Chapter 1: Problem 13
Solve the inequality for \(x\) in \([0,2 \pi)\). $$ \tan x \geq 1 $$
Short Answer
Expert verified
The solution set is \([\frac{\pi}{4}, \frac{5\pi}{4}]\).
Step by step solution
01
Solve the Equation
To solve the inequality \( \tan x \geq 1 \), we first solve for the equation \( \tan x = 1 \). The general solution for \( \tan x = 1 \) is \( x = \frac{\pi}{4} + k\pi \), where \( k \) is an integer.
02
Find the Solutions in Problem's Domain
The problem states that \( x \) should be in the interval \([0, 2\pi)\). Calculate the specific values of \( x = \frac{\pi}{4} + k\pi \) that fall within this interval: \- For \( k = 0 \), \( x = \frac{\pi}{4} \).- For \( k = 1 \), \( x = \frac{5\pi}{4} \).(No further values of \( k \) in increasing order will result in \( x < 2\pi \).)
03
Analyze the Inequality in Each Interval
Evaluate the inequality \( \tan x \geq 1 \). The relevant intervals based on the tangent function's period of \( \pi \) and zeros given as solutions are \((\frac{\pi}{4}, \frac{5\pi}{4}) \) and \((\frac{5\pi}{4}, 2\pi) \). In \((\frac{\pi}{4}, \frac{5\pi}{4}) \), \( \tan x \) is greater than or equal to 1, including endpoints. The interval \((\frac{5\pi}{4}, 2\pi) \) is outside the requirement except for where we have \( \tan x \) increasing until another zero at \( 2\pi\). Hence the set of solutions is \( [\frac{\pi}{4}, \frac{5\pi}{4}] \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Tangent Function
The tangent function, denoted as \( \tan x \), is one of the primary trigonometric functions. Understanding its behavior is critical when solving trigonometric equations and inequalities. The function is defined by the ratio of the sine and cosine functions: \( \tan x = \frac{\sin x}{\cos x} \). This function is periodic, meaning it repeats its values in a regular cycle. Specifically, \( \tan x \) has a period of \( \pi \), which means after every \( \pi \) units, the function's values start repeating.
Within each period, \( \tan x \) can take all real values, which makes it unique among trigonometric functions. It has vertical asymptotes whenever \( \cos x = 0 \), occurring at odd multiples of \( \frac{\pi}{2} \). At these points, the tangent function is undefined.
Within each period, \( \tan x \) can take all real values, which makes it unique among trigonometric functions. It has vertical asymptotes whenever \( \cos x = 0 \), occurring at odd multiples of \( \frac{\pi}{2} \). At these points, the tangent function is undefined.
- The zeros of \( \tan x \) occur at multiples of \( \pi \), such as \( x = 0, \pi, 2\pi, \ldots \).
- The tangent function is positive in the first quadrant (0 to \( \frac{\pi}{2} \)) and in the third quadrant (\( \pi \) to \( \frac{3\pi}{2} \)).
Trigonometric Equations
Trigonometric equations involve functions like sine, cosine, and tangent. Solving \( \tan x = 1 \) is a typical example where understanding the periodic nature of these functions is crucial. Solving the equation involves:
- Recognizing that \( \tan x = 1 \) occurs at specific angles. For tangent, this happens at angles such as \( x = \frac{\pi}{4} \), since \( \tan \frac{\pi}{4} = \frac{\sin \frac{\pi}{4}}{\cos \frac{\pi}{4}} = 1 \).
- Using the periodicity, the general solution can be expressed as \( x = \frac{\pi}{4} + k\pi \), where \( k \) is an integer.
Interval Notation
Interval notation is a mathematical language used to describe a range of numbers. It is especially useful in expressing solutions to inequalities. There are several forms, each indicating whether endpoints are included or excluded:
- "[ ]" indicates that the endpoints are included in the interval.
- "( )" implies that the endpoints are not included.
- \([\frac{\pi}{4}, \frac{5\pi}{4}]\) includes both endpoints, meaning \( \tan x \geq 1 \) at \( x = \frac{\pi}{4} \) and \( x = \frac{5\pi}{4} \), as well as all points between.