/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 $$ \ln \left(e^{\ln e}\right) ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

$$ \ln \left(e^{\ln e}\right) $$

Short Answer

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Step by step solution

01

Identify the Innermost Expression

In the given expression \( \ln \left(e^{\ln e} \right) \), begin with the innermost part, which is \( \ln e \). We know that \( \ln e = 1 \) because the natural logarithm of the base \( e \) is 1.
02

Simplify the Exponent

Now replace \( \ln e \) with 1 in the exponent: \( e^{\ln e} = e^1 \). This simplifies our expression to \( e \).
03

Evaluate the Logarithm

Substitute \( e \) back into the logarithm, giving us \( \ln e \). Since \( \ln e = 1 \), the whole expression simplifies to 1.
04

Final Result

The original expression \( \ln \left(e^{\ln e} \right) \) simplifies step-by-step to 1. Thus, the final result of this calculation is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a special type of logarithm where the base is the mathematical constant \( e \). This constant is approximately equal to 2.71828, and it arises naturally in many areas of mathematics, especially in calculus and complex numbers.

Some key properties of the natural logarithm include:
  • \( \ln 1 = 0 \) because \( e^0 = 1 \).
  • \( \ln e = 1 \) because \( e^1 = e \).
  • \( \ln(ab) = \ln a + \ln b \), which means you can break down the logarithm of a product into a sum of logarithms.
  • \( \ln \left( \frac{a}{b} \right) = \ln a - \ln b \), which allows separation of a logarithm of a fraction into a difference.
  • \( \ln(a^b) = b \ln a \), showing how exponents affect the logarithm.
  • Since \( e \) is the base, the natural logarithm \( \ln e \) is always 1.
Understanding these rules helps in simplifying expressions that involve natural logarithms. Knowing that \( \ln e = 1 \) is crucial for evaluating the given expression \( \ln(e^{\ln e}) \), which simplifies the problem significantly.
Exponentiation
Exponentiation involves raising a number, known as the base, to a certain power or exponent. In simpler terms, if you have a number \( a \) and you raise it to the power \( b \), you are multiplying \( a \) by itself \( b \) times. Mathematically, this is expressed as \( a^b \).

Important points about exponentiation:
  • Any number raised to the power of 0 is 1 (e.g., \( a^0 = 1 \)).
  • Raising any number \( a \) to the power of 1 yields \( a \) itself (e.g., \( a^1 = a \)).
  • Exponentiation is a powerful operation and is the inverse of taking a logarithm when the base is a natural logarithm.
  • The exponential function \( e^x \) is foundational in calculus, describing continuous growth.
In our exercise, understanding that \( e^{\ln e} = e^1 = e \) is crucial for simplifying the expression as it demonstrates the utility of both operations in reversing one another to some extent.
Simplifying Expressions
Simplifying expressions is a process where we make a mathematical expression as straightforward as possible. This often involves reducing the complexity by applying basic arithmetic operations, algebraic identities, and other mathematical rules.

Some steps to effectively simplify an expression:
  • Look for the innermost expressions and simplify them first (e.g., \( \ln e = 1 \)).
  • Replace exponential terms with simpler equivalents if possible (e.g., \( e^{\ln e} \rightarrow e^1 \)).
  • Reapply core properties, such as logarithm identities, to collapse the expression further.
  • Check results by reconsidering any potential simplifications (li>Ensure all calculations abide by the mathematical rules and properties.
In our given problem, the steps involved checking the innermost expression \( \ln e = 1 \) first, followed by using properties of exponents to simplify \( e^{1} = e \), and finally reevaluating the logarithmic part to return to a simplified result of 1.

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