Chapter 2: Problem 136
For the following exercises, find the measure of the angle between the three- dimensional vectors \(\mathbf{a}\) and \(\mathbf{b}\). Express the answer in radians rounded to two decimal places, if it is not possible to express it exactly. \(\mathbf{a}=\langle 0,-1,-3\rangle, \quad \mathbf{b}=\langle 2,3,-1\rangle\)
Short Answer
Step by step solution
Understand the Formula
Calculate the Dot Product
Calculate the Magnitudes
Calculate the Cosine of the Angle
Find the Angle
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dot Product
- In the given exercise, \( \mathbf{a} \cdot \mathbf{b} = 0 \), indicating that the vectors are perpendicular.
- Remember that the dot product reflects projection. A zero value means no projection exists!
Vector Magnitude
- It allows us to normalize vectors, making them unit vectors (vectors of length one).
- By using magnitudes, we can apply them in the formula to find the cosine of the angle between vectors.
Theta in Radians
- 1 radian is about 57.2958 degrees.
- In the case of \( \cos \theta = 0 \), \( \theta \) is actually \( \frac{\pi}{2} \) radians, representing 90 degrees.
Three-Dimensional Vectors
- In this context, each component affects both the result of vector operations and spatial relations, like the angle between vectors.
- It is crucial to visualize 3D vectors within the context of geometry, aiding in understanding their interactions like angles and distances.