1}{(p-1) j^{p-1}} $$

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