Chapter 14: Problem 13
Find a parametrization for the surface of revolution \(\Sigma\). \(\Sigma\) is obtained by revolving about the \(z\) axis the graph of \(x=e^{z}\) for \(0 \leq z \leq 1\)
Short Answer
Expert verified
The parametrization is \((e^z \cos(\theta), e^z \sin(\theta), z)\) where \(0 \leq z \leq 1\) and \(0 \leq \theta < 2\pi\).
Step by step solution
01
Identify the Graph's Components
The graph involved in the surface of revolution is given by the equation \(x = e^z\) where \(0 \leq z \leq 1\). The graph is being revolved around the \(z\)-axis.
02
Set up Polar Coordinates for Revolution
To find a parametric representation of the surface, introduce a parameter \(\theta\) to describe the angle of revolution around the \(z\)-axis. Here, \(x = r\cos(\theta)\) and \(y = r\sin(\theta)\) for the radius \(r\). Since the graph revolves around the \(z\)-axis, the radius of revolution is \(r = e^z\).
03
Express x, y, and z in Parametric Form
The parameters \(z\) and \(\theta\) will determine the coordinates \((x, y, z)\) on the surface. Since \(r = e^z\), express \(x\) and \(y\) using polar coordinates: \(\begin{align*}x &= e^z \cos(\theta), \y &= e^z \sin(\theta), \z &= z.\end{align*}\)The parameters \(z\) and \(\theta\) vary over the ranges \(0 \leq z \leq 1\) and \(0 \leq \theta < 2\pi\).
04
Verify the Parametrization
Check that this parametrization satisfies the original surface equation and the given conditions. For \(0 \leq z \leq 1\), \((x, y, z) = (e^z \cos(\theta), e^z \sin(\theta), z)\) correctly represents the surface generated by revolving \(x = e^z\) around the \(z\)-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a powerful tool in mathematics for describing curves, surfaces, and more. Rather than expressing relationships using standard Cartesian coordinates, parametric equations introduce one or more parameters to define a set of equations. In the context of surfaces of revolution, parametrics are used to describe how a surface behaves as it revolves around an axis. When manipulating these equations, each parameter plays a specific role:
- The parameter \( z \) represents the height along the \( z \)-axis, which is the axis of revolution in this exercise.
- Another parameter, usually an angular measure, like \( \theta \), indicates the amount of rotation around the axis. In our example, \( \theta \) ranges from \( 0 \) to \( 2\pi \), enabling a full revolution.
Polar Coordinates
Polar coordinates offer an alternative to Cartesian coordinates, particularly useful for circular or rotational systems. They define a point based on its distance from a fixed central point (the pole) and the angle from a reference direction. Understanding these basics of polar systems is crucial when dealing with surfaces of revolution like this one:
- The radial coordinate \( r \) signifies the distance from the axis of revolution, which is derived from the original function \( r = e^z \).
- The angular coordinate \( \theta \) expresses the angle of revolution about the \( z \)-axis, reflecting full rotation over \( 0 \leq \theta < 2\pi \).
Graph Revolving
The concept of graph revolving involves rotating a graph about an axis to form a three-dimensional surface. In this exercise, you've revolved the graph of the function \( x = e^z \) about the \( z \)-axis. To visualize graph revolving:
- Imagine the line \( x = e^z \) extending vertically as \( z \) increases. As \( z \) moves from 0 to 1, the graph forms a curve in the \( xz \)-plane.
- When this curve revolves around the \( z \)-axis, it sweeps through the surrounding 3D space, creating a surface.
- This surface is represented through the parametrization that incorporates both the function definition (\( e^z \)) and a rotational parameter (\( \theta \)).