Chapter 9: Problem 27
Evaluate the limit as a number, \(\infty\), or \(-\infty\), $$ \lim _{k \rightarrow \infty}(1+k)^{1 /(2 k)} $$
Short Answer
Expert verified
The limit is 1.
Step by step solution
01
Understand the Expression
We need to evaluate the limit of \( (1 + k)^{1/(2k)} \) as \( k \to \infty \). This involves a function with a variable raised to a power that depends on the variable itself.
02
Simplify the Power
We rewrite \( (1 + k)^{1/(2k)} \) as \( \exp\left( \frac{1}{2k}\log(1 + k) \right) \). This helps separate the exponent from the base in the limit evaluation.
03
Find the Limiting Value of the Exponent
Evaluate \( \lim_{k \to \infty} \frac{1}{2k} \log(1 + k) \). We know that \( \log(1+k) \sim \log(k) \) as \( k \to \infty \), so \( \lim_{k \to \infty} \frac{1}{2k} \log(1 + k) = \lim_{k \to \infty} \frac{1}{2k} \log(k) \).
04
Use L'Hôpital's Rule
The limit \( \lim_{k \to \infty} \frac{\log(k)}{2k} \) is an indeterminate form \( \frac{\infty}{\infty} \). Applying L'Hôpital's Rule gives: \[ \lim_{k \to \infty} \frac{1/k}{2} = 0 \]. Hence, the exponent approaches 0 as \( k \to \infty \).
05
Evaluate the Limit of the Original Expression
The expression becomes \( \exp(0) = 1 \). Therefore, \( \lim_{k \to \infty} (1 + k)^{1/(2k)} = 1 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
L'Hôpital's Rule
L'Hôpital's Rule is a powerful tool in calculus used to evaluate limits that result in indeterminate forms. When presented with a limit of the form \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \), L'Hôpital's Rule can be employed. The rule states that the limit of a quotient of two functions can be found by taking the derivatives of the numerator and the denominator separately, as long as the original limit resulted in an indeterminate form.
- Apply the rule only when the initial limit is an indeterminate form like \( \frac{0}{0} \) or \( \frac{\infty}{\infty} \).
- Differentiate both the numerator and the denominator until the limit is no longer indeterminate.
- If the new expression still results in an indeterminate form, you might need to apply the rule again.
Exponential Function
The exponential function, denoted as \( \exp(x) \) or \( e^x \), is a fundamental concept in mathematics, particularly in calculus. One of its defining features is its rate of growth, which is proportional to its current value. The function \( e^x \) is unique due to its property that the function is its own derivative.
- The base of the natural logarithm, \( e \), is approximately 2.71828.
- The exponential function expands quickly as its argument, \( x \), gets larger.
- It appears in many natural processes, including population growth and radioactive decay.
Indeterminate Forms
Indeterminate forms are expressions in calculus that do not initially have a clear limit. Common types include \( \frac{0}{0} \), \( \frac{\infty}{\infty} \), "\( 0 \times \infty \)", \( \infty - \infty \), and others. These forms suggest ambiguity because they can lead to more than one result based on the structure of the original functions involved.
- They often require algebraic manipulation or applying calculus theorems like L'Hôpital's Rule.
- Not all ambiguous expressions are indeterminate forms; they specifically arise in the context of limits.
- Each form might need a different approach for resolving into a determinate value.