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Find the numerical value of the expression. \(\operatorname{csch}\left(\ln \pi^{2}\right)\)

Short Answer

Expert verified
The numerical value is \( \frac{2\pi^2}{\pi^4 - 1} \).

Step by step solution

01

Understand the Problem

We need to evaluate the hyperbolic cosecant function, denoted as \( \operatorname{csch}(x) \). The argument provided is \( \ln \pi^{2} \).
02

Recall the Definition of Hyperbolic Cosecant

The hyperbolic cosecant of \( x \) is defined as \( \operatorname{csch}(x) = \frac{1}{\sinh(x)} \), where \( \sinh(x) = \frac{e^x - e^{-x}}{2} \).
03

Simplify the Argument \( \ln \pi^{2} \)

Compute the natural logarithm of \( \pi^2 \):\[ \ln \pi^{2} = 2 \ln \pi \]This means the argument of the \( \operatorname{csch} \) function is \( 2 \ln \pi \).
04

Calculate \( \sinh(2 \ln \pi) \)

Use the definition of the hyperbolic sine to find:\[ \sinh(2 \ln \pi) = \frac{e^{2 \ln \pi} - e^{-2 \ln \pi}}{2} \]Since \( e^{2 \ln \pi} = (e^{\ln \pi})^2 = \pi^2 \), we have:\[ \sinh(2 \ln \pi) = \frac{\pi^2 - \frac{1}{\pi^2}}{2} \]
05

Compute \( \operatorname{csch}(2 \ln \pi) \)

By definition, \( \operatorname{csch}(2 \ln \pi) = \frac{1}{\sinh(2 \ln \pi)} \).Insert the expression from Step 4:\[ \operatorname{csch}(2 \ln \pi) = \frac{2}{\pi^2 - \frac{1}{\pi^2}} \]
06

Simplify the Expression

Simplify \( \frac{2}{\pi^2 - \frac{1}{\pi^2}} \) by finding a common denominator:\[ \operatorname{csch}(2 \ln \pi) = \frac{2\pi^2}{\pi^4 - 1} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

hyperbolic cosecant
The hyperbolic cosecant function is a lesser-known yet important hyperbolic function. Understanding this function is crucial, as it often appears in various mathematical contexts.
In simple terms, the hyperbolic cosecant (\( \operatorname{csch}(x) \)) is the reciprocal of the hyperbolic sine (\( \sinh(x) \)). This means:
  • \( \operatorname{csch}(x) = \frac{1}{\sinh(x)} \)
Where the hyperbolic sine function \( \sinh(x) \) is defined using exponential functions: \( \sinh(x) = \frac{e^x - e^{-x}}{2} \).
Just like other hyperbolic functions, hyperbolic cosecant is not most people’s first encounter amongst mathematical concepts. Yet, it is just as important as its counterparts such as sine and cosine.
This function helps to express calculations involving hyperbolic angles and can be used in disciplines like engineering and physics for solving complex equations.
natural logarithm
The natural logarithm is a special and useful type of logarithm. Among its many features, its unique characteristic is its base, which is the irrational number \( e \)\, approximately equal to 2.71828.
The natural logarithm, often denoted as \( \ln(x) \), gives us the power to which \( e \) must be raised to obtain the number \( x \).\ For example, \( \ln(e) = 1 \)\ because \( e^1 = e \).\ In our exercise, we simplified \( \ln \pi^{2} \) as \( 2 \ln \pi \). This is because of the logarithmic identity: \( \ln (a^b) = b \ln a \).\ This identity is very handy for breaking down complex logarithmic expressions into simpler parts.
Understanding natural logarithms is crucial across many fields: from sciences and engineering to computer science and statistics. It aids in solving exponential growth problems and measuring time needed for growth or decay of phenomena.
exponential functions
Exponential functions are a core aspect of mathematics that describe processes with continuous growth or decay. These functions have the form \( f(x) = a \cdot e^{bx} \), where \( e \)\ is the base of the natural logarithm. The exponential function \( e^x \) is especially significant because it is its own derivative and integral.
These functions are crucial for defining further mathematical functions like hyperbolic functions, integrating the understanding of growth processes, or solving complex differential equations. In the context of our exercise, the exponential function is instrumental in expressing hyperbolic functions as it forms the basis of defining \( \sinh(x) \). For example, \( \sinh(x) \) can be written as:
  • \( \sinh(x) = \frac{e^x - e^{-x}}{2} \)
This highlights the core functionality of exponential functions in building more complex mathematical expressions and converting them into manageable forms.
From financial models predicting stock growth to physics explaining radioactive decay, exponential functions find use in explaining real-world phenomena. Their applications are endless in various scientific and analytic fields.

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Most popular questions from this chapter

Let the path \(C\) of a particle in motion be given parametrically by \(x=f(t) \quad\) and \(\quad y=g(t) \quad\) for all \(t\) where \(f^{\prime}(t)=2 f(t)\) and \(g^{\prime}(t)=6 g(t)\) for all \(t\). a. Solve the equations for \(f\) and \(g\), and then write \(y\) as a function of \(x\). b. Suppose \(f(0)=2\) and \(g(0)=3\). Determine the curve \(C\), and sketch it.

Let \(f(x)=1 / \sqrt{1+x^{2}}\). Find the center of gravity of the region between the graph of \(f\) and the \(x\) axis on \([0,1]\).

Use l'Hôpital's Rule to find the limit. $$ \lim _{x \rightarrow \infty} \frac{1}{x\left(\pi / 2-\tan ^{-1} x\right)} $$

Let \(f(x)=\tan ^{-1}\left(\frac{x+1}{x-1}\right)\). a. Show that \(f^{\prime}(x)=\frac{-1}{x^{2}+1}\) for \(x \neq 1\). b. Find a formula for \(f^{\prime \prime}\). c. Show that \(\lim _{x \rightarrow 1^{+}} f(x)=\pi / 2\) and \(\lim _{x \rightarrow 1^{-}} f(x)=-\pi / 2\). d. Sketch the graph of \(f\). e. Show that there is no constant \(C\) such that \(f(x)=\) \(-\tan ^{-1} x+C\) for all \(x \neq 1\), although the functions \(f\) and \(-\tan ^{-1} x\) have the same derivative when \(x \neq 1\) f. Find constants \(C_{1}\) and \(C_{2}\) such that $$ \begin{aligned} &f(x)=-\tan ^{-1} x+C_{1} \quad \text { for } x<1 \\ &f(x)=-\tan ^{-1} x+C_{2} \quad \text { for } x>1 \end{aligned} $$

Let $$ f(v)=\frac{m_{0}}{\sqrt{1-v^{2} / c^{2}}} \text { for } v \geq 0 $$ and $$ g(m)=c \sqrt{1-m_{0}^{2} / m^{2}} \quad \text { for } m \geq m_{0} $$ where \(m_{0}\) and \(c\) are constants. Show that \(g\) is the inverse of \(f\). (The functions \(f\) and \(g\) arise in the theory of relativity. If \(c\) is the speed of light in a vacuum and \(m_{0}\) is the rest mass of a particle, then \(f(v)\) is the mass of the particle as it moves with velocity \(v\), and \(g(m)\) is the velocity of the particle when it has mass \(m\).)

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