Chapter 4: Problem 163
Find a unit normal vector to the surface at the indicated point. \(f(x, y)=x^{3},(2,-1,8)\)
Short Answer
Expert verified
The unit normal vector is \( \left( \frac{12}{\sqrt{145}}, 0, \frac{-1}{\sqrt{145}} \right) \).
Step by step solution
01
Define the Surface Function
The given function is a surface in the form of a level surface: \[ f(x, y, z) = x^3 - z = 0 \]. We need to determine the gradient of this function to find the normal vector.
02
Calculate the Gradient of the Function
The gradient of a function \( f(x, y, z) = g(x, y, z) \) is given by \( abla f = \left( \frac{\partial g}{\partial x}, \frac{\partial g}{\partial y}, \frac{\partial g}{\partial z} \right) \). For our function, \( g(x, y, z) = x^3 - z \), we have: \[ \frac{\partial g}{\partial x} = 3x^2, \quad \frac{\partial g}{\partial y} = 0, \quad \frac{\partial g}{\partial z} = -1 \]. Thus, \( abla f = (3x^2, 0, -1) \).
03
Evaluate the Gradient at the Given Point
Substitute the point (2, -1, 8) into the gradient. \[ abla f(2, -1, 8) = (3(2)^2, 0, -1) = (12, 0, -1) \].
04
Normalize the Gradient Vector
To find a unit normal vector, we need to divide the gradient by its magnitude. The magnitude of \( (12, 0, -1) \) is \[ \sqrt{12^2 + 0^2 + (-1)^2} = \sqrt{144 + 1} = \sqrt{145} \]. The unit normal vector is \[ \left( \frac{12}{\sqrt{145}}, \frac{0}{\sqrt{145}}, \frac{-1}{\sqrt{145}} \right) \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gradient Vector
The gradient vector is like a guide that points in the direction of steepest ascent for a multivariable function. Think of it as climbing a hill: the gradient shows you where to go to reach the top fastest. In mathematical terms, for a function \[ f(x, y, z) \], the gradient vector, denoted as \( abla f \), is constructed from the partial derivatives. This means:
- It captures how the function changes in different directions, represented by the variables \( x, y, \text{and} z \).
- The components of the gradient are the partial derivatives of \( f \) with respect to each variable.
Level Surface
A level surface is a three-dimensional counterpart to a contour line on a map, indicating where a function has a constant value. It’s like drawing a surface in the sky where every point meets the same condition.
In the exercise's context, our level surface is defined by the equation \[ f(x, y, z) = x^3 - z = 0 \], which outlines a surface where all points satisfy this equation.
In the exercise's context, our level surface is defined by the equation \[ f(x, y, z) = x^3 - z = 0 \], which outlines a surface where all points satisfy this equation.
- This means every point on this surface makes the expression equal zero, creating a specific shape in 3D space.
- The role of the level surface is key in finding vectors that are normal (perpendicular) to it.
Surface Function
The concept of a surface function essentially defines a relationship among variables that form a surface in three-dimensional space. It explains how these variables interact to create a particular shape or configuration. In the exercise, the surface is represented by the function \[ f(x, y, z) = x^3 - z \].
Here are the key points:
Here are the key points:
- This function sets out the rules for the surface’s form by equating it to zero, indicating the surface itself.
- Surface functions like this one are used to explore properties such as gradients, normals, and more.
Partial Derivative
Partial derivatives measure how a function changes as one of its variables is varied, while all others are kept constant. They are the "slices" of a multivariable function, detailing how it behaves in different directions.
- Imagine adjusting the position on a surface by shifting only along one axis at a time. The partial derivative shows how sensitive the surface is to these small changes.
- For the function \[ g(x, y, z) = x^3 - z \], we calculate these derivatives as:
- \( \frac{\partial g}{\partial x} = 3x^2 \) - showing change in function with respect to \( x \).
- \( \frac{\partial g}{\partial y} = 0 \) - indicating no change or influence by \( y \).
- \( \frac{\partial g}{\partial z} = -1 \) - revealing a change with respect to \( z \).