Chapter 8: Problem 42
In Exercises evaluate the integral. $$ \int \frac{e^{3 w}}{\sqrt{1-e^{2 w}}} d w $$
Short Answer
Expert verified
The integral evaluates to \( \frac{1}{2} \left[ \arcsin(e^w) - \frac{1}{2} e^{2w} \right] + C \).
Step by step solution
01
Substitution
To simplify the integral, let's use the substitution method. Let \( u = e^{w} \). Thus, \( du = e^{w} \, dw \) or \( dw = \frac{du}{e^{w}} \). Since \( u = e^w \), it follows that \( dw = \frac{du}{u} \). The integral becomes: \( \int \frac{u^3}{\sqrt{1-u^2}} \times \frac{1}{u} du = \int \frac{u^2}{\sqrt{1-u^2}} du \).
02
Trigonometric Substitution
To further simplify the integral, use the trigonometric substitution \( u = \sin(\theta) \). Thus, \( du = \cos(\theta) \, d\theta \) and \( \sqrt{1-u^2} = \cos(\theta) \). Substitute these into the integral: \( \int \frac{\sin^2(\theta)}{\cos(\theta)} \cdot \cos(\theta) \, d\theta = \int \sin^2(\theta) \, d\theta \).
03
Simplifying the Integral
The integral \( \int \sin^2(\theta) d\theta \) can be solved using the identity \( \sin^2(\theta) = \frac{1 - \cos(2\theta)}{2} \). Substitute this into the integral: \( \int \frac{1 - \cos(2\theta)}{2} d\theta = \frac{1}{2} \int (1 - \cos(2\theta)) d\theta \).
04
Solving the Integral
Solve \( \frac{1}{2} \int (1 - \cos(2\theta)) d\theta \). This becomes \( \frac{1}{2} \left[ \theta - \frac{1}{2}\sin(2\theta) \right] + C \).
05
Back-substitute to Original Variable
Since \( u = \sin(\theta) \) and \( u = e^w \), we have \( \theta = \arcsin(e^w) \). Therefore, the solution in terms of \( w \) is \( \frac{1}{2} \left[ \arcsin(e^w) - \frac{1}{2} e^{2w} \right] + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful tool in integral calculus. It simplifies complex integrals by transforming them into a more manageable form. **Basic Idea**The main idea is to substitute a part of the original integral with a new variable, usually denoted as "u". This substitution is chosen to make integration easier. For example, given the integral \( \int \frac{e^{3w}}{\sqrt{1-e^{2w}}} \, dw \), we start by setting \( u = e^w \). By doing this, the differential \( du = e^w \, dw \) or \( dw = \frac{du}{u} \). **Steps to Apply Substitution**
- Identify a substitution that simplifies the integral.
- Express \( dw \) in terms of \( du \).
- Replace all \( w \)-dependent expressions with \( u \).
- Carry out the integration with the new variable.
Trigonometric Substitution
Trigonometric substitution is a technique used for integrating functions involving square roots, typically of the form \( \sqrt{a^2 - x^2} \), \( \sqrt{x^2 + a^2} \), or \( \sqrt{x^2 - a^2} \). It leverages trigonometric identities to simplify the integral.In our exercise, after substituting \( u = e^w \), we encountered an expression \( \int \frac{u^2}{\sqrt{1-u^2}} \, du \). To handle the square root, we apply trigonometric substitution by setting \( u = \sin(\theta) \). The substitution changes \( du = \cos(\theta) \, d\theta \) and \( \sqrt{1-u^2} = \cos(\theta) \).**Implementation Steps**
- Choose a trigonometric function that fits the expression in the square root.
- Use trigonometric identities to replace the expression, turning the integral into a trigonometric one.
- Perform the integration in terms of the trigonometric variable.
Integration Techniques
Integration techniques refer to various methods used to solve integrals, especially non-standard ones that cannot be solved by basic antiderivatives alone. In this case, our task was to evaluate \( \int \sin^2(\theta) \, d\theta \). This requires an identity called the power-reduction identity: \( \sin^2(\theta) = \frac{1 - \cos(2\theta)}{2} \). This transforms the integral into \( \frac{1}{2} \int (1 - \cos(2\theta)) \, d\theta \). The reduced expression can be integrated more straightforwardly, resulting in \( \frac{1}{2} \left[ \theta - \frac{1}{2}\sin(2\theta) \right] + C \).**Common Techniques**
- Substitution (both simple and trigonometric)
- Integration by parts
- Partial fraction decomposition