Chapter 3: Problem 33
Consider the curve described by the vector-valued function $$\mathbf{r}(t)=\left(50 e^{-t} \cos t\right) \mathbf{i}+\left(50 e^{-t} \sin t\right) \mathbf{j}+\left(5-5 e^{-t}\right) \mathbf{k}$$ What is the initial point of the path corresponding to \(\mathbf{r}(0) ?\)
Short Answer
Expert verified
The initial point is (50, 0, 0).
Step by step solution
01
Understanding the Problem
We are given a vector-valued function \(\mathbf{r}(t)\) that describes a curve in three-dimensional space. We need to find the position of a point on this curve at \(t=0\), which is known as the initial point of the path.
02
Identify Components at \(t=0\)
Separate the vector-valued function \(\mathbf{r}(t)\) into its components: \(x(t) = 50 e^{-t} \cos t\), \(y(t) = 50 e^{-t} \sin t\), and \(z(t) = 5 - 5 e^{-t}\). We will evaluate each component at \(t=0\).
03
Calculate the \(x\) Coordinate
Substitute \(t=0\) into \(x(t) = 50 e^{-t} \cos t\). This gives \(x(0) = 50 e^{0} \cos 0 = 50 \cdot 1 \cdot 1 = 50\).
04
Calculate the \(y\) Coordinate
Substitute \(t=0\) into \(y(t) = 50 e^{-t} \sin t\). This gives \(y(0) = 50 e^{0} \sin 0 = 50 \cdot 1 \cdot 0 = 0\).
05
Calculate the \(z\) Coordinate
Substitute \(t=0\) into \(z(t) = 5 - 5 e^{-t}\). This gives \(z(0) = 5 - 5 e^{0} = 5 - 5 \cdot 1 = 0\).
06
Determine the Initial Point
Combine the evaluated components \(x(0)\), \(y(0)\), and \(z(0)\) to form the point \((x, y, z) = (50, 0, 0)\). This is the initial point of the path.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
The Initial Point of a Curve
The initial point of a curve is the starting location of a path when the parameter that defines the curve, typically \( t \), is set to zero. When dealing with vector-valued functions that describe curves, finding the initial point means calculating the position vector \( \mathbf{r}(0) \).
For example, with the function \( \mathbf{r}(t) = (50 e^{-t} \cos t) \mathbf{i} + (50 e^{-t} \sin t) \mathbf{j} + (5 - 5 e^{-t}) \mathbf{k} \), we compute each component at \( t=0 \):
For example, with the function \( \mathbf{r}(t) = (50 e^{-t} \cos t) \mathbf{i} + (50 e^{-t} \sin t) \mathbf{j} + (5 - 5 e^{-t}) \mathbf{k} \), we compute each component at \( t=0 \):
- The \( x \) component: \( x(0) = 50 \cos 0 = 50 \).
- The \( y \) component: \( y(0) = 50 \sin 0 = 0 \).
- The \( z \) component: \( z(0) = 5 - 5 = 0 \).
Understanding Three-Dimensional Space
Three-dimensional space is the space that we live in. It has three dimensions: length, width, and height. In mathematics, this is often expressed in terms of three coordinates \((x, y, z)\). Each coordinate represents a dimension.
A vector-valued function can describe paths and curves in such a space, cutting through all dimensions together. For instance, the given function \( \mathbf{r}(t) \) maps a path that evolves with time, capturing movement in the \( x \), \( y \), and \( z \) directions simultaneously.
A vector-valued function can describe paths and curves in such a space, cutting through all dimensions together. For instance, the given function \( \mathbf{r}(t) \) maps a path that evolves with time, capturing movement in the \( x \), \( y \), and \( z \) directions simultaneously.
- \( x \)-axis: Connects points from left to right.
- \( y \)-axis: Connects points from front to back.
- \( z \)-axis: Connects points from top to bottom.
Component Functions in Vector-Valued Functions
Vector-valued functions consist of several component functions, each corresponding to a spatial dimension. For a three-dimensional curve, the position vector can be expressed in terms of three separate functions: \( x(t) \), \( y(t) \), and \( z(t) \). Each function describes how the curve behaves in a particular dimension.
For example, in the vector function \( \mathbf{r}(t) = (50 e^{-t} \cos t) \mathbf{i} + (50 e^{-t} \sin t) \mathbf{j} + (5 - 5 e^{-t}) \mathbf{k} \):
For example, in the vector function \( \mathbf{r}(t) = (50 e^{-t} \cos t) \mathbf{i} + (50 e^{-t} \sin t) \mathbf{j} + (5 - 5 e^{-t}) \mathbf{k} \):
- \( x(t) = 50 e^{-t} \cos t \) controls the movement along the \( x \)-axis.
- \( y(t) = 50 e^{-t} \sin t \) controls the movement along the \( y \)-axis.
- \( z(t) = 5 - 5 e^{-t} \) adjusts vertical movement along the \( z \)-axis.
Position Vectors and Their Significance
A position vector is a vector that originates from the origin and points to a specific location in space. It is used to pinpoint the location of a point in space based on its coordinates \((x, y, z)\).
In our scenario, the vector \( \mathbf{r}(t) \) not only describes the position of a point at any time \( t \), but it also illustrates how the point moves in three-dimensional space.
In our scenario, the vector \( \mathbf{r}(t) \) not only describes the position of a point at any time \( t \), but it also illustrates how the point moves in three-dimensional space.
- Beginning with the initial point at \( t=0 \), where the position vector might be \( (50, 0, 0) \), gives an idea about the starting position.
- As \( t \) changes, \( \mathbf{r}(t) \) will trace the trajectory of the point, thereby exhibiting dynamics in a vibrant 3D path.
- In other words, position vectors connect mathematical calculations to physical locations in the real world.