/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Solve the equation for \(x\) in ... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the equation for \(x\) in \([0,2 \pi)\). $$ \tan x=\sqrt{3} $$

Short Answer

Expert verified
The solutions are \( x = \frac{\pi}{3} \) and \( x = \frac{4\pi}{3} \).

Step by step solution

01

Understand the given equation

We are given the equation \( \tan x = \sqrt{3} \). We need to find the values of \( x \) between \( [0, 2\pi) \) for which this is true.
02

Identify reference angle

The tangent function \( \tan x = \sqrt{3} \) is known to occur at the angle \( x = \frac{\pi}{3} \) in the first quadrant. Reference angles repeat every \( \pi \) radians in the unit circle.
03

Solve for \(x\) in the given interval

Since \( \tan x = \sqrt{3} \) first occurs at \( x = \frac{\pi}{3} \), and given that tangent is periodic with a period of \( \pi \), the next solution within the interval \( [0, 2\pi) \) will be \( x = \frac{\pi}{3} + \pi \). This results in \( x = \frac{\pi}{3} + \pi = \frac{\pi}{3} + \frac{3\pi}{3} = \frac{4\pi}{3} \).
04

Verify the solutions

Verify that the solutions \( x = \frac{\pi}{3} \) and \( x = \frac{4\pi}{3} \) satisfy the original equation within the interval \( [0, 2\pi) \). Both values result in \( \tan x = \sqrt{3} \), confirming they are correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Function
The tangent function, denoted as \( \tan x \), is one of the primary trigonometric functions. It relates to the ratio of the sine and cosine of an angle, such that \( \tan x = \frac{\sin x}{\cos x} \). This relationship means that the tangent function is undefined when \( \cos x = 0 \). As a fundamental function in trigonometry, it often arises in various equations, particularly when dealing with right triangles or circular motion.

One crucial property of the tangent function is its periodicity, with a period of \( \pi \). This implies that the function repeats its values every \( \pi \) radians. In practical terms:
  • When you know one solution for a tangent equation, other solutions can be found by adding integer multiples of \( \pi \).
With this understanding, solving an equation like \( \tan x = \sqrt{3} \) involves identifying the angles where the tangent value is \( \sqrt{3} \), within the given interval.
Reference Angle
A reference angle is the smallest angle a given angle makes with the x-axis. It helps relate angles in different quadrants of the unit circle. The knowledge of reference angles is crucial in determining values of trigonometric functions for angles beyond the first quadrant.

For the equation \( \tan x = \sqrt{3} \), the reference angle is \( \frac{\pi}{3} \). Reference angles are a powerful tool, especially because they simplify finding solutions within specific quadrants.
  • The reference angle for \( \tan x = \sqrt{3} \) in the first quadrant is \( \frac{\pi}{3} \).
  • Since tangent is positive in both the first and third quadrants, another solution is found by adding \( \pi \), thus giving \( \frac{4\pi}{3} \).
With these two values, \( \frac{\pi}{3} \) and \( \frac{4\pi}{3} \), we cover all possible solutions for the equation in the interval \( [0, 2\pi) \).
Periodic Functions
Periodic functions repeat their values at regular intervals. In the realm of trigonometry, functions such as sine, cosine, and tangent are periodic. Understanding this property is vital because it enables us to generalize solutions across intervals and predict function behavior over the entire number line.

For the tangent function, the fundamental period is \( \pi \). This means that its values repeat every \( \pi \) radians.
  • The equation \( \tan x = \sqrt{3} \) shows that after finding one solution, additional solutions arise by adding \( \pi \), because of this periodicity.
  • It ensures that no matter where you start, the function will return to its original value after every \( \pi \) radian increase.
Practically, this means that for the problem given, once we identify \( x = \frac{\pi}{3} \) as a solution, the next valid solution within the interval \( [0, 2\pi) \) will be \( x = \frac{4\pi}{3} \). Consequently, periodicity not only allows for easier calculations but also for more comprehensive understanding of function behaviors.

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Most popular questions from this chapter

In order to solve an inequality on a graphics calculator, we can graph a corresponding function and determine where it is positive and where it is negative. In Exercises \(51-52\) use the zoom feature of a graphics calculator to find an approximate solution of the inequality. Zoom until successive values of the \(x\) coordinate have identical first three digits. $$ \begin{aligned} &x^{3}+1 \geq-x-2 \text { (Hint: Let } f(x)=x^{3}+x+3 \text { , and determine } \\ &\text { where } f(x) \geq 0 . \text { ) } \end{aligned} $$

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