Chapter 1: Problem 44
Find an equation of the line that is perpendicular to the given line \(l\) and passes through the given point \(P\). \(l: y=-\frac{1}{3} x-2 ; P=(0,0)\)
Short Answer
Expert verified
The equation is \(y = 3x\).
Step by step solution
01
Identify the slope of the given line
The given line is expressed in the form of the slope-intercept equation \( y = mx + b \) where \( m \) is the slope. Here, the equation is \( y = -\frac{1}{3}x - 2 \). Therefore, the slope \( m \) of the given line is \(-\frac{1}{3}\).
02
Determine the slope of the perpendicular line
Two lines are perpendicular if the product of their slopes equals -1. If \( m = -\frac{1}{3} \) is the slope of the given line, then the slope \( m' \) of the perpendicular line can be found using the equation \( m \times m' = -1 \). Solving for \( m' \) gives \( m' = 3 \).
03
Use the point-slope form to find the equation of the line
We have the slope of the perpendicular line \( m' = 3 \) and a point \( P = (0,0) \) through which the line passes. Use the point-slope form \( y - y_1 = m'(x - x_1) \), with \((x_1, y_1) = (0, 0)\):\[y - 0 = 3(x - 0)\].
04
Simplify the equation
Simplify the equation from the previous step: \( y = 3(x - 0) \) which further simplifies to \( y = 3x \). This is the equation of the line that is perpendicular to the given line and passes through the point \((0,0)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a linear equation is represented as \( y = mx + b \). Here, \( m \) is the slope of the line, and \( b \) is the y-intercept, which is the point at which the line crosses the y-axis. This form is particularly useful for quickly identifying both the slope and y-intercept from an equation.
This makes graphing lines straightforward, as you can start by plotting the y-intercept \( b \) on the y-axis, and then use the slope \( m \) to find subsequent points on the line. For example, if \( m = -\frac{1}{3} \), the slope indicates a downward slant from left to right. This means for each unit you move to the right along the x-axis, you move \(-\frac{1}{3} \) units down along the y-axis.
Recognizing the slope-intercept form simplifies solving equations and understanding the line's characteristics.
This makes graphing lines straightforward, as you can start by plotting the y-intercept \( b \) on the y-axis, and then use the slope \( m \) to find subsequent points on the line. For example, if \( m = -\frac{1}{3} \), the slope indicates a downward slant from left to right. This means for each unit you move to the right along the x-axis, you move \(-\frac{1}{3} \) units down along the y-axis.
Recognizing the slope-intercept form simplifies solving equations and understanding the line's characteristics.
Slope of a Line
The slope of a line quantifies its steepness, direction, and the rate of change along the line. It is calculated as the ratio of the change in y to the change in x, often expressed as \( m = \frac{\Delta y}{\Delta x} \).
In simple terms, this means that for every unit increase in x, the y value changes by \( m \). A positive slope indicates an upward trend from left to right, while a negative slope shows a downward trend.
Two lines can have special relationships based on their slopes: parallel lines have equal slopes, and perpendicular lines have slopes that are negative reciprocals of each other. For example, if the slope of one line is \(-\frac{1}{3}\), the slope of a line perpendicular to it would be \(3\). This relationship is vital for solving problems involving perpendicular lines.
In simple terms, this means that for every unit increase in x, the y value changes by \( m \). A positive slope indicates an upward trend from left to right, while a negative slope shows a downward trend.
Two lines can have special relationships based on their slopes: parallel lines have equal slopes, and perpendicular lines have slopes that are negative reciprocals of each other. For example, if the slope of one line is \(-\frac{1}{3}\), the slope of a line perpendicular to it would be \(3\). This relationship is vital for solving problems involving perpendicular lines.
Point-Slope Form
The point-slope form of a line's equation is useful when you know a point on the line and its slope. It is written as \( y - y_1 = m(x - x_1) \).
Here, \((x_1, y_1)\) is a specific point on the line, and \( m \) is the slope. This form is especially handy when you need to write the equation of a line quickly given these two pieces of information.
For instance, with a point \( (0, 0) \) and slope \( 3 \), you can easily replace these values into the formula to get \( y - 0 = 3(x - 0) \), which simplifies to \( y = 3x \). Using the point-slope form efficiently transforms knowledge about one point and the line's steepness into a full equation.
Here, \((x_1, y_1)\) is a specific point on the line, and \( m \) is the slope. This form is especially handy when you need to write the equation of a line quickly given these two pieces of information.
For instance, with a point \( (0, 0) \) and slope \( 3 \), you can easily replace these values into the formula to get \( y - 0 = 3(x - 0) \), which simplifies to \( y = 3x \). Using the point-slope form efficiently transforms knowledge about one point and the line's steepness into a full equation.
Equations of Lines
Equations of lines are fundamental in algebra and come in various forms, each serving a unique purpose. The most common forms include slope-intercept, point-slope, and standard form \( Ax + By = C \). This diversity allows flexibility in problem-solving and graphing.
The choice of form depends on the information available. For instance, slope-intercept is perfect for quick graphing, while point-slope is advantageous when a line's slope and a single point are known.
Translating between forms is often necessary in algebra, such as deriving the slope-intercept from the point-slope form. Each form reveals something specific: the slope-intercept form clarifies the line's slope and y-intercept, while the point-slope form is excellent for emphasizing a line’s steepness from a specific starting point. Understanding these forms enriches one's capability to tackle diverse mathematical challenges involving linear equations.
The choice of form depends on the information available. For instance, slope-intercept is perfect for quick graphing, while point-slope is advantageous when a line's slope and a single point are known.
Translating between forms is often necessary in algebra, such as deriving the slope-intercept from the point-slope form. Each form reveals something specific: the slope-intercept form clarifies the line's slope and y-intercept, while the point-slope form is excellent for emphasizing a line’s steepness from a specific starting point. Understanding these forms enriches one's capability to tackle diverse mathematical challenges involving linear equations.