Chapter 2: Problem 19
Let \(\mathbf{u}\) and \(\mathbf{v}\) be two nonzero vectors that are nonequivalent. Consider the vectors \(\mathbf{a}=4 \mathbf{u}+5 \mathbf{v}\) and \(\mathbf{b}=\mathbf{u}+2 \mathbf{v}\) defined in terms of \(\mathbf{u}\) and \(\mathbf{v}\). Find the scalar \(\lambda\) such that vectors \(\mathbf{a}+\lambda \mathbf{b}\) and \(\mathbf{u}-\mathbf{v}\) are equivalent.
Short Answer
Step by step solution
Express Resultant Vector
Distribute Nonzero Scalars
Combine Like Terms
Equate to Target Vector
Extract Scalar Conditions
Solve Scalar Equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Scalar Multiplication
- If \( \lambda \) is greater than 1, the vector will stretch.
- If \( \lambda \) is between 0 and 1, the vector will shrink.
- If \( \lambda \) is 0, the vector disappears, essentially becoming a zero vector.
- If \( \lambda \) is negative, the vector will not only change in magnitude but also reverse its direction.
Vector Components
When you have a vector like \( \mathbf{a} = 4\mathbf{u} + 5\mathbf{v} \), the vector components \( 4\mathbf{u} \) and \( 5\mathbf{v} \) indicate how much of each direction (\( \mathbf{u} \) and \( \mathbf{v} \)) contribute to the vector \( \mathbf{a} \). This shows us:
- 4 units in the direction of \( \mathbf{u} \)
- 5 units in the direction of \( \mathbf{v} \)
Vector Equivalence
To establish equivalence, each component of one vector needs to match the corresponding component of the other vector. In this exercise:
- For the component along \( \mathbf{u} \): Make sure \( 4 + \lambda = 1 \).
- For the component along \( \mathbf{v} \): Ensure \( 5 + 2\lambda = -1 \).