/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Find an interval on which \(f\) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find an interval on which \(f\) has an inverse. (Hint: Find an interval on which \(f^{\prime}>0\) or on which \(f^{\prime}<0 .\) ) $$ f(x)=\cos x $$

Short Answer

Expert verified
\([0,\pi]\) is an interval where \(f(x)=\cos x\) has an inverse.

Step by step solution

01

Understanding the Function

The function given is \( f(x) = \cos x \), which is a periodic and oscillating function. The cosine function is not one-to-one on its entire domain \( (-\infty, \infty) \) because it repeats its values every \(2\pi\).
02

Determine the Derivative

The first step in identifying an interval where \( f \) is one-to-one is to find the derivative of \( f \). The derivative, \( f'(x) \), of \( f(x) = \cos x \) is \( f'(x) = -\sin x \). We need to find intervals where \( f'(x) > 0 \) (increasing) or \( f'(x) < 0 \) (decreasing) to ensure \( f \) is one-to-one.
03

Analyze the Sine Function

We have the derivative \( f'(x) = -\sin x \). In order for the function to be strictly increasing, we would need \( f'(x) > 0 \), which translates to \( -\sin x > 0 \) or \( \sin x < 0 \). Similarly, for \( f(x) \) to be decreasing, \( f'(x) < 0 \), so \( \sin x > 0 \).
04

Find Suitable Intervals

The sine function is positive on the intervals \( (0, \pi) \) and negative on \( (-\pi, 0) \). On the interval \( (0, \pi) \), \(-\sin x\) is negative, meaning \( f(x) = \cos x \) is decreasing. On \( (-\pi, 0) \), \(-\sin x\) is positive, meaning \( f(x) = \cos x \) is increasing. Thus, these intervals have no repeat values, making \( f \) invertible on \((0,\pi)\) and \((-\pi,0)\).
05

Choose an Interval for Inverse

Either \((0,\pi)\) or \((-\pi,0)\) can be selected as they both make \( f(x) \) strictly monotonic. Conventionally, \((0,\pi)\) is often chosen as the interval for which \( \cos x \) is decreasing, simplifying computation and application.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative
The concept of a derivative is pivotal in understanding how functions change. A derivative, often denoted as \( f'(x) \), gives us the rate at which the function \( f(x) \) changes with respect to \( x \). In simpler terms, it tells us the slope of the tangent line to the curve at any point.For the cosine function \( f(x) = \cos x \), its derivative is \( f'(x) = -\sin x \). This results because the derivative of \( \cos x \) is associated with the sine function, reflecting the periodic nature of trigonometric functions.
  • If \( f'(x) > 0 \), the function \( f(x) \) is increasing on that interval.
  • If \( f'(x) < 0 \), the function \( f(x) \) is decreasing on that interval.
Understanding derivatives helps determine where a function is increasing or decreasing, which is key to finding intervals where functions like cosine are invertible.
Cosine Function
The cosine function, represented as \( f(x) = \cos x \), is a fundamental trigonometric function that describes the horizontal coordinate of a unit circle as a point moves around it. It is periodic with a period of \(2\pi\), meaning it repeats itself every \(2\pi\) radians. This repeating nature makes the cosine function not one-to-one across its entire domain.However, to find an interval where \( \cos x \) is invertible, we look for segments where it is strictly increasing or decreasing. By examining its derivative, \(-\sin x\), we determine intervals:
  • \((0, \pi)\) - cosine is decreasing.
  • \((-\pi, 0)\) - cosine is increasing.
Choosing a specific interval like \((0, \pi)\), simplifies analysis and application, as it is a conventional approach due to its continuity and monotonicity.
Monotonicity
Monotonicity refers to functions consistently increasing or decreasing. For a function to be invertible, it must be monotonic on the chosen interval. In the context of trigonometric functions like the cosine, understanding monotonic behavior is essential.Given \( f(x) = \cos x \) and its derivative \( f'(x) = -\sin x \), we can determine monotonicity:
  • \(-\sin x > 0\) implies an increasing function, since \( \sin x < 0 \).
  • \(-\sin x < 0\) implies a decreasing function, since \( \sin x > 0 \).
The intervals \((0, \pi)\) and \((-\pi, 0)\) satisfy the condition for monotonicity, making the cosine function invertible. Understanding monotonicity is crucial for determining where a function like \( \cos x \) is one-to-one and hence has an inverse.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.