Chapter 1: Problem 41
Find an equation of the line that is parallel to the given line \(l\) and passes through the given point \(P\). \(l:-3 y+2 x=8 ; P=(2,1)\)
Short Answer
Expert verified
The equation of the parallel line is \(y = \frac{2}{3}x - \frac{1}{3}\).
Step by step solution
01
Identify the Slope of the Given Line
The given line is presented in the standard form \(-3y + 2x = 8\). To find its slope, we need to rearrange the equation into the slope-intercept form \(y = mx + b\), where \(m\) is the slope.Rearrange the equation:\[-3y = -2x + 8\]Divide each side by \(-3\):\[y = \frac{2}{3}x - \frac{8}{3}\]The slope of the given line is \(\frac{2}{3}\).
02
Use the Slope for the Parallel Line
A line parallel to another has the same slope. Thus, the slope of our new line (parallel line) is also \(\frac{2}{3}\).
03
Apply the Point-Slope Form
We will use the point-slope form of a line equation, which is given by \(y - y_1 = m(x - x_1)\), where \((x_1, y_1)\) is the given point the line passes through and \(m\) is the slope.Substitute the point \(P = (2, 1)\) and the slope \(m = \frac{2}{3}\):\[y - 1 = \frac{2}{3}(x - 2)\]
04
Simplify to Slope-Intercept Form
We will simplify the equation from Step 3 to make it look more like the familiar \(y = mx + b\) form.Distribute the slope \(\frac{2}{3}\):\[y - 1 = \frac{2}{3}x - \frac{4}{3}\]Add 1 to both sides to solve for \(y\):\[y = \frac{2}{3}x - \frac{4}{3} + 1\]Convert 1 to \(\frac{3}{3}\) for easy addition:\[y = \frac{2}{3}x + \frac{-4}{3} + \frac{3}{3}\]Simplify:\[y = \frac{2}{3}x - \frac{1}{3}\]That's the equation of the line parallel to the given line and passing through the point \((2, 1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
The slope-intercept form of a line is a widely used mathematical equation, represented as \( y = mx + b \). Here, \( y \) is the dependent variable, \( x \) is the independent variable, \( m \) is the slope of the line, and \( b \) is the y-intercept—the point at which the line crosses the y-axis. This form helps us easily understand how steep the line is and where it starts on the y-axis.
To better grasp it, think of a line as a ramp. The slope \( m \) tells you how steep that ramp is, while the y-intercept \( b \) shows you where the bottom of the ramp sits if it were set on the y-axis.
The beauty of the slope-intercept form is in its simplicity and clarity. From this equation, you can tell whether the line rises or falls as you move from left to right—a positive \( m \) means the line is rising, while a negative \( m \) indicates a fall. The y-intercept \( b \) directly gives you a starting point, making it easier to graph and interpret real-world scenarios.
By understanding this form, transforming equations to a more usable state becomes easier, especially from a standard form as shown in the exercise.
To better grasp it, think of a line as a ramp. The slope \( m \) tells you how steep that ramp is, while the y-intercept \( b \) shows you where the bottom of the ramp sits if it were set on the y-axis.
The beauty of the slope-intercept form is in its simplicity and clarity. From this equation, you can tell whether the line rises or falls as you move from left to right—a positive \( m \) means the line is rising, while a negative \( m \) indicates a fall. The y-intercept \( b \) directly gives you a starting point, making it easier to graph and interpret real-world scenarios.
By understanding this form, transforming equations to a more usable state becomes easier, especially from a standard form as shown in the exercise.
Point-Slope Form
The point-slope form is a powerful tool, especially when you need to create an equation of a line based on a known point and slope. Written as \( y - y_1 = m(x - x_1) \), this equation can be quickly built if you know a point \((x_1, y_1)\) on the line and the slope \(m\).
By using the point-slope form, building an equation becomes straightforward: just plug in the slope and the coordinates of the point. For example, if your point is \((2, 1)\) and the slope is \( \frac{2}{3} \), you'd have \( y - 1 = \frac{2}{3}(x - 2) \).
This form is especially handy in situations where you need quick adjustments, such as identifying lines parallel or perpendicular to a given line. For example, parallel lines share the same slope, so once you know the slope, you can use the point-slope form to write the equation of any line parallel to another, passing through a point you specify.
In various applications such as engineering, physics, and economics, this form helps in modeling and expressing linear relationships efficiently.
By using the point-slope form, building an equation becomes straightforward: just plug in the slope and the coordinates of the point. For example, if your point is \((2, 1)\) and the slope is \( \frac{2}{3} \), you'd have \( y - 1 = \frac{2}{3}(x - 2) \).
This form is especially handy in situations where you need quick adjustments, such as identifying lines parallel or perpendicular to a given line. For example, parallel lines share the same slope, so once you know the slope, you can use the point-slope form to write the equation of any line parallel to another, passing through a point you specify.
In various applications such as engineering, physics, and economics, this form helps in modeling and expressing linear relationships efficiently.
Line Equation
The equation of a line showcases fundamental relationships between variables, typically in contexts involving change and prediction. Whether in the slope-intercept or point-slope form, understanding these equations is crucial for interpreting linear phenomena.
Lines can describe basic relationships, like predicting outcomes (e.g., sales and revenue) based on historical data. A line equation expresses constant change, portraying how one variable consistently scales with another.
The line equation processes start from identifying the relationship type: from a given slope and a point or rearranging standard forms to bring clarity. In practice, like solving the exercise given, knowing these steps can lead to effectively describing a parallel line, which involves finding a line with the same slope as another.
Whether using the line to determine the future position of a moving object or to analyze trends, mastering line equations allows for deeper insights into linear data, supporting better decision-making and precise predictions.
Lines can describe basic relationships, like predicting outcomes (e.g., sales and revenue) based on historical data. A line equation expresses constant change, portraying how one variable consistently scales with another.
The line equation processes start from identifying the relationship type: from a given slope and a point or rearranging standard forms to bring clarity. In practice, like solving the exercise given, knowing these steps can lead to effectively describing a parallel line, which involves finding a line with the same slope as another.
Whether using the line to determine the future position of a moving object or to analyze trends, mastering line equations allows for deeper insights into linear data, supporting better decision-making and precise predictions.