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Suppose the current \(I(t)\) flowing in an electrical circuit at time \(t\) is given by $$ I(t)=\frac{100}{1+t^{2}}+3 \sin \frac{30 t}{\pi} \text { for } t \geq 0 $$ Show that $$ \lim _{t \rightarrow \infty}\left(I(t)-3 \sin \frac{30 t}{\pi}\right)=0 $$ Thus for large values of \(t, I(t)\) is very nearly equal to \(3 \sin (30 t / \pi)\). The expression \(3 \sin (30 t / \pi)\) is called the steady-state current, and the expression \(100 /\left(1+t^{2}\right)\) is the transient current (since it is significant only for small values of \(t\) ).

Short Answer

Expert verified
\( \lim_{t \to \infty} (I(t) - 3 \sin \frac{30 t}{\pi}) = 0 \), so \( I(t) \approx 3 \sin \frac{30 t}{\pi} \) for large \( t \).

Step by step solution

01

Identify Components of Current Function

Given the function for current is \( I(t) = \frac{100}{1+t^2} + 3 \sin \frac{30 t}{\pi} \). It consists of a transient component \( \frac{100}{1 + t^2} \) and a steady-state component \( 3 \sin \frac{30 t}{\pi} \).
02

Understand the Limit

The problem asks us to show that \( \lim_{t \to \infty} \left( I(t) - 3 \sin \frac{30 t}{\pi} \right) = 0 \). This implies that as \( t \to \infty \), the contribution from the transient component becomes negligible.
03

Simplify the Expression

Simplify the expression by isolating the transient component: \( I(t) - 3 \sin \frac{30 t}{\pi} = \frac{100}{1 + t^2} \). This expression needs to evaluate to zero as \( t \to \infty \).
04

Calculate the Limit of Transient Component

Evaluate \( \lim_{t \to \infty} \frac{100}{1 + t^2} \). As \( t \to \infty \), the denominator \( 1 + t^2 \) grows infinitely large, causing the fraction to tend towards zero.
05

Conclusion on Limit

Since \( \lim_{t \to \infty} \frac{100}{1 + t^2} = 0 \), we conclude that \( \lim_{t \to \infty} \left( I(t) - 3 \sin \frac{30 t}{\pi} \right) = 0 \). This confirms that for large values of \( t \), the current \( I(t) \) is approximately equal to the steady-state component \( 3 \sin \frac{30 t}{\pi} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transient Current
Transient current in an electrical circuit refers to the component of the current that is only significant for a short period after a change in the circuit occurs. In the given current function, the transient component is represented by \( \frac{100}{1+t^2} \). This part of the current decreases quickly over time, as its influence diminishes as time progresses.
As \( t \) increases, the denominator \( 1 + t^2 \) becomes very large, leading to the entire fraction approaching zero. Thus, the transient current has a fleeting nature, being notable only when \( t \) is small.
This characteristic is why transient currents are often the focus of early-time behavior analysis in circuits, where sudden changes, such as those from a switch opening or closing, temporarily affect the overall current. Over time, however, these effects fade away, emphasizing the steady-state behavior of the circuit.
Limit as t approaches infinity
Understanding the limit as \( t \to \infty \) is crucial for determining the long-term behavior of the circuit's current. In the given problem, evaluating \( \lim_{t \to \infty} \left( I(t) - 3 \sin \frac{30 t}{\pi} \right) = 0 \) helps us recognize which components of the current persist over time.
In this expression, we isolate the transient part \( \frac{100}{1+t^2} \) from the steady-state component \( 3 \sin \frac{30 t}{\pi} \).
  • The calculation simplifies by focusing on \( \lim_{t \to \infty} \frac{100}{1+t^2} \), which equals zero.
This demonstrates that over time, the transient current's influence vanishes, and the current primarily reflects the steady-state component.
Seeing limits in action helps students grasp how circuits stabilize over time, highlighting which effects are temporary and which are enduring.
Electrical Circuit Analysis
Electrical circuit analysis involves understanding the different components of a circuit and how they influence its behavior over time. In this exercise, we have dissected a function representing the current \( I(t) \) in a circuit.
The main components at play are transient and steady-state currents, which require analyzing how they affect the circuit at different time scales.
  • Transient currents reveal initial responses to changes, important for short-term analysis.
  • Steady-state currents indicate long-term behaviors, providing insights into the sustained functioning of the circuit.
By applying circuit analysis, students can predict how real-world circuits will function under various conditions. This problem shows the importance of separating these components to study their individual as well as combined effects.
Such analytical skills are foundational for electrical engineers, enabling them to design and troubleshoot circuits effectively by understanding both immediate alterations and stable states.

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Most popular questions from this chapter

Suppose an object is released and moves through a viscous fluid that tends to resist the motion of the object. Then the velocity \(v\) increases with time, and may approach a terminal velocity \(v_{T}\), which depends on the mass of the object and the viscosity of the fluid. If the fluid's resistance is proportional to the object's velocity, then as a function of time \(t\) the velocity is given by $$ v=v_{T}\left(1-e^{-g t / v_{T}}\right) $$ where \(g=9.8\) (meters per second per second) is the acceleration due to gravity. a. Find \(\lim _{t \rightarrow \infty} v(t)\). b. If the object is a tiny fog droplet (which is frequently on the order of \(5 \times 10^{-6}\) meters in radius), and is falling in the sky near earth, then a reasonable value for the terminal velocity is \(2.7 \times 10^{-2}\) meters per second (which is equivalent to 1 meter every 37 seconds). If the fog droplet begins falling at time \(t=0\), determine how long it takes for the velocity of the droplet to reach half of the terminal velocity.

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