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Let \(f(x)=\cosh x\) for \(0 \leq x \leq \ln 2 .\) Find the length \(L\) of the graph of \(f\).

Short Answer

Expert verified
The length of the graph is \(\frac{3}{4}\).

Step by step solution

01

Understand the hyperbolic cosine function

The hyperbolic cosine function \(f(x) = \cosh(x)\) is given by the formula \(\cosh(x) = \frac{e^x + e^{-x}}{2}\). This is an even function and is similar in property to the traditional cosine function but differs as it is defined using exponential functions.
02

Set up the arc length formula

The arc length \(L\) of a function \(f(x)\) over the interval \([a, b]\) is given by the integral \(L = \int_a^b \sqrt{1 + \left(\frac{df}{dx}\right)^2} \, dx\). For this problem, \(a = 0\) and \(b = \ln 2\).
03

Differentiate \(f(x) = \cosh x\)

Calculate the derivative of the function \(f(x) = \cosh x\). We know \(\frac{d}{dx} \cosh x = \sinh x\), so \(\frac{df}{dx} = \sinh(x)\).
04

Substitute the derivative into the arc length formula

Substitute \(\frac{df}{dx} = \sinh x\) into the arc length formula: \(L = \int_0^{\ln 2} \sqrt{1 + \sinh^2(x)} \, dx\).
05

Use the hyperbolic identity

Recall the hyperbolic identity: \(\cosh^2(x) - \sinh^2(x) = 1\) hence \(1 + \sinh^2(x) = \cosh^2(x)\). Substitute this back into the integral to get \(L = \int_0^{\ln 2} \sqrt{\cosh^2(x)} \, dx\). Since \(x\) is positive, this simplifies to \(L = \int_0^{\ln 2} \cosh(x) \, dx\).
06

Solve the integral

The integral of \(\cosh(x)\) is \(\sinh(x)\). So, the arc length is calculated as \(L = \left[ \sinh(x) \right]_0^{\ln 2}\).
07

Compute the definite integral

Evaluate the definite integral: \(L = \sinh(\ln 2) - \sinh(0)\). We know \(\sinh(0) = 0\) and \(\sinh(\ln 2) = \frac{e^{\ln 2} - e^{-\ln 2}}{2} = \frac{2 - \frac{1}{2}}{2} = \frac{3}{4}\).
08

Conclusion

Thus, the length of the graph of \(f(x) = \cosh x\) from \(x = 0\) to \(x = \ln 2\) is \(\frac{3}{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hyperbolic Functions
Hyperbolic functions are analogs of trigonometric functions that arise naturally in the study of hyperbolas, just as trigonometric functions relate to circles. The two primary hyperbolic functions are hyperbolic sine, denoted as \(\sinh x\), and hyperbolic cosine, denoted as \(\cosh x\). Hyperbolic cosine, \(\cosh x\), is defined by the equation \(\cosh x = \frac{e^x + e^{-x}}{2}\). It is an even function, meaning \(\cosh(-x) = \cosh(x)\). Like the trigonometric cosine, the hyperbolic cosine is also related to a Pythagorean identity: \(\cosh^2(x) - \sinh^2(x) = 1\).
These functions are essential in various branches of mathematics and physics, such as in the study of catenary shapes and in the solutions of hyperbolic partial differential equations, which model wave-like phenomena.
  • Defines hyperbolic cosine using exponential functions
  • Has similarities with trigonometric cosine but forms a Pythagorean identity with hyperbolic sine
  • Vital in modeling natural phenomena and in complex analysis
Derivative of Hyperbolic Functions
Differentiating hyperbolic functions is crucial to understanding how they change with respect to variables, much like derivatives of traditional trigonometric functions. The derivative of the hyperbolic cosine function \(\cosh x\) is the hyperbolic sine function \(\sinh x\). Mathematically, this is expressed as \(\frac{d}{dx} \cosh x = \sinh x\).
The relationship between \(\cosh x\) and \(\sinh x\) mirrors that of regular cosine and sine functions, yet they belong to the realm of hyperbolic geometry. The derivative tells us that as \(x\) increases, the rate of change of \(\cosh x\) follows the hyperbolic sine function. Knowing derivatives allows us to perform calculations like determining the slope of a curve at a given point, making it significant for the arc length calculation of curves.
  • \(\cosh x\)'s derivative: \(\sinh x\)
  • Shows rate of change of the function
  • Essential for calculating the arc length and other calculus operations
Definite Integrals in Calculus
Definite integrals are a fundamental concept in calculus used to find the signed area under a curve over a specific interval. In the context of arc length calculation, the integral helps us determine the length of the curve of a function over a set interval. The integral form used for arc length of a function \(f(x)\) is:
\[ L = \int_a^b \sqrt{1 + \left(\frac{df}{dx}\right)^2} \, dx \]
Here, \(a\) and \(b\) are the bounds of the interval, and \(\frac{df}{dx}\) is the derivative of the function. For the hyperbolic cosine function \(\cosh x\), we utilize its derivative \(\sinh x\). Through identities such as \(1 + \sinh^2(x) = \cosh^2(x)\), the integral simplifies, allowing us to evaluate the arc length efficiently.
Definite integrals not only compute areas but are widely used in various calculations across mathematics and physics, such as volumes, averages, and total accumulated change.
  • Integral for arc length depends on the derivative
  • Uses definite bounds to compute precise measurements
  • Key for a wide range of applications beyond geometry

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Most popular questions from this chapter

The rated speed \(v_{R}\) of a banked curve on a road is the maximum speed a car can attain on the curve without skidding outward, under the assumption that there is no friction between the road and the tires (under icy road conditions, for example). The rated speed is given by $$ v^{2}=\rho g \tan \theta $$ where \(g=9.8\) (meters per second per second) is the acceleration due to gravity, \(\rho\) is the radius of curvature of the curve, and \(\theta\) is the banking angle (Figure 7.34). a. Express the angle \(\theta\) in terms of \(v, \rho\), and \(g\). b. If a curve is to have a rated speed of 18 meters per second (approximately \(40 \mathrm{mph}\) ) and a radius of curvature of 60 meters, at what angle should it be banked? c. Suppose the radius of curvature is a constant 100 meters, but that the banking angle is variable. Suppose also that a professional stunt driver rounds the curve, accelerating or decelerating as necessary to keep the car at the maximum safe speed. If at a certain instant the driver's speed is 18 meters per second and is decreasing at the rate of 1 meter per second, how fast is the banking angle changing at that instant?

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