Chapter 3: Problem 267
Use a CAS to evaluate the following integrals. Tables can also be used to verify the answers. $$ [\mathrm{T}] \int x^{3} \sin x d x $$
Short Answer
Expert verified
\( \int x^3 \sin x \, dx = -x^3 \cos x - 3x^2 \sin x - 6x \cos x + 6\sin x + C \).
Step by step solution
01
Identify the Integration Method
The integral \( \int x^{3} \sin x \, dx \) involves a product of a polynomial and a trigonometric function. We will use integration by parts, a method suitable for such integrals. We choose \( u = x^3 \) and \( dv = \sin x \, dx \).
02
Differentiate and Integrate
Differentiate \( u = x^3 \) to get \( du = 3x^2 \, dx \). Integrate \( dv = \sin x \, dx \) to get \( v = -\cos x \).
03
Apply Integration by Parts
Using the integration by parts formula, \( \int u \, dv = uv - \int v \, du \), substitute \( u, du, v, \) and \( dv \) into the formula: \[ \int x^3 \sin x \, dx = -x^3 \cos x + \int 3x^2 (-\cos x) \, dx. \]
04
Repeat Integration by Parts
For the integral \( \int 3x^2 (-\cos x) \, dx \), apply integration by parts again: Let \( u = x^2 \), \( dv = -3\cos x \, dx \). Then, \( du = 2x \, dx \) and \( v = -3\sin x \). Substitute these into the integration by parts formula again.
05
Simplify the Second Integration by Parts
The new expression becomes: \[ \int 3x^2 (-\cos x) \, dx = -3x^2 \sin x + \int 6x \sin x \, dx. \]Now, apply integration by parts a third time to \( \int 6x \sin x \, dx \).
06
Final Integration by Parts
For \( \int 6x \sin x \, dx \), let \( u = x \) and \( dv = 6\sin x \, dx \), giving \( du = dx \) and \( v = -6 \cos x \). The result is:\[ -6x \cos x + \int 6 \cos x \, dx = -6x \cos x + 6 \sin x. \]
07
Combine All Parts and Simplify
Substituting back, combine all expressions: \[ \int x^3 \sin x \, dx = -x^3 \cos x + (-3x^2 \sin x) + (-6x \cos x) + 6\sin x + C, \]where \( C \) is the integration constant.
08
Verification Using CAS or Tables
Finally, verify the solution using a Computer Algebra System (CAS) or a standard integral table to ensure all steps are performed correctly.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals help us compute the area under a curve between two bounds. Unlike indefinite integrals, which provide a general form of antiderivatives, definite integrals give a numerical value. They are written with limits of integration, typically at the top and bottom of the integral symbol, like \[ \int_{a}^{b} f(x) \, dx \].
Here's how they work:
Here's how they work:
- The limits of integration \( a \) and \( b \) define the interval over which the area is calculated.
- The integral evaluates the area between the curve of the function \( f(x) \) and the x-axis.
- If the curve is below the x-axis, the area is negative, impacting the final result.
Trigonometric Functions
Trigonometric functions, like sine, cosine, and tangent, play vital roles in calculus and integration. Functions such as \( \sin x \) and \( \cos x \) frequently appear in integrals, making them essential to understand.
Key points about trigonometric functions:
Key points about trigonometric functions:
- The basic trigonometric functions are periodic and repeat at regular intervals, which is particularly useful in integration processes.
- Trigonometric identities can simplify complex integrals, allowing for easier calculation.
- When using integration by parts, integrating trig functions often involves cyclical processes, requiring persistent application of integration rules.
Polynomial Integration
Polynomial integration, a fundamental skill in calculus, involves integrating expressions like \( x^n \). This kind of integration is straightforward but serves as the foundation for more complex strategies like integration by parts.
Essential elements of polynomial integration include:
Essential elements of polynomial integration include:
- The power rule for integration: If \( n eq -1 \), then \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration.
- Even complex integrals can often be broken down into simpler polynomial components, making them easier to compute.
- Integration by parts often begins with determining the polynomial part since it provides straightforward derivatives and integrals.
CAS (Computer Algebra System) Verification
Using a Computer Algebra System (CAS) aids in solving complex integrals by providing a digital check of manual computations. It serves as an invaluable tool for learners and professionals alike by confirming results.
Benefits of CAS verification:
Benefits of CAS verification:
- Ensures accuracy of solutions derived manually, offering peace of mind that calculations are correct.
- Allows experimentation with various integration techniques, providing insights and alternative approaches to solving integrals.
- Quickly handles cumbersome algebraic manipulations, freeing time for focusing on understanding concepts.