Chapter 3: Problem 211
Use the method of partial fractions to evaluate the following integrals. $$ \int \frac{3 x+4}{\left(x^{2}+4\right)(3-x)} d x $$
Short Answer
Expert verified
The integral evaluates to \( \frac{7}{4} \ln|x^2 + 4| + 2 \arctan\left(\frac{x}{2}\right) + C \).
Step by step solution
01
Recognize the Partial Fraction Form
The integrand \( \frac{3x + 4}{(x^2 + 4)(3-x)} \) involves two distinct polynomial factors in the denominator. We can express it as: \[\frac{A x + B}{x^2 + 4} + \frac{C}{3 - x}.\] This setup will allow us to find \( A \), \( B \), and \( C \) so that partial fraction decomposition is possible.
02
Set Up the Equation
Multiply both sides by \((x^2 + 4)(3-x)\) to clear the denominators:\[3x + 4 = (Ax + B)(3-x) + C(x^2 + 4).\] Expanding both terms gives us the equation to solve for \(A\), \(B\), and \(C\).
03
Expand and Collect Like Terms
Expand the equation:\[3x + 4 = (Ax - A)(3) + (B)(3-x) + Cx^2 + 4C.\]This gives us: \[3x + 4 = (3Ax - Ax - B) + (3B + Cx^2 + 4C).\] Reorganize it to:\[3x + 4 = Cx^2 + (3A - A - B)x + (4C + B).\]
04
Equate Coefficients
By equating the coefficients from both sides, we get the following equations:- For \(x^2\), \( C = 0 \).- For \(x\), \( 3A - B - A = 3 \).- For the constant term, \( 4C + B = 4 \).Solving these gives us \( C = 0 \), \( 2A - B = 3 \), and \( B = 4 \).
05
Solve the System of Equations
Substitute \( B = 4 \) into \( 2A - B = 3 \):\[2A - 4 = 3 \2A = 7 \A = \frac{7}{2}\] Now that we have \( A = \frac{7}{2} \), \( B = 4 \), and \( C = 0 \).
06
Write the Partial Fraction Decomposition
The partial fraction decomposition is:\[\frac{3x+4}{(x^2+4)(3-x)} = \frac{\frac{7}{2} x + 4}{x^2 + 4}.\] Since \( C = 0 \), the \( \frac{C}{3-x} \) term is not present.
07
Integrate Each Term
Separate the integrands and integrate each term:\[\int \left(\frac{\frac{7}{2} x}{x^2+4} + \frac{4}{x^2+4}\right) dx.\]For \( \int \frac{\frac{7}{2} x}{x^2+4} dx \): make the substitution \( u = x^2 + 4 \), \( du = 2x dx \).For \( \int \frac{4}{x^2+4} dx \): use the integral formula \( \int \frac{1}{x^2+a^2} dx = \frac{1}{a} \arctan\left(\frac{x}{a}\right) + C \).
08
Solve the Integrals
Calculate the integrals separately:\[\int \frac{\frac{7}{2} x}{x^2+4} dx = \frac{7}{4} \ln|x^2 + 4| + C_1.\]\[\int \frac{4}{x^2+4} dx = \arctan\left(\frac{x}{2}\right) + C_2.\]Combine the results to provide the final integral solution.
09
Combine the Results
The solution to the integral is:\[\int \frac{3x + 4}{(x^2 + 4)(3-x)} dx = \frac{7}{4} \ln|x^2 + 4| + 2 \arctan\left(\frac{x}{2}\right) + C,\]where \( C = C_1 + C_2 \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Factorization
Polynomial factorization is an essential concept that involves breaking down a polynomial expression into a product of simpler polynomials, often to make calculations or integrations easier. In our exercise, the integrand has a polynomial in the denominator: \( (x^2 + 4)(3-x) \). Factorizing or recognizing these polynomials' form allows us to use techniques like partial fraction decomposition effectively.
To factorize polynomials, you should:
To factorize polynomials, you should:
- Identify common factors (i.e., terms that can be taken out of each component).
- Factor any quadratic or higher-degree polynomials using techniques such as grouping, using the quadratic formula, or recognizing special product forms (e.g., difference of squares).
- Express the polynomial as a product of simpler factors, each of which ideally cannot be factored further.
Partial Fraction Decomposition
Partial fraction decomposition is a powerful method used primarily to simplify mathematical expressions, particularly when dealing with rational functions. This approach decomposes a complex fraction into a sum of simpler fractions, which are often more straightforward to integrate or differentiate.
In this exercise, we started with the expression \( \frac{3x + 4}{(x^2 + 4)(3-x)} \). By recognizing the distinct polynomial factors in the denominator, it is possible to express it as a sum of simpler fractions:
Once decomposed, each term can be tackled individually, making complex integrations much more manageable, as simplifying complex expressions into linear or lesser-degree terms often allows straightforward application of basic integration techniques.
In this exercise, we started with the expression \( \frac{3x + 4}{(x^2 + 4)(3-x)} \). By recognizing the distinct polynomial factors in the denominator, it is possible to express it as a sum of simpler fractions:
- \( \frac{Ax + B}{x^2 + 4} \)
- \( \frac{C}{3-x} \)
Once decomposed, each term can be tackled individually, making complex integrations much more manageable, as simplifying complex expressions into linear or lesser-degree terms often allows straightforward application of basic integration techniques.
Integral Calculus
Integral calculus involves finding the integral of a function, which is essentially the reverse process of differentiation. Integrals can help determine areas under curves, among other applications, and they come in two main types: indefinite and definite integrals.
In the given exercise, we dealt with an indefinite integral \( \int \frac{3x+4}{(x^2+4)(3-x)} \, dx \). After performing partial fraction decomposition, the task was to integrate each simplified term separately:
We have:
In the given exercise, we dealt with an indefinite integral \( \int \frac{3x+4}{(x^2+4)(3-x)} \, dx \). After performing partial fraction decomposition, the task was to integrate each simplified term separately:
We have:
- \( \int \frac{\frac{7}{2} x}{x^2+4} \, dx \)
- \( \int \frac{4}{x^2+4} \, dx \)
- Using substitutions like \( u = x^2 + 4 \) which helps integrate polynomials in fractions with different bases.
- Employ known integral formulas such as \( \int \frac{1}{x^2+a^2} \, dx = \frac{1}{a} \arctan\left(\frac{x}{a}\right) + C \).