Chapter 7: Problem 24
a. Write down a differential equation that has no solution. b. Write down a differential equation that has exactly one solution.
Short Answer
Expert verified
For (a): \( y' = y^2, \) \( y(0) = -1;\) no solution. For (b): \( y' = -2y, \) \( y(0) = 3;\) one solution.
Step by step solution
01
Understanding a Differential Equation with No Solution
To write a differential equation with no solution, consider an inherently inconsistent equation. A common example in differential equations is trying to specify an impossible initial condition for a given type of differential equation.
02
Example of a Differential Equation with No Solution
An example of such an equation is the initial value problem: \( y' = y^2, \) with the initial condition \( y(0) = -1. \) Since \( y^2 \) is always non-negative, \( y' = y^2 \) implies a non-negative velocity; therefore, it cannot lead to a negative solution.
03
Understanding a Differential Equation with Exactly One Solution
For a differential equation to have a unique solution, it typically needs to satisfy certain conditions like the Lipschitz condition in a given interval. This ensures the well-posedness and uniqueness of the solution.
04
Example of a Differential Equation with Exactly One Solution
Consider the initial value problem: \( y' = -2y, \) with the initial condition \( y(0) = 3. \) This is a linear first-order differential equation. According to the theory of linear differential equations, such an equation with a specified initial condition has exactly one solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Initial Value Problem
An initial value problem in differential equations is a problem where we seek a solution to a differential equation that satisfies a specific condition at the start, known as the initial condition. To understand it better:
- It consists of a differential equation itself, like \( y' = y^2 \).
- Additionally, it has an initial condition, such as \( y(0) = -1 \).
Unique Solution
Having a unique solution means that exactly one function satisfies both the differential equation and the initial condition within a particular interval. Not all differential equations with initial conditions yield unique solutions. We can identify some key aspects:
- The differential equation needs to be well-posed. This means that, in addition to having a solution, it should be sensibly solvable under small variations in initial conditions.
- The initial value problem \( y' = -2y \) with \( y(0) = 3 \) is a typical case where there's a unique solution. Its uniqueness is assured by satisfying the conditions required for the existence and uniqueness theorem.
Lipschitz Condition
The Lipschitz condition is a mathematical criterion used to guarantee the uniqueness of solutions to differential equations. It states that a function must not change too rapidly, or in more technical terms, differ by more than a constant proportional to the change in its inputs. Here are some insights:
- If a function \( f(x, y) \) satisfies the Lipschitz condition, it will generally ensure the uniqueness of the solution to the differential equation \( y' = f(x, y) \).
- This condition can be checked by finding if there exists a constant \( L \) such that for any two points \( y_1 \) and \( y_2 \), \( |f(x, y_1) - f(x, y_2)| \leq L |y_1 - y_2| \).
- For example, in the differential equation \( y' = -2y \), the function is linear and satisfies the Lipschitz condition, hence ensures one unique solution for the initial condition given.