Chapter 6: Problem 204
Find the Maclaurin series of each function. $$ f(x)=\frac{\sin x}{x} $$
Short Answer
Expert verified
The Maclaurin series for \( \frac{\sin x}{x} \) is \( 1 - \frac{x^2}{6} + \frac{x^4}{120} - \cdots \).
Step by step solution
01
Understand the Definition of Maclaurin Series
A Maclaurin series is a special case of the Taylor series where the function is expanded at 0. The general form for the Maclaurin series of a function \( f(x) \) is given by \( f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots \)
02
Find the Maclaurin Series for sin(x)
Identify the Maclaurin series expansion for \( \sin x \), which is \( \sin x = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots \).
03
Divide the Series by x
Divide each term of the series \( \sin x \) by \( x \) to find the series for \( \frac{\sin x}{x} \). This results in \( \frac{\sin x}{x} = 1 - \frac{x^2}{3!} + \frac{x^4}{5!} - \frac{x^6}{7!} + \cdots \).
04
Combine and Simplify
Write the final Maclaurin series for \( \frac{\sin x}{x} \) as \( \frac{\sin x}{x} = 1 - \frac{x^2}{6} + \frac{x^4}{120} - \frac{x^6}{5040} + \cdots \). This expression shows the function's behavior near \( x = 0 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Taylor series
The Taylor series is a powerful tool in mathematics used for function approximation. It allows us to expand a given function into an infinite sum of terms calculated from the function's derivatives at a single point. Essentially, it takes a complex function and represents it as an infinite polynomial of powers of its variable.
- The general formula for a Taylor series is: \[ f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f'''(a)}{3!}(x-a)^3 + \cdots \]
- This expansion is centered around the point \( a \).
- The derivatives \( f'(a), f''(a) \) and so on, are evaluated at this specific point.
series expansion
Series expansion is a method we use to express functions as sums of simpler components, usually involving powers or exponential terms. Understanding a series can provide insight into the function's behavior over an interval or point.
- A series expansion breaks functions down into linear combinations of basis functions, like polynomials or trigonometric components.
- It's useful for finding approximate values for complex functions where direct computation might be difficult.
function expansion at zero
In mathematics, expanding a function at zero is specifically known as a Maclaurin series. It is a special case of the Taylor series where the expansion occurs around \( x = 0 \).
This was used in the example of \( f(x)=\frac{\sin x}{x} \), focused on understanding the function's behavior as \( x \) approaches zero, leading to easier analysis and comprehension of key properties.
- The Maclaurin series simplifies the general Taylor series formula:\[ f(x) = f(0) + f'(0)x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + \cdots \]
- This approach provides a straightforward way to understand a function's behavior very close to zero.
This was used in the example of \( f(x)=\frac{\sin x}{x} \), focused on understanding the function's behavior as \( x \) approaches zero, leading to easier analysis and comprehension of key properties.
trigonometric functions
Trigonometric functions, such as sine and cosine, are fundamental components of geometry and calculus. They also play a key role in many analytical and physical applications.
- They describe the ratios of the sides of a right triangle in terms of its angles, commonly denoted as \( \sin(x) \), \( \cos(x) \), and \( \tan(x) \).
- These functions are periodic, meaning they repeat values in a regular interval, making them essential for modeling cyclic phenomena such as sound and light waves.