Chapter 2: Problem 21
For the following exercises, graph the equations and shade the area of the region between the curves. Determine its area by integrating over the \(y\) -axis. $$ x=2 y \text { and } x=y^{3}-y $$
Short Answer
Expert verified
The area between the curves is 4.5.
Step by step solution
01
Identify the Curves
The equations given are \(x = 2y\) and \(x = y^3 - y\). These represent a line and a cubic, respectively.
02
Find Intersection Points
To find the intersection points, set the equations equal: \(2y = y^3 - y\). Simplify to \(y^3 - 3y = 0\). Factor to get \(y(y^2 - 3) = 0\). The solutions are \(y = 0, y = \sqrt{3}, y = -\sqrt{3}\).
03
Determine x-Values at Intersection Points
Substitute the \(y\)-values back into either equation to find \(x\). For \(y = 0\), \(x = 0\). For \(y = \sqrt{3}\), \(x = 2 \sqrt{3}\). For \(y = -\sqrt{3}\), \(x = -2 \sqrt{3}\).
04
Set Up the Integral
The area between the curves is given by \( \int (2y - (y^3 - y))\, dy \). This simplifies to \( \int (2y - y^3 + y)\, dy \) or \( \int (-y^3 + 3y)\, dy \).
05
Integrate
Integrate \( -y^3 + 3y \) with respect to \(y\). This results in \( \left[ -\frac{1}{4}y^4 + \frac{3}{2}y^2 \right] \).
06
Evaluate the Integral
Evaluate \( \left[ -\frac{1}{4}y^4 + \frac{3}{2}y^2 \right] \) from \(y = -\sqrt{3}\) to \(y = \sqrt{3}\). The integral becomes \[ \left( -\frac{1}{4}(\sqrt{3})^4 + \frac{3}{2}(\sqrt{3})^2 \right) - \left( -\frac{1}{4}(-\sqrt{3})^4 + \frac{3}{2}(-\sqrt{3})^2 \right)\].
07
Simplify the Calculation
Calculate separately: \(-\frac{1}{4}(\sqrt{3})^4 = -\frac{9}{4}\) and \(\frac{3}{2}(\sqrt{3})^2 = \frac{9}{2}\). Substitute back to evaluate as \(2 \times \left[-\frac{9}{4} + \frac{9}{2}\right] = 2 \times \frac{9}{4} = \frac{18}{4} = \frac{9}{2}\).
08
Determine the Area
The area between the curves is \(\frac{9}{2}\). Therefore, the area of the region is \(4.5\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integration
Integration is a fundamental concept in calculus that involves adding up small quantities to find a total value, such as an area, a volume, or other measures. The process of integration allows us to accumulate quantities over a segment of the plane or a function's domain.
At its core, integration is the reverse operation of differentiation. While differentiation measures the rate at which a function changes, integration sums up all these infinitesimal changes to give a total function or quantity.
There are different techniques of integration including:
At its core, integration is the reverse operation of differentiation. While differentiation measures the rate at which a function changes, integration sums up all these infinitesimal changes to give a total function or quantity.
There are different techniques of integration including:
- Indefinite Integration: Finding a function whose derivative is the given function. The result includes a constant, as multiple functions can differ by constants and have the same derivative.
- Definite Integration: Calculating the exact area under the curve between two points, providing a numerical value as a result.
Definite Integrals
Definite integrals provide a way to compute the area under a curve between specific boundaries, usually denoted by two points. The Notation \( \int_a^b f(x) \, dx \) represents integrating the function \( f(x) \) from \( x = a \) to \( x = b \). The result is a number that represents the net area, taking into account areas above and below the \(x\)-axis.
Definite integrals are evaluated using limits of the antiderivative of the function, known as the Fundamental Theorem of Calculus:
Definite integrals are evaluated using limits of the antiderivative of the function, known as the Fundamental Theorem of Calculus:
- Step 1: Find the antiderivative of the function, \( F(x) \).
- Step 2: Calculate \( F(b) - F(a) \), which gives the total accumulated value from \( a \) to \( b \).
Area Between Curves
The concept of finding the area between curves involves using integration to calculate the region enclosed by two or more curves. This method typically involves these steps:
- Identify the Curves: The problem begins by finding the functions that define the boundary curves.
- Find Points of Intersection: Solving for where the curves intersect determines the integral limits.
- Set Up the Integral: The formula \( \int [f(y) - g(y)] \, dy \) or \( \int [f(x) - g(x)] \, dx \) finds the area by subtracting the lower curve from the upper curve.
- Integrate: Perform the definite integration over the determined interval.