Chapter 8: Problem 36
Evaluate the integral. \(\int \tan ^{3} x \csc ^{2} x d x\)
Short Answer
Expert verified
\(\frac{1}{2}\tan^2 x + C\)
Step by step solution
01
Rewrite Trigonometric Functions
First, we recognize that \(\tan^3 x\csc^2 x\) can be rewritten using basic trigonometric identities. Recall \(\tan x = \frac{\sin x}{\cos x}\) and \(\csc x = \frac{1}{\sin x}\). Therefore, \(\csc^2 x = \frac{1}{\sin^2 x}\), and we have:\[\tan^3 x \csc^2 x = \left(\frac{\sin^3 x}{\cos^3 x}\right) \cdot \frac{1}{\sin^2 x} = \frac{\sin x}{\cos^3 x}\]Thus, the integral becomes \(\int \frac{\sin x}{\cos^3 x} \, dx\).
02
Simplify the Integrand
The expression \(\frac{\sin x}{\cos^3 x}\) can be simplified for integration purposes. We can rewrite this as:\[\int \frac{\sin x}{\cos^3 x} \, dx = \int \frac{\sin x}{\cos^2 x} \cdot \frac{1}{\cos x} \, dx = \int \tan x \sec^2 x \, dx\]This simplification highlights a potential substitution. Notice that \(\frac{d}{dx}(\tan x) = \sec^2 x\).
03
Use Substitution Method
Let \(u = \tan x\), which implies that \(du = \sec^2 x \, dx\). This substitution allows the integral to be rewritten in terms of \(u\):\[\int \tan x \sec^2 x \, dx = \int u \, du\]The integral \(\int u \, du\) is straightforward to solve.
04
Integrate with Respect to u
Now, integrate \(\int u \, du\):\[\int u \, du = \frac{1}{2}u^2 + C\]where \(C\) is the constant of integration.
05
Substitute Back for x
Finally, substitute back \(u = \tan x\) into the integrated result to express the solution in terms of \(x\):\[\frac{1}{2}u^2 + C = \frac{1}{2}(\tan x)^2 + C\]Thus, the evaluated integral is:\[\frac{1}{2}\tan^2 x + C\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Substitution
When faced with integral problems that involve trigonometric functions, **trigonometric substitution** can be a powerful tool. This technique is applied to simplify integrals by using a trigonometric identity or transformation. In our exercise, we used the identity for tangent and cosecant to rewrite the original integral. Since
- \( \tan x = \frac{\sin x}{\cos x} \)
- \( \csc x = \frac{1}{\sin x} \)
- \( \csc^2 x = \frac{1}{\sin^2 x} \)
Trigonometric Identities
Trigonometric identities are essential in simplifying the components within an integral, making them easier to evaluate. The identities help to express trigonometric functions in forms suitable for integration.
- The identity \( \tan x = \frac{\sin x}{\cos x} \) allows us to transform a tangent into a quotient of sine and cosine, which is useful for integration.
- Similarly, the identity \( \csc x = \frac{1}{\sin x} \) allows us to express cosecant in terms of sine, simplifying expressions further.
Substitution Method
The substitution method is a technique used to simplify the process of integration by changing variables. In our solution, once we simplified the integrand to \( \int \tan x \sec^2 x \, dx \), we noticed that the derivative of tangent is secant squared. This observation highlighted \( \tan x \) as a perfect candidate for substitution.
With \( u = \tan x \), and consequently \( du = \sec^2 x \, dx \), we transformed the integral into \( \int u \, du \). Integrating \( u \) with respect to \( u \) becomes straightforward—resulting in \( \frac{1}{2}u^2 + C \). This is much simpler than dealing with the original trigonometric expressions. After integrating, substituting back \( u = \tan x \) yields the final solution \( \frac{1}{2}\tan^2 x + C \).
With \( u = \tan x \), and consequently \( du = \sec^2 x \, dx \), we transformed the integral into \( \int u \, du \). Integrating \( u \) with respect to \( u \) becomes straightforward—resulting in \( \frac{1}{2}u^2 + C \). This is much simpler than dealing with the original trigonometric expressions. After integrating, substituting back \( u = \tan x \) yields the final solution \( \frac{1}{2}\tan^2 x + C \).
- This method reduces a complex problem into a simple, solvable task and is often used when we can directly equate a part of the integrand with the derivative of a function.
- The key is to spot the part of the integrand that resembles the derivative, making the substitution seamless and efficient.