Chapter 5: Problem 226
For which \(r>0\) does the series \(\sum_{n=1}^{\infty} \frac{r^{n}}{2^{n}}\) converge?
Short Answer
Expert verified
The series converges for \( 0 < r < 2 \).
Step by step solution
01
Understand the convergence criterion
We need to determine the values of \( r \) for which the series \( \sum_{n=1}^{\infty} \frac{r^{n}}{2^{n}} \) converges. This is a geometric series, which converges if the absolute value of the common ratio \( |\frac{r}{2}| \) is less than 1.
02
Set up the inequality for the common ratio
For convergence of the geometric series, set up the inequality: \( \left| \frac{r}{2} \right| < 1 \). This inequality will allow us to solve for the values of \( r \) that satisfy the convergence condition.
03
Solve the inequality
Solve the inequality \( \left| \frac{r}{2} \right| < 1 \):- This inequality simplifies to \( -1 < \frac{r}{2} < 1 \).- Multiplying all parts by 2 gives: \( -2 < r < 2 \).- Given that \( r > 0 \), the solution range for \( r \) is \( 0 < r < 2 \).
04
State the interval of convergence
The series \( \sum_{n=1}^{\infty} \frac{r^{n}}{2^{n}} \) converges for all \( r \) in the interval \( 0 < r < 2 \), where \( r \) is a positive real number.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a special kind of series with a pattern in its terms. Each term is obtained by multiplying the previous one by a fixed, non-zero number. This number is known as the common ratio. If you look at the series
For example, in our exercise, the geometric series is given by \( \sum_{n=1}^{\infty} \frac{r^n}{2^n} \). Here, the first term \( a \) is \( r/2 \), and its common ratio is also \( r/2 \). Understanding the impact of this common ratio is crucial for determining whether the series converges.
- \( a, ar, ar^2, ar^3, \ldots \)
For example, in our exercise, the geometric series is given by \( \sum_{n=1}^{\infty} \frac{r^n}{2^n} \). Here, the first term \( a \) is \( r/2 \), and its common ratio is also \( r/2 \). Understanding the impact of this common ratio is crucial for determining whether the series converges.
Inequality Solving
Solving inequalities is a key part of understanding when a geometric series converges. An inequality is a mathematical statement that shows the relationship between two expressions that may not be equal.
To determine if a geometric series converges, we often deal with the inequality \( |r| < 1 \). However, in our specific problem, the approach modifies to handle the expression for convergence,
To determine if a geometric series converges, we often deal with the inequality \( |r| < 1 \). However, in our specific problem, the approach modifies to handle the expression for convergence,
- \( \left| \frac{r}{2} \right| < 1 \)
Series Convergence
Series convergence is an essential concept in analysis, referring to the behavior of the sums of an infinite series. When we talk about a series converging, it means that as you add more and more terms, the sum approaches a specific finite value.
The series
Essentially, convergence indicates the series won't grow unbounded but will settle to a particular value as more terms are added. Solving for \( r \) within \( -2 < r < 2 \) and applying the positive condition \( r > 0 \) gives us the interval \( 0 < r < 2 \), ensuring the series converges for these values of \( r \).
The series
- \( \sum_{n=1}^{\infty} \frac{r^n}{2^n} \)
Essentially, convergence indicates the series won't grow unbounded but will settle to a particular value as more terms are added. Solving for \( r \) within \( -2 < r < 2 \) and applying the positive condition \( r > 0 \) gives us the interval \( 0 < r < 2 \), ensuring the series converges for these values of \( r \).
Common Ratio
The common ratio is an integral characteristic of a geometric series. It determines whether the terms increase or decrease as you progress through the series.
- In the mathematical series \( a, ar, ar^2, ar^3, \ldots \), the common ratio \( r \) is the factor you multiply by from one term to the next.
- If \(|r| < 1\), the terms decrease and the series can converge to a finite sum.
- If \(|r| \geq 1\), the terms do not shrink sufficiently, and therefore the series might not converge.