Chapter 2: Problem 29
Let \(a, b\), and \(m\) be any real numbers. Show that $$ \lim _{x \rightarrow a}(m x+b)=m a+b $$
Short Answer
Expert verified
The limit of \( mx + b \) as \( x \to a \) is \( ma + b \).
Step by step solution
01
Understand the Problem
We need to find the limit of the linear function \( f(x) = mx + b \) as \( x \) approaches \( a \). We aim to show that the limit equals \( ma + b \).
02
Recall the Limit Definition
The limit \( \lim_{x \to a} f(x) = L \) means that for every epsilon \( \varepsilon > 0 \), there exists a delta \( \delta > 0 \) such that if \( 0 < |x-a| < \delta \), then \( |f(x) - L| < \varepsilon \). Our goal is to show this definition holds true for \( L = ma + b \).
03
Substitute the Linear Function
Substitute \( f(x) = mx + b \) into the limit condition. We need to show that \( |mx + b - (ma + b)| < \varepsilon \) as \( x \) approaches \( a \).
04
Simplify the Expression
Simplify the expression \( |mx + b - (ma + b)| \) to obtain \( |m(x - a)| \). This simplification reduces the problem to finding a condition on \( x \).
05
Apply the Limit Condition
We require that \( |m(x-a)| < \varepsilon \). This can be rewritten as \( |x-a| < \frac{\varepsilon}{|m|} \), assuming \( m eq 0 \).
06
Determine Delta
Choose \( \delta = \frac{\varepsilon}{|m|} \). Thus, for all \( x \) such that \( 0 < |x-a| < \delta \), the condition \( |mx + b - (ma + b)| < \varepsilon \) is satisfied.
07
Special Case for \( m = 0 \)
If \( m = 0 \), then \( f(x) = b \) is constant, and hence \( \lim_{x \to a} f(x) = b \) for any real number \( a \), satisfying \( ma + b = b \).
08
Conclusion
Since both cases (\( m eq 0 \) and \( m = 0 \)) meet the limit definition, the limit \( \lim_{x \to a} (mx + b) = ma + b \) holds true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Epsilon-Delta Definition
The epsilon-delta definition is a formal definition used to rigorously describe the concept of limits in calculus. It's a bit like a guarantee that, as we get closer and closer to a point, the function value also gets closer to a particular number. This is crucial for proving limits, especially in more abstract scenarios. Here's how it works:
Imagine you want the function value, let's call it \( f(x) \), to get within a certain distance, \( \varepsilon \), from a limit \( L \). You can always find a range around the point \( x = a \), known as \( \delta \), where this proximity maintains. Specifically:
Imagine you want the function value, let's call it \( f(x) \), to get within a certain distance, \( \varepsilon \), from a limit \( L \). You can always find a range around the point \( x = a \), known as \( \delta \), where this proximity maintains. Specifically:
- For a given \( \varepsilon > 0 \), there exists a \( \delta > 0 \) such that when \( 0 < |x - a| < \delta \), then \( |f(x) - L| < \varepsilon \).
- This ensures the output of the function stays within the given tolerance \( \varepsilon \) of the limit \( L \) whenever \( x \) is sufficiently close (within \( \delta \)).
Linear Function
A linear function is one of the simplest types of functions you'll encounter in calculus. It is characterized by having a constant rate of change, which makes it predictable and easy to work with. Graphically, linear functions appear as straight lines, defined by the equation \( f(x) = mx + b \). Let's break down the components:
- The parameter \( m \) is known as the slope. It dictates how steep the line is. A positive \( m \) means the line rises as \( x \) increases, while a negative \( m \) means it falls.
- The parameter \( b \) is the y-intercept. This is the point where the line crosses the y-axis, indicating the value of \( f(x) \) when \( x \) is zero.
Limits in Calculus
Limits are a foundational concept in calculus, describing how functions behave as inputs approach a certain value. They help us understand function behavior around points that might not be explicitly defined, and they are crucial for more advanced topics like derivatives and integrals.
A limit considers what a function appears to be heading towards as the input gets closer to some value. In the exercise, we're using limits to predict that the linear function \( f(x) = mx + b \) should approach \( ma + b \) as \( x \) approaches any real number \( a \). Here's why limits matter:
A limit considers what a function appears to be heading towards as the input gets closer to some value. In the exercise, we're using limits to predict that the linear function \( f(x) = mx + b \) should approach \( ma + b \) as \( x \) approaches any real number \( a \). Here's why limits matter:
- They offer insight into function behavior even where direct computation might be cumbersome.
- Limits allow us to handle infinite processes or abrupt changes in functions.
- They build the foundation for defining continuity, which is the idea that a function has no breaks or jumps.