Chapter 12: Problem 42
Let \(\mathbf{F}, \mathbf{G}\), and \(\mathbf{H}\) be differentiable. Using the differentiation rules for the dot and cross products of vector-valued functions, verify that $$ \begin{aligned} \frac{d}{d t}[\mathbf{F} \cdot(\mathbf{G} \times \mathbf{H})] &=\frac{d \mathbf{F}}{d t} \cdot(\mathbf{G} \times \mathbf{H})+\mathbf{F} \cdot\left(\frac{d \mathbf{G}}{d t} \times \mathbf{H}\right) \\ &+\mathbf{F} \cdot\left(\mathbf{G} \times \frac{d \mathbf{H}}{d t}\right) \end{aligned} $$
Short Answer
Step by step solution
Recognize the Derivative
Apply Cross Product Derivative
Use Product Rule for Dot Product
Plug In the Derivatives
Distribute Terms and Conclude
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation Rules
- Product Rule for Dot Products: This rule states that the derivative of a dot product between two vector functions is the derivative of the first vector dotted with the second vector plus the first vector dotted with the derivative of the second vector.
- Product Rule for Cross Products: The cross product rule is similar. It says that the derivative of a cross product is the first vector differentiated and crossed with the second vector plus the first vector crossed with the derivative of the second vector.
Dot Product
- Commutativity: \( \mathbf{A} \cdot \mathbf{B} = \mathbf{B} \cdot \mathbf{A} \)
- Distributivity: \( \mathbf{A} \cdot (\mathbf{B} + \mathbf{C}) = \mathbf{A} \cdot \mathbf{B} + \mathbf{A} \cdot \mathbf{C} \)
- Zero Product Property: If \( \mathbf{A} \cdot \mathbf{B} = 0 \) and neither vector is the zero vector, \( \mathbf{A} \) and \( \mathbf{B} \) are orthogonal.
Cross Product
- Anti-commutativity: \( \mathbf{A} \times \mathbf{B} = - (\mathbf{B} \times \mathbf{A}) \)
- Distributivity: \( \mathbf{A} \times (\mathbf{B} + \mathbf{C}) = \mathbf{A} \times \mathbf{B} + \mathbf{A} \times \mathbf{C} \)
- The magnitude is equal to the area of the parallelogram they form: \( ||\mathbf{A} \times \mathbf{B}|| = ||\mathbf{A}|| ||\mathbf{B}|| sin(\theta) \)