Chapter 5: Problem 210
Use the limit comparison test to determine whether each of the following series converges or diverges. $$\sum_{n=1}^{\infty} \ln \left(1+\frac{1}{n^{2}}\right)$$
Short Answer
Expert verified
The series converges.
Step by step solution
01
Identify the Target Series
We need to analyze the series \( \sum_{n=1}^{\infty} \ln \left(1+\frac{1}{n^{2}}\right) \). To use the limit comparison test, it's helpful to consider a similar series with a known behavior.
02
Choose a Comparison Series
For very large values of \(n\), \( \ln \left(1+\frac{1}{n^{2}}\right) \approx \frac{1}{n^2} \) using basic logarithmic approximations. Therefore, we choose the series \( \sum_{n=1}^{\infty} \frac{1}{n^{2}} \) as our comparison series, which is known to converge (it is a \(p\)-series with \(p = 2\)).
03
Set Up the Limit Comparison Test
We need to calculate \( \lim_{n \to \infty} \frac{\ln \left(1+\frac{1}{n^{2}}\right)}{\frac{1}{n^{2}}} \). If this limit is positive and finite, the limit comparison test will indicate both series have the same convergence behavior.
04
Compute the Limit
Perform the calculation: \[ \lim_{n \to \infty} \frac{\ln \left(1+\frac{1}{n^{2}}\right)}{\frac{1}{n^{2}}} = \lim_{n \to \infty} n^2 \ln \left(1 + \frac{1}{n^2} \right) \] Using the approximation \( \ln(1 + x) \approx x \) for \(x \approx 0\), we get \[ \lim_{n \to \infty} n^2 \left( \frac{1}{n^2} \right) = \lim_{n \to \infty} 1 = 1 \]
05
Conclude with Limit Comparison Test
Since the limit computed in Step 4 is 1, which is positive and finite, the original series \( \sum_{n=1}^{\infty} \ln \left(1+\frac{1}{n^{2}}\right) \) has the same convergence behavior as \( \sum_{n=1}^{\infty} \frac{1}{n^{2}} \). Since \( \sum_{n=1}^{\infty} \frac{1}{n^{2}} \) converges, so does our original series.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Series Convergence
Understanding series convergence is key to analyzing infinite series. When a series converges, the sum of its infinite terms approaches a specific value. If it diverges, the sum doesn't settle on a finite number; it either grows indefinitely or becomes undefined. The Limit Comparison Test is an effective tool to determine whether a series converges or diverges by comparing it to another series with known behavior. A series \( \sum_{n=1}^{\infty} a_n \) can be compared to a series \( \sum_{n=1}^{\infty} b_n \). If \( \lim_{n \to \infty} \frac{a_n}{b_n} = c \) (a positive finite number), both series behave similarly. Thus, knowing the convergence of \( \sum b_n \) helps us understand \( \sum a_n \).
- Convergence: Sum reaches a finite number.
- Divergence: Sum doesn't reach a specific number.
- Important to compare with series of known behavior.
P-Series
The \(p\)-series is a prominent example in convergence tests. It is a series of the form \( \sum_{n=1}^{\infty} \frac{1}{n^p} \). The behavior of \(p\)-series is straightforward:
- If \( p > 1 \), the series converges.
- If \( p \leq 1 \), the series diverges.
Logarithmic Approximation
Logarithmic approximation helps in simplifying complex expressions like \( \ln(1 + x) \). For small values of \(x\), the approximation \( \ln(1 + x) \approx x \) is often used. This simplification serves as part of the Limit Comparison Test calculation by approximating logarithmic terms that would otherwise be complicated to handle. In the exercise, \( \ln (1 + \frac{1}{n^2}) \) was approximated as \(\frac{1}{n^2}\) for very large \(n\). This led to using \(\frac{1}{n^2}\) as the series for comparison, which greatly simplified the convergence analysis.
Convergence Tests
Convergence tests are essential tools in the analysis of infinite series. They provide various methods to determine whether a series converges or diverges. The Limit Comparison Test specifically compares an unknown series with a known one:
- Focuses on behaviors as \(n\) approaches infinity.
- Emphasizes calculating the limit of the ratio of corresponding terms from both series.
- Relies on the known convergence or divergence of the comparison series.