Chapter 13: Problem 46
Sketch the quadric surface. \(y=1-x^{2}\)
Short Answer
Expert verified
It's a downward-opening parabola with vertex at (0,1).
Step by step solution
01
Identify the Surface Type
The given equation is \( y = 1 - x^2 \). This equation is in two variables, \( x \) and \( y \), and represents a parabola because it contains an \( x^2 \) term and no \( z \) variable.
02
Determine the Axis
The equation \( y = 1 - x^2 \) is of the form \( y = a - bx^2 \), indicating that it is a parabola opening along the \( y \)-axis. The \( y \)-variable is not squared, while \( x \) is square, confirming its orientation along the \( y \)-axis.
03
Identify the Vertex
The vertex of the parabola is at the point where the equation reaches its maximum or minimum value. The term \( -x^2 \) shows it is a downward-opening parabola. Thus, the vertex is at the highest point, which is \((0, 1)\).
04
Sketch the Graph
Plot the parabola on the \( xy \)-plane. The vertex is at \((0, 1)\) on the graph. As \( x \) increases or decreases, \( y \) decreases, since \( y = 1 - x^2 \). Sketch a U-shaped curve opening downwards centering at \( (0, 1) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parabola
A parabola is a specific type of curve that you often see in algebra and geometry. It is defined by a quadratic equation that primarily includes a variable squared. In simple terms, it's the shape you get when you plot an equation with an \(x^2\) term on a coordinate plane. Parabolas have a distinct U-shape, which can either open upwards or downwards. The direction depends on the sign of the \(x^2\) term:
The simplistic beauty of parabolas lies in their symmetry - a mirrored image about their axis, which in this case, is a line parallel to the y-axis.
- If the term is positive, the parabola opens upwards.
- If the term is negative, the parabola opens downwards.
The simplistic beauty of parabolas lies in their symmetry - a mirrored image about their axis, which in this case, is a line parallel to the y-axis.
Graph Sketching
Graph sketching is a helpful skill that allows you to visualize mathematical equations on a plane. The case with \(y = 1 - x^2\) involves sketching a parabola. When you start graph sketching, begin by determining the key features of the equation:
- Identify if the parabola opens upwards or downwards.
- Find the vertex, which represents the top or bottom of the U-shape.
- Plot some additional points on each side of the vertex to ensure the curve is accurate and symmetric.
Vertex Identification
The vertex is a crucial part of any parabola, acting as its highest or lowest point. To accurately identify the vertex in a parabola equation like \(y = 1 - x^2\), you generally look at the format to find the coordinates:
- The standard form \(y = a(x-h)^2 + k\) shows the vertex at \((h, k)\).
- For our equation, the vertex occurs when \(x = 0\), since there is no \(h\) to shift it right or left, and thus the highest point is when \(y = 1\), making the vertex \((0, 1)\).