Chapter 5: Problem 364
The \(k\) th term of each of the following series has a factor \(x^{k} .\) Find the range of \(x\) for which the ratio test implies that the series converges. $$\sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}}$$
Short Answer
Expert verified
The series converges for \(-1 < x < 1\).
Step by step solution
01
Understand the Series
The given series is \( \sum_{k=1}^{\infty} \frac{x^{k}}{k^{2}} \). This is an infinite series with each term having a factor \( x^k \). We need to find the range of \( x \) such that this series converges.
02
Apply the Ratio Test
The ratio test states that a series \( \sum a_k \) converges if \( \lim_{k \to \infty} \left| \frac{a_{k+1}}{a_k} \right| < 1 \).Here, \( a_k = \frac{x^k}{k^2} \). Find \( a_{k+1} = \frac{x^{k+1}}{(k+1)^2} \).
03
Calculate the Ratio \( \frac{a_{k+1}}{a_k} \)
Calculate the ratio:\[\frac{a_{k+1}}{a_k} = \frac{\frac{x^{k+1}}{(k+1)^2}}{\frac{x^k}{k^2}} = \frac{x^{k+1}}{(k+1)^2} \cdot \frac{k^2}{x^k} = x \cdot \frac{k^2}{(k+1)^2}\]This simplifies to \( x \cdot \left( \frac{k}{k+1} \right)^2 \).
04
Evaluate the Limit
Find the limit as \( k \) approaches infinity:\[\lim_{k \to \infty} x \cdot \left( \frac{k}{k+1} \right)^2 = x \cdot \lim_{k \to \infty} \left( \frac{k}{k+1} \right)^2 = x \cdot \left( \lim_{k \to \infty} \frac{k}{k+1} \right)^2\]\[= x \cdot 1^2 = x\]
05
Determine Convergence from the Limit
According to the ratio test, convergence requires that:\[|x| < 1\]This means that the series converges when \( x \) is inside the open interval \((-1, 1)\).
06
Conclusion
Therefore, the range of \( x \) for which the series \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \) converges is \(-1 < x < 1\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Convergence
In mathematics, especially in calculus, convergence of a series deals with the behavior of the sum of an infinite sequence of terms. A series is said to converge if the sequence of its partial sums approaches a finite limit. Let's break this down for better understanding:
- If you keep adding successive terms of a series, do these numbers eventually stabilize around a specific value? If yes, the series converges.
- If instead, the numbers keep growing larger in size or oscillating without settling down, the series diverges.
Calculus Series
Calculus often deals with series to evaluate functions, understand patterns and predict behavior. A series in calculus is the sum of the terms of a sequence. Two key concepts relating to series are:
- **Finite series**: These are series with a definite number of terms, like summing the first few terms of an arithmetic or geometric progression.
- **Infinite series**: These extend indefinitely. Examples include the geometric series and harmonic series.
Infinite Series
Infinite series provide a way to sum an unending stream of terms. This concept is important in calculus and mathematical analysis. An infinite series is of the form \( a_1 + a_2 + a_3 + ... \), where each term \( a_k \) can be associated with a function. Here, we deal with the series \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \):
- **Convergence**: An infinite series converges if there is a finite sum that represents the entire sequence as the number of terms approaches infinity.
- **Divergence**: If such a finite sum doesn't exist, the series diverges.
Limit Calculation
The concept of a limit is foundational in calculus, serving as the basis from which the concept of derivatives, integrals, and series convergence spring. Calculating limits involves finding the value that a function or sequence approaches as the variable approaches a specified point. In our context:
- We use **limit calculation** to find how the ratio of successive terms behaves as \( k \) approaches infinity.
- This process decides whether a series such as \( \sum_{k=1}^{\infty} \frac{x^k}{k^2} \) converges within a specific interval of \( x \).