Chapter 1: Problem 226
Use the integration capabilities of a calculator to approximate the length of the curve. \(r=2 \theta^{2}\) on the interval \(0 \leq \theta \leq \pi\)
Short Answer
Expert verified
The approximate length of the curve is the result obtained from evaluating \( \int_{0}^{\pi} 2\theta \sqrt{4 + \theta^2} \, d\theta \) using a calculator.
Step by step solution
01
Understand the formula for the arc length
To find the length of a curve described by a polar equation \(r = f(\theta)\) over an interval \(\alpha \leq \theta \leq \beta\), we use the formula: \[ L = \int_{\alpha}^{\beta} \sqrt{\left( \frac{dr}{d\theta} \right)^2 + r^2} \, d\theta \]. Here, \(r = 2\theta^2\).
02
Differentiate \(r\) with respect to \(\theta\)
Calculate \( \frac{dr}{d\theta} \) for the given function. Since \(r = 2\theta^2\), use differentiation: \( \frac{dr}{d\theta} = 4\theta \).
03
Substitute into the arc length formula
Substitute \( \frac{dr}{d\theta} = 4\theta\) and \(r = 2\theta^2\) into the arc length formula. This gives: \[ L = \int_{0}^{\pi} \sqrt{(4\theta)^2 + (2\theta^2)^2} \, d\theta \].
04
Simplify the expression inside the integral
Simplify the expression under the square root: \( (4\theta)^2 + (2\theta^2)^2 = 16\theta^2 + 4\theta^4 = 4\theta^2(4 + \theta^2) \).
05
Integral setup for calculator approximation
The integral now becomes \( L = \int_{0}^{\pi} 2\theta \sqrt{4 + \theta^2} \, d\theta \). Use your calculator to approximate this integral value over the interval from \(0\) to \(\pi\).
06
Approximate using a calculator
Enter the expression \( 2\theta \sqrt{4 + \theta^2} \) into the integral function of your calculator. Evaluate the definite integral from \(0\) to \(\pi\). This will yield the approximate length of the curve.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Arc Length
The concept of arc length is a fundamental idea in mathematics, particularly in geometry and calculus. Arc length refers to the distance along a curve between two points. In polar coordinates, where points are defined by a radius and angle, calculating the arc length requires a special formula. For a function described by a polar equation such as \( r = f(\theta) \), the arc length \( L \) over the interval \( \alpha \leq \theta \leq \beta \) is given by the integral formula:
- \[ L = \int_{\alpha}^{\beta} \sqrt{\left( \frac{dr}{d\theta} \right)^2 + r^2} \, d\theta \]
Integration
Integration is a key operation in calculus used to calculate areas under curves, among other things. It's the process of finding the integral of a function, which can be thought of as the opposite of differentiation. In terms of calculating arc length, integration helps sum small distances along the curve to find the total length:
- When dealing with polar coordinates, integration becomes essential to evaluate expressions where the function is made of complex roots and squares.
- The integral set up for the arc length \( L \) in the original exercise \( \int_{0}^{\pi} 2\theta \sqrt{4 + \theta^2} \, d\theta \) is solved using numerical techniques or calculators.
Calculus
Calculus is a branch of mathematics that studies how things change and allows us to describe dynamic systems. It is divided into two main branches: differential calculus and integral calculus.
- Differential Calculus: This deals with the concept of a derivative, which represents the rate of change of a function. For example, in calculating arc lengths, the derivative \( \frac{dr}{d\theta} \) is used to understand how the radius changes as the angle \( \theta \) changes.
- Integral Calculus: This deals with integrals and finding the total size or value of something when it is represented by a continuous function. This branch is used to compute quantities such as areas, volumes, and in this case, the total arc length.