Chapter 12: Problem 26
Sketch the curve traced out by the vectorvalued function. Indicate the direction in which the curve is traced out. $$ \mathbf{F}(t)=\sqrt{2} \cos t \mathbf{i}-2 \sin t \mathbf{j}+\sqrt{2} \cos t \mathbf{k} $$
Short Answer
Expert verified
The curve is an elliptical cylinder along the line \( x = z \), traced counter-clockwise in the \( xy \)-plane.
Step by step solution
01
Analyze the Components of \( \mathbf{F}(t) \)
The vector-valued function is given by \( \mathbf{F}(t) = \sqrt{2} \cos t \mathbf{i} - 2 \sin t \mathbf{j} + \sqrt{2} \cos t \mathbf{k} \). Notice that the \( x \) and \( y \) components are \( x = \sqrt{2} \cos t \) and \( y = -2 \sin t \). The \( z \) component is \( z = \sqrt{2} \cos t \). Identify these as parametric equations for a 3D curve.
02
Analyze the Projection on the \( xz \)-Plane
In the \( xz \) components, both are \( \sqrt{2} \cos t \), meaning \( x = z \). This indicates any projection onto the \( xz \)-plane would lie along the line \( z = x \).
03
Consider the Elliptical Nature in the \( xy \)-Plane
If we set the parametric equations \( x = \sqrt{2} \cos t \) and \( y = -2 \sin t \) in the \( xy \)-plane, rearranging gives \( \left( \frac{x}{\sqrt{2}} \right)^2 + \left( \frac{y}{2} \right)^2 = 1 \). This is the equation of an ellipse centered at the origin, with semi-major axis \( 2 \) along the \( y \)-axis and semi-minor axis \( \sqrt{2} \) along the \( x \)-axis.
04
Understanding the 3D Curve
The curve in 3D is an elliptical cylinder stretched along the \( z \)-axis according to \( x = z \). As \( t \) range from \( 0 \) to \( 2\pi \), the ellipse in the \( xy \)-plane moves accordingly, forming the surface of the elliptical cylinder along \( z \).
05
Determining the Direction of the Curve
The curve starts at \((\sqrt{2}, 0, \sqrt{2})\) when \(t = 0\). As \(t\) increases (as given by the parametric equations), the point moves counter-clockwise in the \( xy \)-plane and the \( z \)-component synchronously matches with \( x \), reinforcing the helical form along the \( z \)-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Parametric Equations
Parametric equations are a set of equations where one or more dependent variables are expressed as functions of one or more independent parameters. In the context of vector-valued functions, categories like position, velocity, or acceleration can be described in terms of a parameter, typically denoted by \( t \).
For instance, consider the vector-valued function from the exercise:
Changes in \( t \) trace out a curve, with the parameter controlling the precise movement along this path. Parametric equations offer a flexible way to describe curves that might be hard to capture with the traditional Cartesian equations.
For instance, consider the vector-valued function from the exercise:
- \( x = \sqrt{2} \cos t \)
- \( y = -2 \sin t \)
- \( z = \sqrt{2} \cos t \)
Changes in \( t \) trace out a curve, with the parameter controlling the precise movement along this path. Parametric equations offer a flexible way to describe curves that might be hard to capture with the traditional Cartesian equations.
3D Curve Sketching
Sketching a 3D curve involves tracing the path defined by a vector-valued function in space. Unlike sketching in 2D, 3D curve visualization requires understanding the projection and movement in three dimensions.
The provided vector function \( \mathbf{F}(t) = \sqrt{2} \cos t \mathbf{i} - 2 \sin t \mathbf{j} + \sqrt{2} \cos t \mathbf{k} \) follows a specific trajectory based on its parametric definition:
The provided vector function \( \mathbf{F}(t) = \sqrt{2} \cos t \mathbf{i} - 2 \sin t \mathbf{j} + \sqrt{2} \cos t \mathbf{k} \) follows a specific trajectory based on its parametric definition:
- The \(xz\)-plane projection is a straight line because \( x = z \), indicating aligned motion directly along a path parallel to the line \( y = 0 \).
- In the \(xy\)-plane, the function forms an elliptical path, described by the ellipse equation \( \left( \frac{x}{\sqrt{2}} \right)^2 + \left( \frac{y}{2} \right)^2 = 1 \).
Elliptical Cylinder
An elliptical cylinder is a cylinder where its cross-sections are ellipses rather than just circles. In the exercise, the 3D curve created forms an elliptical cylinder. This is evident when we observe:
1. The elliptical base, defined by \( \left( \frac{x}{\sqrt{2}} \right)^2 + \left( \frac{y}{2} \right)^2 = 1 \) in the \(xy\)-plane.2. The alignment along the \(z\)-axis, denoted by the condition \( x = z \).
This alignment means that all points on the elliptical path can also be found vertically along the \( z \)-axis. Thus, extending each of these ellipses through the \( z \)-dimension traces out the cylindrical surface.
The formation is visually like a spring or a helix wrapping around an elliptical frame as it traces in the counter-clockwise direction when viewed from above. This understanding aids in recognizing and interpreting complex 3D geometric shapes in mathematics and engineering.
1. The elliptical base, defined by \( \left( \frac{x}{\sqrt{2}} \right)^2 + \left( \frac{y}{2} \right)^2 = 1 \) in the \(xy\)-plane.2. The alignment along the \(z\)-axis, denoted by the condition \( x = z \).
This alignment means that all points on the elliptical path can also be found vertically along the \( z \)-axis. Thus, extending each of these ellipses through the \( z \)-dimension traces out the cylindrical surface.
The formation is visually like a spring or a helix wrapping around an elliptical frame as it traces in the counter-clockwise direction when viewed from above. This understanding aids in recognizing and interpreting complex 3D geometric shapes in mathematics and engineering.