Chapter 4: Problem 42
Sketch the following by finding the level curves. Verify the graph using technology. $$f(x, y)=\sqrt{4-x^{2}-y^{2}}$$
Short Answer
Expert verified
The sketch shows concentric circles with decreasing radius as \( c \) increases from 0 to 2.
Step by step solution
01
Understand the function
The function given is \( f(x, y) = \sqrt{4 - x^2 - y^2} \). This represents the upper half of a sphere with radius 2 centered at the origin in the xy-plane. The level curves of this function are circles centered at the origin.
02
Define Level Curves
Level curves are obtained by setting \( f(x, y) = c \), where \( c \) is a constant. Hence, \( \sqrt{4 - x^2 - y^2} = c \). Squaring both sides gives \( 4 - x^2 - y^2 = c^2 \), which simplifies to \( x^2 + y^2 = 4 - c^2 \). This is the equation of a circle with radius \( \sqrt{4 - c^2} \) centered at the origin.
03
Determine Possible Values of c
Since \( f(x, y) = \sqrt{4 - x^2 - y^2} \), \( c \) must be between 0 and 2 inclusive. Thus, \( c \in [0, 2] \). This ensures that \( 4 - c^2 \geq 0 \), making the level curve a real geometric circle.
04
Sketch the Level Curves
For various values of \( c \) within the range, plot the circles representing the level curves. For example, if \( c = 0 \), the circle has a radius of 2 (\( x^2 + y^2 = 4 \)); if \( c = 1 \), the radius is \( \sqrt{3} \) (\( x^2 + y^2 = 3 \)); if \( c = 2 \), the radius is 0 (a point at the origin).
05
Verify with Technology
Use graphing software or a graphing calculator to input the function and visualize the surface. The level curves manifested on the surface should correspond with those calculated: concentric circles shrinking towards the center as you increase \( c \) towards 2.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Level Curves
In multivariable calculus, level curves provide a way to visually represent functions of two variables. To understand level curves, imagine slicing a landscape at different heights and observing the contours formed.
When examining the function \( f(x, y) = \sqrt{4 - x^2 - y^2} \), the level curves are found by setting \( f(x, y) = c \), where \( c \) is a constant. This tells us every point \((x, y)\) on a particular level curve results in the same function value, \( c \).
For the function \( \sqrt{4 - x^2 - y^2} = c \), squaring both sides gives us \( 4 - x^2 - y^2 = c^2 \). Rearranging yields \( x^2 + y^2 = 4 - c^2 \), which represents circles centered at the origin, with varying radii dependent on \( c \).
These level curves show concentric circles when plotted in the xy-plane. They reflect changes in height along the surface defined by the function, akin to contour lines on a topographic map. This vivid depiction can deeply enhance your understanding of the function's behavior.
When examining the function \( f(x, y) = \sqrt{4 - x^2 - y^2} \), the level curves are found by setting \( f(x, y) = c \), where \( c \) is a constant. This tells us every point \((x, y)\) on a particular level curve results in the same function value, \( c \).
For the function \( \sqrt{4 - x^2 - y^2} = c \), squaring both sides gives us \( 4 - x^2 - y^2 = c^2 \). Rearranging yields \( x^2 + y^2 = 4 - c^2 \), which represents circles centered at the origin, with varying radii dependent on \( c \).
These level curves show concentric circles when plotted in the xy-plane. They reflect changes in height along the surface defined by the function, akin to contour lines on a topographic map. This vivid depiction can deeply enhance your understanding of the function's behavior.
Sphere
A sphere in mathematics arises when revolving a circle around its diameter. In this specific exercise, the equation \( f(x, y) = \sqrt{4 - x^2 - y^2} \) describes the upper half of a sphere.
Here, the sphere's equation in standard form is \( x^2 + y^2 + z^2 = r^2 \). For this function, rearranging where \( z = \sqrt{4 - x^2 - y^2} \) confirms the sphere's radius is 2, and it's centered at the origin, \((0,0,0)\).
This geometric interpretation helps link the abstract function to the three-dimensional surface it represents. Understanding how level curves map this sphere onto the plane enriches your spatial reasoning in multivariable calculus.
Here, the sphere's equation in standard form is \( x^2 + y^2 + z^2 = r^2 \). For this function, rearranging where \( z = \sqrt{4 - x^2 - y^2} \) confirms the sphere's radius is 2, and it's centered at the origin, \((0,0,0)\).
This geometric interpretation helps link the abstract function to the three-dimensional surface it represents. Understanding how level curves map this sphere onto the plane enriches your spatial reasoning in multivariable calculus.
- The radius of the sphere guides the extent of level curves.
- The center at the origin simplifies calculations and visualizations.
Radius
Radius plays a crucial role in both the geometry of spheres and in defining level curves.
The function \( f(x, y) = \sqrt{4 - x^2 - y^2} \) inherently defines a sphere of radius 2. In this context, the radius directly impacts the size of level curves, or circles within the xy-plane.
When examining \( x^2 + y^2 = 4 - c^2 \), we identify the radius of each level curve as \( \sqrt{4 - c^2} \). This varies as \( c \) changes:
The function \( f(x, y) = \sqrt{4 - x^2 - y^2} \) inherently defines a sphere of radius 2. In this context, the radius directly impacts the size of level curves, or circles within the xy-plane.
When examining \( x^2 + y^2 = 4 - c^2 \), we identify the radius of each level curve as \( \sqrt{4 - c^2} \). This varies as \( c \) changes:
- For \( c = 0 \), the circle has the maximum radius of 2.
- As \( c \) approaches 2, the radius decreases to 0, culminating as a single point at the origin.
Graphing Software
Graphing software serves as an invaluable tool in visualizing multivariable functions such as \( f(x, y) = \sqrt{4 - x^2 - y^2} \). These programs help translate the mathematical expressions into visual, interactive representations.
Using graphing software affords several advantages:
From assessing the function and verifying mathematical predictions, graphing software turns abstract calculations into colorful visual insights. It enhances learning by providing a virtual yet tangible experience, crucial for mastering multivariable calculus concepts.
Using graphing software affords several advantages:
- Immediate visual feedback of level curves and surfaces.
- Simplification of complex calculations and plotting.
- An opportunity for interactive exploration and deeper understanding.
From assessing the function and verifying mathematical predictions, graphing software turns abstract calculations into colorful visual insights. It enhances learning by providing a virtual yet tangible experience, crucial for mastering multivariable calculus concepts.