Chapter 2: Problem 32
a. Plot the graph of \(\ln x\) on the interval \((0.5,1.5)\). Does the graph suggest that \(\lim _{x \rightarrow 1} \ln x=0\) ? b. Using the formula $$ \ln x=\ln \frac{x}{a}+\ln a $$ along with the limit in part (a) and the Substitution Rule, prove that $$ \lim _{x \rightarrow a} \ln x=\ln a \quad \text { for } a>0 $$ that is, prove that \(\ln x\) is a continuous function.
Short Answer
Step by step solution
Understanding the Plot of \( \ln x \)
Analyzing the Limit Expression
Apply the Substitution Rule
Proof of Continuity
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Natural Logarithm
For example, the natural logarithm has the property that \( \ln(ab) = \ln a + \ln b \). This attribute makes it useful for simplifying complex multiplications into manageable additions. On the graph of the natural logarithm, you will notice that as \( x \) increases, \( \ln x \) also increases, albeit at a decreasing rate. This is why its graph has a concave shape.
When plotting the graph of \( \ln x \) over an interval like \((0.5,1.5)\), you will observe that the curve crosses the x-axis at \( x=1 \) since \( \ln 1 = 0 \). This point is used in many problems where the continuity and limits of the natural logarithm are examined.
Limit of a Function
For the natural logarithm function \( \ln x \), the limit \( \lim_{x \rightarrow a} \ln x = \ln a \) for a positive \( a \) signifies that as \( x \) gets closer to \( a \), the value of \( \ln x \) gets closer to \( \ln a \).
This concept is critical when proving that \( \ln x \) is continuous at specific points. For example, using the graph and properties of logarithms, we observe that near \( x=1 \), \( \ln x \) approaches 0, confirming \( \lim_{x \rightarrow 1} \ln x = 0 \). This aligns with the graphical properties and confirms the function's continuity, since small changes in \( x \) around \( a \) result in expected small changes in \( \ln x \).
Properties of Logarithms
Some useful properties include:
- Product Property: \( \ln(ab) = \ln a + \ln b \)
- Quotient Property: \( \ln\frac{a}{b} = \ln a - \ln b \)
- Power Property: \( \ln(a^b) = b \ln a \)
These transformations play a substantial role in calculus, particularly in evaluating limits and solving integrals related to logarithmic functions.
Substitution Rule
In the context of proving \( \lim _{x \rightarrow a} \ln x = \ln a \), the substitution \( x = a + h \), where \( h \) approaches 0, is beneficial. This approach simplifies the limit by setting \( \frac{x}{a} = 1 + \frac{h}{a} \), turning the problem into evaluating \( \ln(1 + \frac{h}{a}) \) as \( h \to 0 \).
This setup reveals a simple limit: as \( h \) approaches 0, \( \ln(1 + \frac{h}{a}) \) approaches \( \ln 1 = 0 \). Hence, the whole expression tends towards \( \ln a \), proving the desired continuity of the natural logarithm.
Utilizing the substitution rule to convert complex expressions into simpler equivalents is a powerful tool, facilitating our understanding and computations in calculus and demonstrating continuity and other properties of functions.